272138
Two positive ions, each carrying a charge $q$, are separated by a distance $d$. If $F$ is the force of repulsion between the ions, the number of electrons missing from each ion will be ( $e$ being the charge of an electron)
(c) Let $n$ be the number of electrons missing.
$~F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{d}^{2}}}\Rightarrow q=\sqrt{4\pi {{\varepsilon }_{0}}{{d}^{2}}F}=ne \therefore ~n=\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}~$
NCERT Page-12 / N-7
Electric Charges and Fields
272139
The electric charge required to expand a soap bubble to twice its dimension is
272140
Two balls of same mass and carrying equal charge are hung from a fixed support of length $l$. At electrostatic equilibrium, assuming that angles made by each thread is small, the separation, $x$ between the balls is proportional to :
272141
Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is $r$. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become
1 $\left( \frac{r}{\sqrt[3]{2}} \right)$
2 $\left( \frac{2r}{\sqrt{3}} \right)$
3 $\left( \frac{2r}{3} \right)$
4 ${{\left( \frac{r}{\sqrt{2}} \right)}^{2}}$
Explanation:
(a)
NCERT Page- 12 / N-7
Electric Charges and Fields
272142
Two equal point charges each of $3\mu C$ are separated by a certain distance in metres. If they are located at $\left( i+j+k \right)$ and $\left( 2i+3j+k \right)$, then the electrostatic force between them is
272138
Two positive ions, each carrying a charge $q$, are separated by a distance $d$. If $F$ is the force of repulsion between the ions, the number of electrons missing from each ion will be ( $e$ being the charge of an electron)
(c) Let $n$ be the number of electrons missing.
$~F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{d}^{2}}}\Rightarrow q=\sqrt{4\pi {{\varepsilon }_{0}}{{d}^{2}}F}=ne \therefore ~n=\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}~$
NCERT Page-12 / N-7
Electric Charges and Fields
272139
The electric charge required to expand a soap bubble to twice its dimension is
272140
Two balls of same mass and carrying equal charge are hung from a fixed support of length $l$. At electrostatic equilibrium, assuming that angles made by each thread is small, the separation, $x$ between the balls is proportional to :
272141
Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is $r$. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become
1 $\left( \frac{r}{\sqrt[3]{2}} \right)$
2 $\left( \frac{2r}{\sqrt{3}} \right)$
3 $\left( \frac{2r}{3} \right)$
4 ${{\left( \frac{r}{\sqrt{2}} \right)}^{2}}$
Explanation:
(a)
NCERT Page- 12 / N-7
Electric Charges and Fields
272142
Two equal point charges each of $3\mu C$ are separated by a certain distance in metres. If they are located at $\left( i+j+k \right)$ and $\left( 2i+3j+k \right)$, then the electrostatic force between them is
NEET Test Series from KOTA - 10 Papers In MS WORD
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Electric Charges and Fields
272138
Two positive ions, each carrying a charge $q$, are separated by a distance $d$. If $F$ is the force of repulsion between the ions, the number of electrons missing from each ion will be ( $e$ being the charge of an electron)
(c) Let $n$ be the number of electrons missing.
$~F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{d}^{2}}}\Rightarrow q=\sqrt{4\pi {{\varepsilon }_{0}}{{d}^{2}}F}=ne \therefore ~n=\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}~$
NCERT Page-12 / N-7
Electric Charges and Fields
272139
The electric charge required to expand a soap bubble to twice its dimension is
272140
Two balls of same mass and carrying equal charge are hung from a fixed support of length $l$. At electrostatic equilibrium, assuming that angles made by each thread is small, the separation, $x$ between the balls is proportional to :
272141
Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is $r$. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become
1 $\left( \frac{r}{\sqrt[3]{2}} \right)$
2 $\left( \frac{2r}{\sqrt{3}} \right)$
3 $\left( \frac{2r}{3} \right)$
4 ${{\left( \frac{r}{\sqrt{2}} \right)}^{2}}$
Explanation:
(a)
NCERT Page- 12 / N-7
Electric Charges and Fields
272142
Two equal point charges each of $3\mu C$ are separated by a certain distance in metres. If they are located at $\left( i+j+k \right)$ and $\left( 2i+3j+k \right)$, then the electrostatic force between them is
272138
Two positive ions, each carrying a charge $q$, are separated by a distance $d$. If $F$ is the force of repulsion between the ions, the number of electrons missing from each ion will be ( $e$ being the charge of an electron)
(c) Let $n$ be the number of electrons missing.
$~F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{d}^{2}}}\Rightarrow q=\sqrt{4\pi {{\varepsilon }_{0}}{{d}^{2}}F}=ne \therefore ~n=\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}~$
NCERT Page-12 / N-7
Electric Charges and Fields
272139
The electric charge required to expand a soap bubble to twice its dimension is
272140
Two balls of same mass and carrying equal charge are hung from a fixed support of length $l$. At electrostatic equilibrium, assuming that angles made by each thread is small, the separation, $x$ between the balls is proportional to :
272141
Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is $r$. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become
1 $\left( \frac{r}{\sqrt[3]{2}} \right)$
2 $\left( \frac{2r}{\sqrt{3}} \right)$
3 $\left( \frac{2r}{3} \right)$
4 ${{\left( \frac{r}{\sqrt{2}} \right)}^{2}}$
Explanation:
(a)
NCERT Page- 12 / N-7
Electric Charges and Fields
272142
Two equal point charges each of $3\mu C$ are separated by a certain distance in metres. If they are located at $\left( i+j+k \right)$ and $\left( 2i+3j+k \right)$, then the electrostatic force between them is
272138
Two positive ions, each carrying a charge $q$, are separated by a distance $d$. If $F$ is the force of repulsion between the ions, the number of electrons missing from each ion will be ( $e$ being the charge of an electron)
(c) Let $n$ be the number of electrons missing.
$~F=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{{{q}^{2}}}{{{d}^{2}}}\Rightarrow q=\sqrt{4\pi {{\varepsilon }_{0}}{{d}^{2}}F}=ne \therefore ~n=\sqrt{\frac{4\pi {{\varepsilon }_{0}}F{{d}^{2}}}{{{e}^{2}}}}~$
NCERT Page-12 / N-7
Electric Charges and Fields
272139
The electric charge required to expand a soap bubble to twice its dimension is
272140
Two balls of same mass and carrying equal charge are hung from a fixed support of length $l$. At electrostatic equilibrium, assuming that angles made by each thread is small, the separation, $x$ between the balls is proportional to :
272141
Two pith balls carrying equal charges are suspended from a common point by strings of equal length. The equilibrium separation between them is $r$. Now the strings are rigidly clamped at half the height. The equilibrium separation between the balls now become
1 $\left( \frac{r}{\sqrt[3]{2}} \right)$
2 $\left( \frac{2r}{\sqrt{3}} \right)$
3 $\left( \frac{2r}{3} \right)$
4 ${{\left( \frac{r}{\sqrt{2}} \right)}^{2}}$
Explanation:
(a)
NCERT Page- 12 / N-7
Electric Charges and Fields
272142
Two equal point charges each of $3\mu C$ are separated by a certain distance in metres. If they are located at $\left( i+j+k \right)$ and $\left( 2i+3j+k \right)$, then the electrostatic force between them is