268062
**Assertion:** A dielectric is inserted between the plates of an isolated fully-charged capacitor. The dielectric completely fills the space between the plates. The magnitude of electrostatic force on either metal plate decreases, as it was before the insertion of dielectric medium.
**Reason:** Due to insertion of dielectric slab in an isolated parallel plate capacitor (the dielectric completely fills the space between the plates), the electrostatic potential energy of the capacitor decreases.
268063
**Assertion:** If the potential difference across aplaneparallel platecapacitor is doubled then the potential energy of the capacitor is doubled then the potential energy of the capacitor becomes four times under all conditions
**Reason:** The potential energy \(\mathrm{U}\) stored in the capacitor is \(U=\frac{1}{2} C V^{2}\), where \(C\) and \(V\) have usual meaning.
268064
**Assertion:** A parallel plate capacitor is charged to a potential difference of \(100 \mathrm{~V}\), and disconnected from the voltage source. A slab of dielectric is then slowly inserted between the plates. Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is decreased.
**Reason:** W hen we insert a dielectric between the plates of a capacitor, the induced charges tend to draw in the dielectric into the field (just as neutral objects are attracted by charged objects due to induction). We resist this force while slowly inserting the dielectric, and thus do negative work on the system, removing electrostatic energy from the system.
268065
**Statement '\(A\) ':** The energy stored gets reduced by a factor ' \(K\) ' when the battery is disconnected after charging the capacitor and then thedielectric is introduced
**Statement ' \(B\) ':** The energy stored in the capacitor increases by a factor ' \(k\) ' when a dielectric is introduced between the plates with the battery present in the circuit
268062
**Assertion:** A dielectric is inserted between the plates of an isolated fully-charged capacitor. The dielectric completely fills the space between the plates. The magnitude of electrostatic force on either metal plate decreases, as it was before the insertion of dielectric medium.
**Reason:** Due to insertion of dielectric slab in an isolated parallel plate capacitor (the dielectric completely fills the space between the plates), the electrostatic potential energy of the capacitor decreases.
268063
**Assertion:** If the potential difference across aplaneparallel platecapacitor is doubled then the potential energy of the capacitor is doubled then the potential energy of the capacitor becomes four times under all conditions
**Reason:** The potential energy \(\mathrm{U}\) stored in the capacitor is \(U=\frac{1}{2} C V^{2}\), where \(C\) and \(V\) have usual meaning.
268064
**Assertion:** A parallel plate capacitor is charged to a potential difference of \(100 \mathrm{~V}\), and disconnected from the voltage source. A slab of dielectric is then slowly inserted between the plates. Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is decreased.
**Reason:** W hen we insert a dielectric between the plates of a capacitor, the induced charges tend to draw in the dielectric into the field (just as neutral objects are attracted by charged objects due to induction). We resist this force while slowly inserting the dielectric, and thus do negative work on the system, removing electrostatic energy from the system.
268065
**Statement '\(A\) ':** The energy stored gets reduced by a factor ' \(K\) ' when the battery is disconnected after charging the capacitor and then thedielectric is introduced
**Statement ' \(B\) ':** The energy stored in the capacitor increases by a factor ' \(k\) ' when a dielectric is introduced between the plates with the battery present in the circuit
268062
**Assertion:** A dielectric is inserted between the plates of an isolated fully-charged capacitor. The dielectric completely fills the space between the plates. The magnitude of electrostatic force on either metal plate decreases, as it was before the insertion of dielectric medium.
**Reason:** Due to insertion of dielectric slab in an isolated parallel plate capacitor (the dielectric completely fills the space between the plates), the electrostatic potential energy of the capacitor decreases.
268063
**Assertion:** If the potential difference across aplaneparallel platecapacitor is doubled then the potential energy of the capacitor is doubled then the potential energy of the capacitor becomes four times under all conditions
**Reason:** The potential energy \(\mathrm{U}\) stored in the capacitor is \(U=\frac{1}{2} C V^{2}\), where \(C\) and \(V\) have usual meaning.
268064
**Assertion:** A parallel plate capacitor is charged to a potential difference of \(100 \mathrm{~V}\), and disconnected from the voltage source. A slab of dielectric is then slowly inserted between the plates. Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is decreased.
**Reason:** W hen we insert a dielectric between the plates of a capacitor, the induced charges tend to draw in the dielectric into the field (just as neutral objects are attracted by charged objects due to induction). We resist this force while slowly inserting the dielectric, and thus do negative work on the system, removing electrostatic energy from the system.
268065
**Statement '\(A\) ':** The energy stored gets reduced by a factor ' \(K\) ' when the battery is disconnected after charging the capacitor and then thedielectric is introduced
**Statement ' \(B\) ':** The energy stored in the capacitor increases by a factor ' \(k\) ' when a dielectric is introduced between the plates with the battery present in the circuit
268062
**Assertion:** A dielectric is inserted between the plates of an isolated fully-charged capacitor. The dielectric completely fills the space between the plates. The magnitude of electrostatic force on either metal plate decreases, as it was before the insertion of dielectric medium.
**Reason:** Due to insertion of dielectric slab in an isolated parallel plate capacitor (the dielectric completely fills the space between the plates), the electrostatic potential energy of the capacitor decreases.
268063
**Assertion:** If the potential difference across aplaneparallel platecapacitor is doubled then the potential energy of the capacitor is doubled then the potential energy of the capacitor becomes four times under all conditions
**Reason:** The potential energy \(\mathrm{U}\) stored in the capacitor is \(U=\frac{1}{2} C V^{2}\), where \(C\) and \(V\) have usual meaning.
268064
**Assertion:** A parallel plate capacitor is charged to a potential difference of \(100 \mathrm{~V}\), and disconnected from the voltage source. A slab of dielectric is then slowly inserted between the plates. Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is decreased.
**Reason:** W hen we insert a dielectric between the plates of a capacitor, the induced charges tend to draw in the dielectric into the field (just as neutral objects are attracted by charged objects due to induction). We resist this force while slowly inserting the dielectric, and thus do negative work on the system, removing electrostatic energy from the system.
268065
**Statement '\(A\) ':** The energy stored gets reduced by a factor ' \(K\) ' when the battery is disconnected after charging the capacitor and then thedielectric is introduced
**Statement ' \(B\) ':** The energy stored in the capacitor increases by a factor ' \(k\) ' when a dielectric is introduced between the plates with the battery present in the circuit
268062
**Assertion:** A dielectric is inserted between the plates of an isolated fully-charged capacitor. The dielectric completely fills the space between the plates. The magnitude of electrostatic force on either metal plate decreases, as it was before the insertion of dielectric medium.
**Reason:** Due to insertion of dielectric slab in an isolated parallel plate capacitor (the dielectric completely fills the space between the plates), the electrostatic potential energy of the capacitor decreases.
268063
**Assertion:** If the potential difference across aplaneparallel platecapacitor is doubled then the potential energy of the capacitor is doubled then the potential energy of the capacitor becomes four times under all conditions
**Reason:** The potential energy \(\mathrm{U}\) stored in the capacitor is \(U=\frac{1}{2} C V^{2}\), where \(C\) and \(V\) have usual meaning.
268064
**Assertion:** A parallel plate capacitor is charged to a potential difference of \(100 \mathrm{~V}\), and disconnected from the voltage source. A slab of dielectric is then slowly inserted between the plates. Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is decreased.
**Reason:** W hen we insert a dielectric between the plates of a capacitor, the induced charges tend to draw in the dielectric into the field (just as neutral objects are attracted by charged objects due to induction). We resist this force while slowly inserting the dielectric, and thus do negative work on the system, removing electrostatic energy from the system.
268065
**Statement '\(A\) ':** The energy stored gets reduced by a factor ' \(K\) ' when the battery is disconnected after charging the capacitor and then thedielectric is introduced
**Statement ' \(B\) ':** The energy stored in the capacitor increases by a factor ' \(k\) ' when a dielectric is introduced between the plates with the battery present in the circuit