266589 The equivalent capacitance of three capacitors of capacitance \(\mathrm{C}_1, \mathrm{C}_2 \& \mathrm{C}_5\) are connected in parallel is 12 units \& product \(C_1 C_2 C_5=48\). When the capacitors \(\mathrm{C}_1 \& \mathrm{C}_2\) are connected in parallel the equivalent capacitance is 6 unit. Then capacitances are:
266590 The current in a wire varies with time according to the equation \(I=4+2 \mathrm{t}\), where \(I\) is in ampere and \(t\) is in second. The quantity of charge which has to be passed through a cross-section of the wire during the time \(t=2 \mathrm{~s}\) to \(t=6 \mathrm{~s}\) is :
266591
A 100 W bulb \(\mathrm{B}_1\) and two 60 W bulbs \(\mathrm{B}_2 \& \mathrm{~B}_3\) are connected to 250 V source as shown in figure. How \(\mathrm{W}_1, \mathrm{~W}_2 \& \mathrm{~W}_3\) are the output powers of bulbs \(\mathrm{B}_1, \mathrm{~B}_2\) and \(B_3\) respectively then : 
266589 The equivalent capacitance of three capacitors of capacitance \(\mathrm{C}_1, \mathrm{C}_2 \& \mathrm{C}_5\) are connected in parallel is 12 units \& product \(C_1 C_2 C_5=48\). When the capacitors \(\mathrm{C}_1 \& \mathrm{C}_2\) are connected in parallel the equivalent capacitance is 6 unit. Then capacitances are:
266590 The current in a wire varies with time according to the equation \(I=4+2 \mathrm{t}\), where \(I\) is in ampere and \(t\) is in second. The quantity of charge which has to be passed through a cross-section of the wire during the time \(t=2 \mathrm{~s}\) to \(t=6 \mathrm{~s}\) is :
266591
A 100 W bulb \(\mathrm{B}_1\) and two 60 W bulbs \(\mathrm{B}_2 \& \mathrm{~B}_3\) are connected to 250 V source as shown in figure. How \(\mathrm{W}_1, \mathrm{~W}_2 \& \mathrm{~W}_3\) are the output powers of bulbs \(\mathrm{B}_1, \mathrm{~B}_2\) and \(B_3\) respectively then :
266589 The equivalent capacitance of three capacitors of capacitance \(\mathrm{C}_1, \mathrm{C}_2 \& \mathrm{C}_5\) are connected in parallel is 12 units \& product \(C_1 C_2 C_5=48\). When the capacitors \(\mathrm{C}_1 \& \mathrm{C}_2\) are connected in parallel the equivalent capacitance is 6 unit. Then capacitances are:
266590 The current in a wire varies with time according to the equation \(I=4+2 \mathrm{t}\), where \(I\) is in ampere and \(t\) is in second. The quantity of charge which has to be passed through a cross-section of the wire during the time \(t=2 \mathrm{~s}\) to \(t=6 \mathrm{~s}\) is :
266591
A 100 W bulb \(\mathrm{B}_1\) and two 60 W bulbs \(\mathrm{B}_2 \& \mathrm{~B}_3\) are connected to 250 V source as shown in figure. How \(\mathrm{W}_1, \mathrm{~W}_2 \& \mathrm{~W}_3\) are the output powers of bulbs \(\mathrm{B}_1, \mathrm{~B}_2\) and \(B_3\) respectively then :
266589 The equivalent capacitance of three capacitors of capacitance \(\mathrm{C}_1, \mathrm{C}_2 \& \mathrm{C}_5\) are connected in parallel is 12 units \& product \(C_1 C_2 C_5=48\). When the capacitors \(\mathrm{C}_1 \& \mathrm{C}_2\) are connected in parallel the equivalent capacitance is 6 unit. Then capacitances are:
266590 The current in a wire varies with time according to the equation \(I=4+2 \mathrm{t}\), where \(I\) is in ampere and \(t\) is in second. The quantity of charge which has to be passed through a cross-section of the wire during the time \(t=2 \mathrm{~s}\) to \(t=6 \mathrm{~s}\) is :
266591
A 100 W bulb \(\mathrm{B}_1\) and two 60 W bulbs \(\mathrm{B}_2 \& \mathrm{~B}_3\) are connected to 250 V source as shown in figure. How \(\mathrm{W}_1, \mathrm{~W}_2 \& \mathrm{~W}_3\) are the output powers of bulbs \(\mathrm{B}_1, \mathrm{~B}_2\) and \(B_3\) respectively then :
266589 The equivalent capacitance of three capacitors of capacitance \(\mathrm{C}_1, \mathrm{C}_2 \& \mathrm{C}_5\) are connected in parallel is 12 units \& product \(C_1 C_2 C_5=48\). When the capacitors \(\mathrm{C}_1 \& \mathrm{C}_2\) are connected in parallel the equivalent capacitance is 6 unit. Then capacitances are:
266590 The current in a wire varies with time according to the equation \(I=4+2 \mathrm{t}\), where \(I\) is in ampere and \(t\) is in second. The quantity of charge which has to be passed through a cross-section of the wire during the time \(t=2 \mathrm{~s}\) to \(t=6 \mathrm{~s}\) is :
266591
A 100 W bulb \(\mathrm{B}_1\) and two 60 W bulbs \(\mathrm{B}_2 \& \mathrm{~B}_3\) are connected to 250 V source as shown in figure. How \(\mathrm{W}_1, \mathrm{~W}_2 \& \mathrm{~W}_3\) are the output powers of bulbs \(\mathrm{B}_1, \mathrm{~B}_2\) and \(B_3\) respectively then :