272187
An electric dipole, consisting of two opposite charges of $2\times {{10}^{-6}}C$ each separated by a distance $3~cm$ is placed in an electric field of $2\times {{10}^{5}}~N/C$. Torque acting on the dipole is
1 $12\times {{10}^{-1}}~N-m$
2 $12\times {{10}^{-2}}~N-m$
3 $12\times {{10}^{-3}}~N-m$
4 $12\times {{10}^{-4}}~N-m$
Explanation:
(c) Charges (q) $=2\times {{10}^{-6}}C$, Distance (d) $=3~cm$ $=3\times {{10}^{-2}}~m$ and electric field $\left( E \right)=2\times {{10}^{5}}~N/C$. Torque $\left( \tau \right)=q.d$. $E=\left( 2\times {{10}^{-6}} \right)\times \left( 3\times {{10}^{-2}} \right)\times \left( 2\times {{10}^{5}} \right)=12\times {{10}^{-3}}~N-m$.
NCERT Page-28 / N-27
Electric Charges and Fields
272191
If the dipole of moment $2.57\times {{10}^{-17}}~cm$ is placed into an electric field of magnitude $3.0\times {{10}^{4}}~N/C$ such that the fields lines are aligned at ${{30}^{\circ }}$ with the line joining $P$ to the dipole, what torque acts on the dipole?
272192
An electric dipole is placed at an angle of ${{30}^{\circ }}$ with an electric field of intensity $2\times {{10}^{5}}N{{C}^{-1}}$, It experiences a torque of $4Nm$. Calculate the charge on the dipole if the dipole length is $2~cm$.
272193
On decreasing the distance between the two charges of a dipole which is perpendicular to electric field and decreasing the angle between the dipole and electric field, the torque on the dipole
1 increases
2 decreases
3 remains same
4 cannot be predicted
Explanation:
(b) Since $\tau =pEsin\theta $ on decreasing the distance between the two charges, and on decreasing angle $\theta $ between the dipole and electric field, $sin\theta $ decreases therefore torque decreases.
272187
An electric dipole, consisting of two opposite charges of $2\times {{10}^{-6}}C$ each separated by a distance $3~cm$ is placed in an electric field of $2\times {{10}^{5}}~N/C$. Torque acting on the dipole is
1 $12\times {{10}^{-1}}~N-m$
2 $12\times {{10}^{-2}}~N-m$
3 $12\times {{10}^{-3}}~N-m$
4 $12\times {{10}^{-4}}~N-m$
Explanation:
(c) Charges (q) $=2\times {{10}^{-6}}C$, Distance (d) $=3~cm$ $=3\times {{10}^{-2}}~m$ and electric field $\left( E \right)=2\times {{10}^{5}}~N/C$. Torque $\left( \tau \right)=q.d$. $E=\left( 2\times {{10}^{-6}} \right)\times \left( 3\times {{10}^{-2}} \right)\times \left( 2\times {{10}^{5}} \right)=12\times {{10}^{-3}}~N-m$.
NCERT Page-28 / N-27
Electric Charges and Fields
272191
If the dipole of moment $2.57\times {{10}^{-17}}~cm$ is placed into an electric field of magnitude $3.0\times {{10}^{4}}~N/C$ such that the fields lines are aligned at ${{30}^{\circ }}$ with the line joining $P$ to the dipole, what torque acts on the dipole?
272192
An electric dipole is placed at an angle of ${{30}^{\circ }}$ with an electric field of intensity $2\times {{10}^{5}}N{{C}^{-1}}$, It experiences a torque of $4Nm$. Calculate the charge on the dipole if the dipole length is $2~cm$.
272193
On decreasing the distance between the two charges of a dipole which is perpendicular to electric field and decreasing the angle between the dipole and electric field, the torque on the dipole
1 increases
2 decreases
3 remains same
4 cannot be predicted
Explanation:
(b) Since $\tau =pEsin\theta $ on decreasing the distance between the two charges, and on decreasing angle $\theta $ between the dipole and electric field, $sin\theta $ decreases therefore torque decreases.
272187
An electric dipole, consisting of two opposite charges of $2\times {{10}^{-6}}C$ each separated by a distance $3~cm$ is placed in an electric field of $2\times {{10}^{5}}~N/C$. Torque acting on the dipole is
1 $12\times {{10}^{-1}}~N-m$
2 $12\times {{10}^{-2}}~N-m$
3 $12\times {{10}^{-3}}~N-m$
4 $12\times {{10}^{-4}}~N-m$
Explanation:
(c) Charges (q) $=2\times {{10}^{-6}}C$, Distance (d) $=3~cm$ $=3\times {{10}^{-2}}~m$ and electric field $\left( E \right)=2\times {{10}^{5}}~N/C$. Torque $\left( \tau \right)=q.d$. $E=\left( 2\times {{10}^{-6}} \right)\times \left( 3\times {{10}^{-2}} \right)\times \left( 2\times {{10}^{5}} \right)=12\times {{10}^{-3}}~N-m$.
NCERT Page-28 / N-27
Electric Charges and Fields
272191
If the dipole of moment $2.57\times {{10}^{-17}}~cm$ is placed into an electric field of magnitude $3.0\times {{10}^{4}}~N/C$ such that the fields lines are aligned at ${{30}^{\circ }}$ with the line joining $P$ to the dipole, what torque acts on the dipole?
272192
An electric dipole is placed at an angle of ${{30}^{\circ }}$ with an electric field of intensity $2\times {{10}^{5}}N{{C}^{-1}}$, It experiences a torque of $4Nm$. Calculate the charge on the dipole if the dipole length is $2~cm$.
272193
On decreasing the distance between the two charges of a dipole which is perpendicular to electric field and decreasing the angle between the dipole and electric field, the torque on the dipole
1 increases
2 decreases
3 remains same
4 cannot be predicted
Explanation:
(b) Since $\tau =pEsin\theta $ on decreasing the distance between the two charges, and on decreasing angle $\theta $ between the dipole and electric field, $sin\theta $ decreases therefore torque decreases.
272187
An electric dipole, consisting of two opposite charges of $2\times {{10}^{-6}}C$ each separated by a distance $3~cm$ is placed in an electric field of $2\times {{10}^{5}}~N/C$. Torque acting on the dipole is
1 $12\times {{10}^{-1}}~N-m$
2 $12\times {{10}^{-2}}~N-m$
3 $12\times {{10}^{-3}}~N-m$
4 $12\times {{10}^{-4}}~N-m$
Explanation:
(c) Charges (q) $=2\times {{10}^{-6}}C$, Distance (d) $=3~cm$ $=3\times {{10}^{-2}}~m$ and electric field $\left( E \right)=2\times {{10}^{5}}~N/C$. Torque $\left( \tau \right)=q.d$. $E=\left( 2\times {{10}^{-6}} \right)\times \left( 3\times {{10}^{-2}} \right)\times \left( 2\times {{10}^{5}} \right)=12\times {{10}^{-3}}~N-m$.
NCERT Page-28 / N-27
Electric Charges and Fields
272191
If the dipole of moment $2.57\times {{10}^{-17}}~cm$ is placed into an electric field of magnitude $3.0\times {{10}^{4}}~N/C$ such that the fields lines are aligned at ${{30}^{\circ }}$ with the line joining $P$ to the dipole, what torque acts on the dipole?
272192
An electric dipole is placed at an angle of ${{30}^{\circ }}$ with an electric field of intensity $2\times {{10}^{5}}N{{C}^{-1}}$, It experiences a torque of $4Nm$. Calculate the charge on the dipole if the dipole length is $2~cm$.
272193
On decreasing the distance between the two charges of a dipole which is perpendicular to electric field and decreasing the angle between the dipole and electric field, the torque on the dipole
1 increases
2 decreases
3 remains same
4 cannot be predicted
Explanation:
(b) Since $\tau =pEsin\theta $ on decreasing the distance between the two charges, and on decreasing angle $\theta $ between the dipole and electric field, $sin\theta $ decreases therefore torque decreases.