268032
An insulator plateis passed between the plates of a capacitor. Then current
1 always flowsfromA to \(B\)
2 always flowsfromB to \(A\)
3 first flows fromA to \(B\) and then from \(B\) to \(A\)
4 first flows from \(B\) to \(A\) and then from \(A\) to \(B\)
Explanation:
The capacitor's capacity first increases as an insulator plate is slipped in between the plates, then decreases as the plate slides out. As a consequence, the positive charge on plate A increases initially before decreasing, causing current in the outer circuit to flow from B to A before returning to B.
Electrostatic Potentials and Capacitance
268037
A capacitor \(\mathbf{C}\) is connnected to a battery circuit having two switches \(S_{1}\) and \(S_{2}\) and resistors \(R_{1}\) and \(R_{2}\). The capacitor will be fully charged when
1 both\(S_{1}\) and \(S_{2}\) are closed
2 \(S_{1}\) is closed and \(S_{2}\) is open
3 \(S_{1}\) is open and \(S_{2}\) is closed
4 any one oftheabove
Explanation:
When both are open no charge will pass through the capacitor. When \(\mathrm{S}_1\) is open and \(\mathrm{S}_2\) is closed capacitor is not connected to the battery so not charge will flow.
When both \(\mathrm{S}_1\) and \(\mathrm{S}_2\) are closed, the potential drop across the capacitor will be \(\frac{\mathrm{ER}_2}{\mathrm{R}_1+\mathrm{R}_2}\) where E is the EMF of cell.
When \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open, the potential drop only occurs across the capacitor so the potential drop across the plates of the capacitor will be E .
The capacitor will be fully charged when \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open.
Electrostatic Potentials and Capacitance
268119
Theequivalent capacity of theinfinite net work shown in the figure (across \(A B\) ) is (C apacity of each capacitor is \(1 \mu \mathrm{F}\) )
1 \(\infty\)
2 \(1 \mu F\)
3 \(\left(\frac{\sqrt{3}-1}{2}\right) \mu F\)
4 \(\left(\frac{\sqrt{3}+1}{2}\right) \mu F\)
Explanation:
Between \(D \& E\) effectivecapacitanceis \(x\) \(\frac{1}{x+1}+1+1=x\)
268032
An insulator plateis passed between the plates of a capacitor. Then current
1 always flowsfromA to \(B\)
2 always flowsfromB to \(A\)
3 first flows fromA to \(B\) and then from \(B\) to \(A\)
4 first flows from \(B\) to \(A\) and then from \(A\) to \(B\)
Explanation:
The capacitor's capacity first increases as an insulator plate is slipped in between the plates, then decreases as the plate slides out. As a consequence, the positive charge on plate A increases initially before decreasing, causing current in the outer circuit to flow from B to A before returning to B.
Electrostatic Potentials and Capacitance
268037
A capacitor \(\mathbf{C}\) is connnected to a battery circuit having two switches \(S_{1}\) and \(S_{2}\) and resistors \(R_{1}\) and \(R_{2}\). The capacitor will be fully charged when
1 both\(S_{1}\) and \(S_{2}\) are closed
2 \(S_{1}\) is closed and \(S_{2}\) is open
3 \(S_{1}\) is open and \(S_{2}\) is closed
4 any one oftheabove
Explanation:
When both are open no charge will pass through the capacitor. When \(\mathrm{S}_1\) is open and \(\mathrm{S}_2\) is closed capacitor is not connected to the battery so not charge will flow.
When both \(\mathrm{S}_1\) and \(\mathrm{S}_2\) are closed, the potential drop across the capacitor will be \(\frac{\mathrm{ER}_2}{\mathrm{R}_1+\mathrm{R}_2}\) where E is the EMF of cell.
When \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open, the potential drop only occurs across the capacitor so the potential drop across the plates of the capacitor will be E .
The capacitor will be fully charged when \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open.
Electrostatic Potentials and Capacitance
268119
Theequivalent capacity of theinfinite net work shown in the figure (across \(A B\) ) is (C apacity of each capacitor is \(1 \mu \mathrm{F}\) )
1 \(\infty\)
2 \(1 \mu F\)
3 \(\left(\frac{\sqrt{3}-1}{2}\right) \mu F\)
4 \(\left(\frac{\sqrt{3}+1}{2}\right) \mu F\)
Explanation:
Between \(D \& E\) effectivecapacitanceis \(x\) \(\frac{1}{x+1}+1+1=x\)
268032
An insulator plateis passed between the plates of a capacitor. Then current
1 always flowsfromA to \(B\)
2 always flowsfromB to \(A\)
3 first flows fromA to \(B\) and then from \(B\) to \(A\)
4 first flows from \(B\) to \(A\) and then from \(A\) to \(B\)
Explanation:
The capacitor's capacity first increases as an insulator plate is slipped in between the plates, then decreases as the plate slides out. As a consequence, the positive charge on plate A increases initially before decreasing, causing current in the outer circuit to flow from B to A before returning to B.
Electrostatic Potentials and Capacitance
268037
A capacitor \(\mathbf{C}\) is connnected to a battery circuit having two switches \(S_{1}\) and \(S_{2}\) and resistors \(R_{1}\) and \(R_{2}\). The capacitor will be fully charged when
1 both\(S_{1}\) and \(S_{2}\) are closed
2 \(S_{1}\) is closed and \(S_{2}\) is open
3 \(S_{1}\) is open and \(S_{2}\) is closed
4 any one oftheabove
Explanation:
When both are open no charge will pass through the capacitor. When \(\mathrm{S}_1\) is open and \(\mathrm{S}_2\) is closed capacitor is not connected to the battery so not charge will flow.
When both \(\mathrm{S}_1\) and \(\mathrm{S}_2\) are closed, the potential drop across the capacitor will be \(\frac{\mathrm{ER}_2}{\mathrm{R}_1+\mathrm{R}_2}\) where E is the EMF of cell.
When \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open, the potential drop only occurs across the capacitor so the potential drop across the plates of the capacitor will be E .
The capacitor will be fully charged when \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open.
Electrostatic Potentials and Capacitance
268119
Theequivalent capacity of theinfinite net work shown in the figure (across \(A B\) ) is (C apacity of each capacitor is \(1 \mu \mathrm{F}\) )
1 \(\infty\)
2 \(1 \mu F\)
3 \(\left(\frac{\sqrt{3}-1}{2}\right) \mu F\)
4 \(\left(\frac{\sqrt{3}+1}{2}\right) \mu F\)
Explanation:
Between \(D \& E\) effectivecapacitanceis \(x\) \(\frac{1}{x+1}+1+1=x\)
268032
An insulator plateis passed between the plates of a capacitor. Then current
1 always flowsfromA to \(B\)
2 always flowsfromB to \(A\)
3 first flows fromA to \(B\) and then from \(B\) to \(A\)
4 first flows from \(B\) to \(A\) and then from \(A\) to \(B\)
Explanation:
The capacitor's capacity first increases as an insulator plate is slipped in between the plates, then decreases as the plate slides out. As a consequence, the positive charge on plate A increases initially before decreasing, causing current in the outer circuit to flow from B to A before returning to B.
Electrostatic Potentials and Capacitance
268037
A capacitor \(\mathbf{C}\) is connnected to a battery circuit having two switches \(S_{1}\) and \(S_{2}\) and resistors \(R_{1}\) and \(R_{2}\). The capacitor will be fully charged when
1 both\(S_{1}\) and \(S_{2}\) are closed
2 \(S_{1}\) is closed and \(S_{2}\) is open
3 \(S_{1}\) is open and \(S_{2}\) is closed
4 any one oftheabove
Explanation:
When both are open no charge will pass through the capacitor. When \(\mathrm{S}_1\) is open and \(\mathrm{S}_2\) is closed capacitor is not connected to the battery so not charge will flow.
When both \(\mathrm{S}_1\) and \(\mathrm{S}_2\) are closed, the potential drop across the capacitor will be \(\frac{\mathrm{ER}_2}{\mathrm{R}_1+\mathrm{R}_2}\) where E is the EMF of cell.
When \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open, the potential drop only occurs across the capacitor so the potential drop across the plates of the capacitor will be E .
The capacitor will be fully charged when \(\mathrm{S}_1\) is closed and \(\mathrm{S}_2\) is open.
Electrostatic Potentials and Capacitance
268119
Theequivalent capacity of theinfinite net work shown in the figure (across \(A B\) ) is (C apacity of each capacitor is \(1 \mu \mathrm{F}\) )
1 \(\infty\)
2 \(1 \mu F\)
3 \(\left(\frac{\sqrt{3}-1}{2}\right) \mu F\)
4 \(\left(\frac{\sqrt{3}+1}{2}\right) \mu F\)
Explanation:
Between \(D \& E\) effectivecapacitanceis \(x\) \(\frac{1}{x+1}+1+1=x\)
