266483 An electron is travelling horizontally towards east. A magnetic field in vertically downward direction exerts a force on the electron along

266484 What is current in the circuit shown below:

266485 Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, sucussively illuminates a metal of work function 0.5 eV . The ratio of maximum kinetic energy of the emitted electron will be

266486 The focal lengths for violet, green and red light rays are \(f_w, f_G\) and \(f_R\) respectively. Which of the following is the true relationship

TEST SERIES (PHYSICS FST)

266483 An electron is travelling horizontally towards east. A magnetic field in vertically downward direction exerts a force on the electron along

1 East

2 West

3 North

4 South

Show/Hide Explanation

Explanation:

d

TEST SERIES (PHYSICS FST)

266484 What is current in the circuit shown below:

1 0 Amp.

2 \(10^{-2} \mathrm{Amp}\).

3 1 Amp.

4 0.10 Amp .

Show/Hide Explanation

Explanation:

a
Current is zero in reverse bias.

**NCERT-XI-II-289**

TEST SERIES (PHYSICS FST)

266485 Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, sucussively illuminates a metal of work function 0.5 eV . The ratio of maximum kinetic energy of the emitted electron will be

1 \(1: 5\)

2 \(1: 4\)

3 \(1: 2\)

4 \(1: 1\)

Show/Hide Explanation

Explanation:

b
By using \(E=W_0+K_{\text {max }}\)
\(K_{\text {max }}=E-W_0\)
Hence, \(K_1=1-0.5=0.5\)
and \(K_2=2.5-0.5=2\)
\[
\frac{K_1}{K_2}=\frac{1}{4}
\]

**NCERT-XII-II-281**

TEST SERIES (PHYSICS FST)

266486 The focal lengths for violet, green and red light rays are \(f_w, f_G\) and \(f_R\) respectively. Which of the following is the true relationship

1 \(f_R

2 \(f_v

3 \(f_G

4 \(f_G

Show/Hide Explanation

Explanation:

b
\(f \infty \frac{1}{\mu-1}\) and \(\mu \infty \frac{1}{\lambda}\)

**NCERT-XIIII-223**

NEET DIGITAL LIBRARY

TEST SERIES (PHYSICS FST)

266483 An electron is travelling horizontally towards east. A magnetic field in vertically downward direction exerts a force on the electron along

1 East

2 West

3 North

4 South

Show/Hide Explanation

Explanation:

d

TEST SERIES (PHYSICS FST)

266484 What is current in the circuit shown below:

1 0 Amp.

2 \(10^{-2} \mathrm{Amp}\).

3 1 Amp.

4 0.10 Amp .

Show/Hide Explanation

Explanation:

a
Current is zero in reverse bias.

**NCERT-XI-II-289**

TEST SERIES (PHYSICS FST)

266485 Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, sucussively illuminates a metal of work function 0.5 eV . The ratio of maximum kinetic energy of the emitted electron will be

1 \(1: 5\)

2 \(1: 4\)

3 \(1: 2\)

4 \(1: 1\)

Show/Hide Explanation

Explanation:

b
By using \(E=W_0+K_{\text {max }}\)
\(K_{\text {max }}=E-W_0\)
Hence, \(K_1=1-0.5=0.5\)
and \(K_2=2.5-0.5=2\)
\[
\frac{K_1}{K_2}=\frac{1}{4}
\]

**NCERT-XII-II-281**

TEST SERIES (PHYSICS FST)

266486 The focal lengths for violet, green and red light rays are \(f_w, f_G\) and \(f_R\) respectively. Which of the following is the true relationship

1 \(f_R

2 \(f_v

3 \(f_G

4 \(f_G

Show/Hide Explanation

Explanation:

b
\(f \infty \frac{1}{\mu-1}\) and \(\mu \infty \frac{1}{\lambda}\)

**NCERT-XIIII-223**

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TEST SERIES (PHYSICS FST)

266483 An electron is travelling horizontally towards east. A magnetic field in vertically downward direction exerts a force on the electron along

1 East

2 West

3 North

4 South

Show/Hide Explanation

Explanation:

d

TEST SERIES (PHYSICS FST)

266484 What is current in the circuit shown below:

1 0 Amp.

2 \(10^{-2} \mathrm{Amp}\).

3 1 Amp.

4 0.10 Amp .

Show/Hide Explanation

Explanation:

a
Current is zero in reverse bias.

**NCERT-XI-II-289**

TEST SERIES (PHYSICS FST)

266485 Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, sucussively illuminates a metal of work function 0.5 eV . The ratio of maximum kinetic energy of the emitted electron will be

1 \(1: 5\)

2 \(1: 4\)

3 \(1: 2\)

4 \(1: 1\)

Show/Hide Explanation

Explanation:

b
By using \(E=W_0+K_{\text {max }}\)
\(K_{\text {max }}=E-W_0\)
Hence, \(K_1=1-0.5=0.5\)
and \(K_2=2.5-0.5=2\)
\[
\frac{K_1}{K_2}=\frac{1}{4}
\]

**NCERT-XII-II-281**

TEST SERIES (PHYSICS FST)

266486 The focal lengths for violet, green and red light rays are \(f_w, f_G\) and \(f_R\) respectively. Which of the following is the true relationship

1 \(f_R

2 \(f_v

3 \(f_G

4 \(f_G

Show/Hide Explanation

Explanation:

b
\(f \infty \frac{1}{\mu-1}\) and \(\mu \infty \frac{1}{\lambda}\)

**NCERT-XIIII-223**

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