NEET Test Series from KOTA - 10 Papers In MS WORD
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Current Electricity
268432
The temperature coefficient of resistance of platinum is \(\alpha=3.92 \times 10^{-3} \mathrm{~K}^{-1}\) at \(20^{\circ} \mathrm{C}\). F ind the temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(20^{\circ} \mathrm{C}\)
1 \(40.5^{\circ} \mathrm{C}\)
2 \(45.5^{\circ} \mathrm{C}\)
3 \(48.5^{\circ} \mathrm{C}\)
4 \(43.5^{\circ} \mathrm{C}\)
Explanation:
\(\Delta t=\frac{R_{2}-R_{1}}{R_{1} \alpha}\)
Current Electricity
268433
Four identical resistancearej oined as shown in fig. The equivalent resistance between points \(A\) and \(B\) is \(R_{1}\) and that between \(A\) and \(\mathrm{C}\) is \(R_{2^{2}}\). Then ratio of \(\frac{R_{1}}{R_{2}}\) is
1 \(1: 5\)
2 \(3: 4\)
3 \(2: 5\)
4 \(1: 2\)
Explanation:
Combination of resistors
Current Electricity
268434
If the galvanometer reading is zero in the given circuit, the current passing through resistance \(250_{\Omega}\) is
1 \(0.016 \mathrm{~A}\)
2 \(0.16 \mathrm{~A}^{12}\)
3 \(0.032 \mathrm{~A}\)
4 \(0.042 \mathrm{~A}\)
Explanation:
\(i=\frac{V}{R_{\text {total }}}\)
Current Electricity
268435
The effective resistance between \(A\) and \(B\) is the given circuit is
268432
The temperature coefficient of resistance of platinum is \(\alpha=3.92 \times 10^{-3} \mathrm{~K}^{-1}\) at \(20^{\circ} \mathrm{C}\). F ind the temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(20^{\circ} \mathrm{C}\)
1 \(40.5^{\circ} \mathrm{C}\)
2 \(45.5^{\circ} \mathrm{C}\)
3 \(48.5^{\circ} \mathrm{C}\)
4 \(43.5^{\circ} \mathrm{C}\)
Explanation:
\(\Delta t=\frac{R_{2}-R_{1}}{R_{1} \alpha}\)
Current Electricity
268433
Four identical resistancearej oined as shown in fig. The equivalent resistance between points \(A\) and \(B\) is \(R_{1}\) and that between \(A\) and \(\mathrm{C}\) is \(R_{2^{2}}\). Then ratio of \(\frac{R_{1}}{R_{2}}\) is
1 \(1: 5\)
2 \(3: 4\)
3 \(2: 5\)
4 \(1: 2\)
Explanation:
Combination of resistors
Current Electricity
268434
If the galvanometer reading is zero in the given circuit, the current passing through resistance \(250_{\Omega}\) is
1 \(0.016 \mathrm{~A}\)
2 \(0.16 \mathrm{~A}^{12}\)
3 \(0.032 \mathrm{~A}\)
4 \(0.042 \mathrm{~A}\)
Explanation:
\(i=\frac{V}{R_{\text {total }}}\)
Current Electricity
268435
The effective resistance between \(A\) and \(B\) is the given circuit is
268432
The temperature coefficient of resistance of platinum is \(\alpha=3.92 \times 10^{-3} \mathrm{~K}^{-1}\) at \(20^{\circ} \mathrm{C}\). F ind the temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(20^{\circ} \mathrm{C}\)
1 \(40.5^{\circ} \mathrm{C}\)
2 \(45.5^{\circ} \mathrm{C}\)
3 \(48.5^{\circ} \mathrm{C}\)
4 \(43.5^{\circ} \mathrm{C}\)
Explanation:
\(\Delta t=\frac{R_{2}-R_{1}}{R_{1} \alpha}\)
Current Electricity
268433
Four identical resistancearej oined as shown in fig. The equivalent resistance between points \(A\) and \(B\) is \(R_{1}\) and that between \(A\) and \(\mathrm{C}\) is \(R_{2^{2}}\). Then ratio of \(\frac{R_{1}}{R_{2}}\) is
1 \(1: 5\)
2 \(3: 4\)
3 \(2: 5\)
4 \(1: 2\)
Explanation:
Combination of resistors
Current Electricity
268434
If the galvanometer reading is zero in the given circuit, the current passing through resistance \(250_{\Omega}\) is
1 \(0.016 \mathrm{~A}\)
2 \(0.16 \mathrm{~A}^{12}\)
3 \(0.032 \mathrm{~A}\)
4 \(0.042 \mathrm{~A}\)
Explanation:
\(i=\frac{V}{R_{\text {total }}}\)
Current Electricity
268435
The effective resistance between \(A\) and \(B\) is the given circuit is
268432
The temperature coefficient of resistance of platinum is \(\alpha=3.92 \times 10^{-3} \mathrm{~K}^{-1}\) at \(20^{\circ} \mathrm{C}\). F ind the temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(20^{\circ} \mathrm{C}\)
1 \(40.5^{\circ} \mathrm{C}\)
2 \(45.5^{\circ} \mathrm{C}\)
3 \(48.5^{\circ} \mathrm{C}\)
4 \(43.5^{\circ} \mathrm{C}\)
Explanation:
\(\Delta t=\frac{R_{2}-R_{1}}{R_{1} \alpha}\)
Current Electricity
268433
Four identical resistancearej oined as shown in fig. The equivalent resistance between points \(A\) and \(B\) is \(R_{1}\) and that between \(A\) and \(\mathrm{C}\) is \(R_{2^{2}}\). Then ratio of \(\frac{R_{1}}{R_{2}}\) is
1 \(1: 5\)
2 \(3: 4\)
3 \(2: 5\)
4 \(1: 2\)
Explanation:
Combination of resistors
Current Electricity
268434
If the galvanometer reading is zero in the given circuit, the current passing through resistance \(250_{\Omega}\) is
1 \(0.016 \mathrm{~A}\)
2 \(0.16 \mathrm{~A}^{12}\)
3 \(0.032 \mathrm{~A}\)
4 \(0.042 \mathrm{~A}\)
Explanation:
\(i=\frac{V}{R_{\text {total }}}\)
Current Electricity
268435
The effective resistance between \(A\) and \(B\) is the given circuit is