CAPACITANCE
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Electrostatic Potentials and Capacitance

268133 The time in seconds required toproducea P.D at \(20 \mathrm{~V}\) across a capacitor at \(1000 \mu \mathrm{F}\) when it is charged at thesteady rate of \(200 \mu \mathrm{C} / \mathrm{sec}\) is

1 50
2 100
3 150
4 200
Electrostatic Potentials and Capacitance

268134 A parallelplatecapacitor of capacity \(5 \mu \mathrm{F}\) and plate separation \(6 \mathrm{~cm}\) is connected to a IV battery and is charged. A dielectric of dielectric constant 4 and thickness \(4 \mathrm{~cm}\) is introduced into the capacitor. The additional charge that flows into the capacitor from the battery is

1 \(2 \mu \mathrm{C}\)
2 \(3 \mu \mathrm{C}\)
3 \(5 \mu C\)
4 \(10 \mu \mathrm{C}\)
Electrostatic Potentials and Capacitance

268135 The force between the plates of a parallel plate capacitor ofcapacitanceC and distance of separation of the plates \(d\) with a potential difference \(V\) between the plates, is

1 \(\frac{C V^{2}}{2 d}\)
2 \(\frac{C^{2} V^{2}}{2 d^{2}}\)
3 \(\frac{C^{2} V^{2}}{d^{2}}\)
4 \(\frac{V^{2} d}{C}\)
Electrostatic Potentials and Capacitance

268137 Two identical capacitors 1 and 2areconnected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant \(K\) as shown. \(Q_{1}\) and \(Q_{2}\) arethe charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are \(Q_{1}^{\prime}\) and \(Q_{2}^{\prime}\).
Then

1 \(\frac{Q_{1}^{\prime}}{Q_{1}}=\frac{K+1}{K}\)
2 \(\frac{Q_{2}^{\prime} 2}{Q_{2}}=\frac{K+1}{2}\)
3 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K+1}{2 K}\)
4 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K}{2}\)
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Electrostatic Potentials and Capacitance

268133 The time in seconds required toproducea P.D at \(20 \mathrm{~V}\) across a capacitor at \(1000 \mu \mathrm{F}\) when it is charged at thesteady rate of \(200 \mu \mathrm{C} / \mathrm{sec}\) is

1 50
2 100
3 150
4 200
Electrostatic Potentials and Capacitance

268134 A parallelplatecapacitor of capacity \(5 \mu \mathrm{F}\) and plate separation \(6 \mathrm{~cm}\) is connected to a IV battery and is charged. A dielectric of dielectric constant 4 and thickness \(4 \mathrm{~cm}\) is introduced into the capacitor. The additional charge that flows into the capacitor from the battery is

1 \(2 \mu \mathrm{C}\)
2 \(3 \mu \mathrm{C}\)
3 \(5 \mu C\)
4 \(10 \mu \mathrm{C}\)
Electrostatic Potentials and Capacitance

268135 The force between the plates of a parallel plate capacitor ofcapacitanceC and distance of separation of the plates \(d\) with a potential difference \(V\) between the plates, is

1 \(\frac{C V^{2}}{2 d}\)
2 \(\frac{C^{2} V^{2}}{2 d^{2}}\)
3 \(\frac{C^{2} V^{2}}{d^{2}}\)
4 \(\frac{V^{2} d}{C}\)
Electrostatic Potentials and Capacitance

268137 Two identical capacitors 1 and 2areconnected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant \(K\) as shown. \(Q_{1}\) and \(Q_{2}\) arethe charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are \(Q_{1}^{\prime}\) and \(Q_{2}^{\prime}\).
Then

1 \(\frac{Q_{1}^{\prime}}{Q_{1}}=\frac{K+1}{K}\)
2 \(\frac{Q_{2}^{\prime} 2}{Q_{2}}=\frac{K+1}{2}\)
3 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K+1}{2 K}\)
4 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K}{2}\)
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Electrostatic Potentials and Capacitance

268133 The time in seconds required toproducea P.D at \(20 \mathrm{~V}\) across a capacitor at \(1000 \mu \mathrm{F}\) when it is charged at thesteady rate of \(200 \mu \mathrm{C} / \mathrm{sec}\) is

1 50
2 100
3 150
4 200
Electrostatic Potentials and Capacitance

268134 A parallelplatecapacitor of capacity \(5 \mu \mathrm{F}\) and plate separation \(6 \mathrm{~cm}\) is connected to a IV battery and is charged. A dielectric of dielectric constant 4 and thickness \(4 \mathrm{~cm}\) is introduced into the capacitor. The additional charge that flows into the capacitor from the battery is

1 \(2 \mu \mathrm{C}\)
2 \(3 \mu \mathrm{C}\)
3 \(5 \mu C\)
4 \(10 \mu \mathrm{C}\)
Electrostatic Potentials and Capacitance

268135 The force between the plates of a parallel plate capacitor ofcapacitanceC and distance of separation of the plates \(d\) with a potential difference \(V\) between the plates, is

1 \(\frac{C V^{2}}{2 d}\)
2 \(\frac{C^{2} V^{2}}{2 d^{2}}\)
3 \(\frac{C^{2} V^{2}}{d^{2}}\)
4 \(\frac{V^{2} d}{C}\)
Electrostatic Potentials and Capacitance

268137 Two identical capacitors 1 and 2areconnected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant \(K\) as shown. \(Q_{1}\) and \(Q_{2}\) arethe charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are \(Q_{1}^{\prime}\) and \(Q_{2}^{\prime}\).
Then

1 \(\frac{Q_{1}^{\prime}}{Q_{1}}=\frac{K+1}{K}\)
2 \(\frac{Q_{2}^{\prime} 2}{Q_{2}}=\frac{K+1}{2}\)
3 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K+1}{2 K}\)
4 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K}{2}\)
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Electrostatic Potentials and Capacitance

268133 The time in seconds required toproducea P.D at \(20 \mathrm{~V}\) across a capacitor at \(1000 \mu \mathrm{F}\) when it is charged at thesteady rate of \(200 \mu \mathrm{C} / \mathrm{sec}\) is

1 50
2 100
3 150
4 200
Electrostatic Potentials and Capacitance

268134 A parallelplatecapacitor of capacity \(5 \mu \mathrm{F}\) and plate separation \(6 \mathrm{~cm}\) is connected to a IV battery and is charged. A dielectric of dielectric constant 4 and thickness \(4 \mathrm{~cm}\) is introduced into the capacitor. The additional charge that flows into the capacitor from the battery is

1 \(2 \mu \mathrm{C}\)
2 \(3 \mu \mathrm{C}\)
3 \(5 \mu C\)
4 \(10 \mu \mathrm{C}\)
Electrostatic Potentials and Capacitance

268135 The force between the plates of a parallel plate capacitor ofcapacitanceC and distance of separation of the plates \(d\) with a potential difference \(V\) between the plates, is

1 \(\frac{C V^{2}}{2 d}\)
2 \(\frac{C^{2} V^{2}}{2 d^{2}}\)
3 \(\frac{C^{2} V^{2}}{d^{2}}\)
4 \(\frac{V^{2} d}{C}\)
Electrostatic Potentials and Capacitance

268137 Two identical capacitors 1 and 2areconnected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant \(K\) as shown. \(Q_{1}\) and \(Q_{2}\) arethe charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are \(Q_{1}^{\prime}\) and \(Q_{2}^{\prime}\).
Then

1 \(\frac{Q_{1}^{\prime}}{Q_{1}}=\frac{K+1}{K}\)
2 \(\frac{Q_{2}^{\prime} 2}{Q_{2}}=\frac{K+1}{2}\)
3 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K+1}{2 K}\)
4 \(\frac{Q_{2}^{\prime}}{Q_{2}}=\frac{K}{2}\)