ELECTRIC CURRENT AND DRIFT VELOCITY
Current Electricity

268515 In a straight conductor of uniformcrosssection charge \(q\) is flowing for time \(t\). Let \(s\) be the specific charge of an electron. The momentum of all the free electrons per unit length of the conductor, due to their drift velocity only is

1 \(\frac{q}{t s}\)
2 \(\left(\frac{q}{t s}\right)^{2}\)
3 \(\sqrt{\frac{q}{t s}}\)
4 qts
Current Electricity

268516 Potential difference of\(\mathbf{1 0 0} \mathrm{V}\) is applied to the ends of a copper wire one metre long. Find the ratio of average drift velocity and thermal velocity of electrons at \(27^{\circ} \mathrm{C}\). (Consider there is one conduction electron per atom. The density of copper is \(9.0 \times 10^{3}\); A tomic mass of copper is \(63.5 \mathrm{~g}\).
\(N_{A}=6.0 \times 10^{23}\) per gram-mole, conductivity of copper is \(5.81 \times 10^{7} \Omega^{-1}\).
\(\mathbf{K}=1.38 \times 10^{-23} J K^{-1}\) )

1 \(3.67 \times 10^{-6}\)
2 \(4.3 \times 10^{-6}\)
3 \(6 \times 10^{-5}\)
4 \(5.6 \times 10^{-6}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Current Electricity

268515 In a straight conductor of uniformcrosssection charge \(q\) is flowing for time \(t\). Let \(s\) be the specific charge of an electron. The momentum of all the free electrons per unit length of the conductor, due to their drift velocity only is

1 \(\frac{q}{t s}\)
2 \(\left(\frac{q}{t s}\right)^{2}\)
3 \(\sqrt{\frac{q}{t s}}\)
4 qts
Current Electricity

268516 Potential difference of\(\mathbf{1 0 0} \mathrm{V}\) is applied to the ends of a copper wire one metre long. Find the ratio of average drift velocity and thermal velocity of electrons at \(27^{\circ} \mathrm{C}\). (Consider there is one conduction electron per atom. The density of copper is \(9.0 \times 10^{3}\); A tomic mass of copper is \(63.5 \mathrm{~g}\).
\(N_{A}=6.0 \times 10^{23}\) per gram-mole, conductivity of copper is \(5.81 \times 10^{7} \Omega^{-1}\).
\(\mathbf{K}=1.38 \times 10^{-23} J K^{-1}\) )

1 \(3.67 \times 10^{-6}\)
2 \(4.3 \times 10^{-6}\)
3 \(6 \times 10^{-5}\)
4 \(5.6 \times 10^{-6}\)