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Current Electricity

268310 A 25 watt, 220 volt bulb and a 100 watt, 220 volt bulb are connected in series across 440 volt line

1 only 100 walt bulb will fuse

2 only 25 watt bulb will fuse

3 none of the bulb will fuse

4 both bulbs will fuse

Explanation:

$R = \frac{V^{2}}{P}; V = i R$

Current Electricity

268311 There are 5 tube-lights each of $40 W$ in a house. These are used on an average for 5 hours per day. In addition, there is an immersion heater of $1500 W$ used on an average for 1 hour per day. The number of units of electricity are consumed ina month is

1 25 units

2

50

units

3 75 units

4 100 units

Explanation:

$P = \frac{E}{t}, 1 K . W . H = 1$ unit

Current Electricity

268312 Three equal resistors connected in series across a source emf together dissipate 10 watt. If the same resistors are connected in parallel across the same emf the power dissipate will be

1 10 walt

2 30 watt

3

10 / 3

watt

4 90 watt

Explanation:

$P = \frac{V^{2}}{R} \Rightarrow \frac{P_{S}}{P_{P}} = \frac{R_{P}}{R_{S}}$

Current Electricity

268313 Time taken by a $836 W$ heater to heat one litre of water from $10^{\circ} C$ to $40^{\circ} C$ is

1

50 s

2

100 s

3

150 s

4

200 s

Explanation:

$W = J Q \Rightarrow P \times t = J m Δ Δ T$

Current Electricity

268314 A lamp of $600 W - 240 V$ is connected to $220 V$ mains. Its resistance is

1

96 Ω

2

84 Ω

3

90 Ω

4

64 Ω

Explanation:

$R = \frac{{(V^{'})}^{2}}{P^{'}}$

Current Electricity

268310 A 25 watt, 220 volt bulb and a 100 watt, 220 volt bulb are connected in series across 440 volt line

1 only 100 walt bulb will fuse

2 only 25 watt bulb will fuse

3 none of the bulb will fuse

4 both bulbs will fuse

Explanation:

$R = \frac{V^{2}}{P}; V = i R$

Current Electricity

268311 There are 5 tube-lights each of $40 W$ in a house. These are used on an average for 5 hours per day. In addition, there is an immersion heater of $1500 W$ used on an average for 1 hour per day. The number of units of electricity are consumed ina month is

1 25 units

2

50

units

3 75 units

4 100 units

Explanation:

$P = \frac{E}{t}, 1 K . W . H = 1$ unit

Current Electricity

268312 Three equal resistors connected in series across a source emf together dissipate 10 watt. If the same resistors are connected in parallel across the same emf the power dissipate will be

1 10 walt

2 30 watt

3

10 / 3

watt

4 90 watt

Explanation:

$P = \frac{V^{2}}{R} \Rightarrow \frac{P_{S}}{P_{P}} = \frac{R_{P}}{R_{S}}$

Current Electricity

268313 Time taken by a $836 W$ heater to heat one litre of water from $10^{\circ} C$ to $40^{\circ} C$ is

1

50 s

2

100 s

3

150 s

4

200 s

Explanation:

$W = J Q \Rightarrow P \times t = J m Δ Δ T$

Current Electricity

268314 A lamp of $600 W - 240 V$ is connected to $220 V$ mains. Its resistance is

1

96 Ω

2

84 Ω

3

90 Ω

4

64 Ω

Explanation:

$R = \frac{{(V^{'})}^{2}}{P^{'}}$

Current Electricity

268310 A 25 watt, 220 volt bulb and a 100 watt, 220 volt bulb are connected in series across 440 volt line

1 only 100 walt bulb will fuse

2 only 25 watt bulb will fuse

3 none of the bulb will fuse

4 both bulbs will fuse

Explanation:

$R = \frac{V^{2}}{P}; V = i R$

Current Electricity

268311 There are 5 tube-lights each of $40 W$ in a house. These are used on an average for 5 hours per day. In addition, there is an immersion heater of $1500 W$ used on an average for 1 hour per day. The number of units of electricity are consumed ina month is

1 25 units

2

50

units

3 75 units

4 100 units

Explanation:

$P = \frac{E}{t}, 1 K . W . H = 1$ unit

Current Electricity

268312 Three equal resistors connected in series across a source emf together dissipate 10 watt. If the same resistors are connected in parallel across the same emf the power dissipate will be

1 10 walt

2 30 watt

3

10 / 3

watt

4 90 watt

Explanation:

$P = \frac{V^{2}}{R} \Rightarrow \frac{P_{S}}{P_{P}} = \frac{R_{P}}{R_{S}}$

Current Electricity

268313 Time taken by a $836 W$ heater to heat one litre of water from $10^{\circ} C$ to $40^{\circ} C$ is

1

50 s

2

100 s

3

150 s

4

200 s

Explanation:

$W = J Q \Rightarrow P \times t = J m Δ Δ T$

Current Electricity

268314 A lamp of $600 W - 240 V$ is connected to $220 V$ mains. Its resistance is

1

96 Ω

2

84 Ω

3

90 Ω

4

64 Ω

Explanation:

$R = \frac{{(V^{'})}^{2}}{P^{'}}$

Current Electricity

268310 A 25 watt, 220 volt bulb and a 100 watt, 220 volt bulb are connected in series across 440 volt line

1 only 100 walt bulb will fuse

2 only 25 watt bulb will fuse

3 none of the bulb will fuse

4 both bulbs will fuse

Explanation:

$R = \frac{V^{2}}{P}; V = i R$

Current Electricity

268311 There are 5 tube-lights each of $40 W$ in a house. These are used on an average for 5 hours per day. In addition, there is an immersion heater of $1500 W$ used on an average for 1 hour per day. The number of units of electricity are consumed ina month is

1 25 units

2

50

units

3 75 units

4 100 units

Explanation:

$P = \frac{E}{t}, 1 K . W . H = 1$ unit

Current Electricity

268312 Three equal resistors connected in series across a source emf together dissipate 10 watt. If the same resistors are connected in parallel across the same emf the power dissipate will be

1 10 walt

2 30 watt

3

10 / 3

watt

4 90 watt

Explanation:

$P = \frac{V^{2}}{R} \Rightarrow \frac{P_{S}}{P_{P}} = \frac{R_{P}}{R_{S}}$

Current Electricity

268313 Time taken by a $836 W$ heater to heat one litre of water from $10^{\circ} C$ to $40^{\circ} C$ is

1

50 s

2

100 s

3

150 s

4

200 s

Explanation:

$W = J Q \Rightarrow P \times t = J m Δ Δ T$

Current Electricity

268314 A lamp of $600 W - 240 V$ is connected to $220 V$ mains. Its resistance is

1

96 Ω

2

84 Ω

3

90 Ω

4

64 Ω

Explanation:

$R = \frac{{(V^{'})}^{2}}{P^{'}}$

Current Electricity

268310 A 25 watt, 220 volt bulb and a 100 watt, 220 volt bulb are connected in series across 440 volt line

1 only 100 walt bulb will fuse

2 only 25 watt bulb will fuse

3 none of the bulb will fuse

4 both bulbs will fuse

Explanation:

$R = \frac{V^{2}}{P}; V = i R$

Current Electricity

268311 There are 5 tube-lights each of $40 W$ in a house. These are used on an average for 5 hours per day. In addition, there is an immersion heater of $1500 W$ used on an average for 1 hour per day. The number of units of electricity are consumed ina month is

1 25 units

2

50

units

3 75 units

4 100 units

Explanation:

$P = \frac{E}{t}, 1 K . W . H = 1$ unit

Current Electricity

268312 Three equal resistors connected in series across a source emf together dissipate 10 watt. If the same resistors are connected in parallel across the same emf the power dissipate will be

1 10 walt

2 30 watt

3

10 / 3

watt

4 90 watt

Explanation:

$P = \frac{V^{2}}{R} \Rightarrow \frac{P_{S}}{P_{P}} = \frac{R_{P}}{R_{S}}$

Current Electricity

268313 Time taken by a $836 W$ heater to heat one litre of water from $10^{\circ} C$ to $40^{\circ} C$ is

1

50 s

2

100 s

3

150 s

4

200 s

Explanation:

$W = J Q \Rightarrow P \times t = J m Δ Δ T$

Current Electricity

268314 A lamp of $600 W - 240 V$ is connected to $220 V$ mains. Its resistance is

1

96 Ω

2

84 Ω

3

90 Ω

4

64 Ω

Explanation:

$R = \frac{{(V^{'})}^{2}}{P^{'}}$