272155
Two point charges $+Q$ and $+q$ are separated by a certain distance. If $+Q>+q$ then in between the charges the electric field is zero at a point
1 closer to $+Q$
2 closer to $+q$
3 exactly at the mid-point of line segment joining $+Q$ and $+q$.
4 no where on the line segment joining $+Q$ and $+q$.
Explanation:
(b) Electric field is directly proportional to the magnitude of charge and inversely proportional to the square of the distance from the charge. Therefore charge $+Q$ produce a comparatively stronger electric field than $+q$ which get at cancelled with each other at a point closer to $+q$.
NCERT Page-20 / N-16
Electric Charges and Fields
272156
If an electron has an initial velocity in a direction different from that of an electric field, the path of the electron is
1 a straight line
2 a circle
3 an ellipse
4 aparabolà
Explanation:
(d)
NCERT Page-21 / N-14
Electric Charges and Fields
272157
In the figure, charge $q$ is placed at origin $\rho $. When the charge $q$ is displaced from its position the electric field at point $P$ changes
1 at the same time when $q$ is displaced.
2 at a time after $\frac{OP}{c}$ where $c$ is the speed of light.
3 at a time after $\frac{OPcos\theta }{c}$
4 at a time after $\frac{OPsin\theta }{c}$
Explanation:
(b) The electric field around a charge propagates with the speed of light away from the charge. Therefore the required time $=\frac{~distance~}{~speed~}=\frac{OP}{c}$.
NCERT Page-20 / N-14
Electric Charges and Fields
272158
The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass, charge of an electron respectively are $9.1\times {{10}^{-31}}~kg$ and $1.6\times {{10}^{-19}}C$.)
(d) Unit positive charge at $O$ will be repelled equally by three charges at the three corners of triangle. By symmetry, resultant $\vec{E}$ at $O$ would be zero.
272155
Two point charges $+Q$ and $+q$ are separated by a certain distance. If $+Q>+q$ then in between the charges the electric field is zero at a point
1 closer to $+Q$
2 closer to $+q$
3 exactly at the mid-point of line segment joining $+Q$ and $+q$.
4 no where on the line segment joining $+Q$ and $+q$.
Explanation:
(b) Electric field is directly proportional to the magnitude of charge and inversely proportional to the square of the distance from the charge. Therefore charge $+Q$ produce a comparatively stronger electric field than $+q$ which get at cancelled with each other at a point closer to $+q$.
NCERT Page-20 / N-16
Electric Charges and Fields
272156
If an electron has an initial velocity in a direction different from that of an electric field, the path of the electron is
1 a straight line
2 a circle
3 an ellipse
4 aparabolà
Explanation:
(d)
NCERT Page-21 / N-14
Electric Charges and Fields
272157
In the figure, charge $q$ is placed at origin $\rho $. When the charge $q$ is displaced from its position the electric field at point $P$ changes
1 at the same time when $q$ is displaced.
2 at a time after $\frac{OP}{c}$ where $c$ is the speed of light.
3 at a time after $\frac{OPcos\theta }{c}$
4 at a time after $\frac{OPsin\theta }{c}$
Explanation:
(b) The electric field around a charge propagates with the speed of light away from the charge. Therefore the required time $=\frac{~distance~}{~speed~}=\frac{OP}{c}$.
NCERT Page-20 / N-14
Electric Charges and Fields
272158
The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass, charge of an electron respectively are $9.1\times {{10}^{-31}}~kg$ and $1.6\times {{10}^{-19}}C$.)
(d) Unit positive charge at $O$ will be repelled equally by three charges at the three corners of triangle. By symmetry, resultant $\vec{E}$ at $O$ would be zero.
272155
Two point charges $+Q$ and $+q$ are separated by a certain distance. If $+Q>+q$ then in between the charges the electric field is zero at a point
1 closer to $+Q$
2 closer to $+q$
3 exactly at the mid-point of line segment joining $+Q$ and $+q$.
4 no where on the line segment joining $+Q$ and $+q$.
Explanation:
(b) Electric field is directly proportional to the magnitude of charge and inversely proportional to the square of the distance from the charge. Therefore charge $+Q$ produce a comparatively stronger electric field than $+q$ which get at cancelled with each other at a point closer to $+q$.
NCERT Page-20 / N-16
Electric Charges and Fields
272156
If an electron has an initial velocity in a direction different from that of an electric field, the path of the electron is
1 a straight line
2 a circle
3 an ellipse
4 aparabolà
Explanation:
(d)
NCERT Page-21 / N-14
Electric Charges and Fields
272157
In the figure, charge $q$ is placed at origin $\rho $. When the charge $q$ is displaced from its position the electric field at point $P$ changes
1 at the same time when $q$ is displaced.
2 at a time after $\frac{OP}{c}$ where $c$ is the speed of light.
3 at a time after $\frac{OPcos\theta }{c}$
4 at a time after $\frac{OPsin\theta }{c}$
Explanation:
(b) The electric field around a charge propagates with the speed of light away from the charge. Therefore the required time $=\frac{~distance~}{~speed~}=\frac{OP}{c}$.
NCERT Page-20 / N-14
Electric Charges and Fields
272158
The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass, charge of an electron respectively are $9.1\times {{10}^{-31}}~kg$ and $1.6\times {{10}^{-19}}C$.)
(d) Unit positive charge at $O$ will be repelled equally by three charges at the three corners of triangle. By symmetry, resultant $\vec{E}$ at $O$ would be zero.
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Electric Charges and Fields
272155
Two point charges $+Q$ and $+q$ are separated by a certain distance. If $+Q>+q$ then in between the charges the electric field is zero at a point
1 closer to $+Q$
2 closer to $+q$
3 exactly at the mid-point of line segment joining $+Q$ and $+q$.
4 no where on the line segment joining $+Q$ and $+q$.
Explanation:
(b) Electric field is directly proportional to the magnitude of charge and inversely proportional to the square of the distance from the charge. Therefore charge $+Q$ produce a comparatively stronger electric field than $+q$ which get at cancelled with each other at a point closer to $+q$.
NCERT Page-20 / N-16
Electric Charges and Fields
272156
If an electron has an initial velocity in a direction different from that of an electric field, the path of the electron is
1 a straight line
2 a circle
3 an ellipse
4 aparabolà
Explanation:
(d)
NCERT Page-21 / N-14
Electric Charges and Fields
272157
In the figure, charge $q$ is placed at origin $\rho $. When the charge $q$ is displaced from its position the electric field at point $P$ changes
1 at the same time when $q$ is displaced.
2 at a time after $\frac{OP}{c}$ where $c$ is the speed of light.
3 at a time after $\frac{OPcos\theta }{c}$
4 at a time after $\frac{OPsin\theta }{c}$
Explanation:
(b) The electric field around a charge propagates with the speed of light away from the charge. Therefore the required time $=\frac{~distance~}{~speed~}=\frac{OP}{c}$.
NCERT Page-20 / N-14
Electric Charges and Fields
272158
The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass, charge of an electron respectively are $9.1\times {{10}^{-31}}~kg$ and $1.6\times {{10}^{-19}}C$.)
(d) Unit positive charge at $O$ will be repelled equally by three charges at the three corners of triangle. By symmetry, resultant $\vec{E}$ at $O$ would be zero.
272155
Two point charges $+Q$ and $+q$ are separated by a certain distance. If $+Q>+q$ then in between the charges the electric field is zero at a point
1 closer to $+Q$
2 closer to $+q$
3 exactly at the mid-point of line segment joining $+Q$ and $+q$.
4 no where on the line segment joining $+Q$ and $+q$.
Explanation:
(b) Electric field is directly proportional to the magnitude of charge and inversely proportional to the square of the distance from the charge. Therefore charge $+Q$ produce a comparatively stronger electric field than $+q$ which get at cancelled with each other at a point closer to $+q$.
NCERT Page-20 / N-16
Electric Charges and Fields
272156
If an electron has an initial velocity in a direction different from that of an electric field, the path of the electron is
1 a straight line
2 a circle
3 an ellipse
4 aparabolà
Explanation:
(d)
NCERT Page-21 / N-14
Electric Charges and Fields
272157
In the figure, charge $q$ is placed at origin $\rho $. When the charge $q$ is displaced from its position the electric field at point $P$ changes
1 at the same time when $q$ is displaced.
2 at a time after $\frac{OP}{c}$ where $c$ is the speed of light.
3 at a time after $\frac{OPcos\theta }{c}$
4 at a time after $\frac{OPsin\theta }{c}$
Explanation:
(b) The electric field around a charge propagates with the speed of light away from the charge. Therefore the required time $=\frac{~distance~}{~speed~}=\frac{OP}{c}$.
NCERT Page-20 / N-14
Electric Charges and Fields
272158
The electric field intensity just sufficient to balance the earth's gravitational attraction on an electron will be: (given mass, charge of an electron respectively are $9.1\times {{10}^{-31}}~kg$ and $1.6\times {{10}^{-19}}C$.)
(d) Unit positive charge at $O$ will be repelled equally by three charges at the three corners of triangle. By symmetry, resultant $\vec{E}$ at $O$ would be zero.
