266467
Voltage and current in an AC circuit are given by \(V=5 \sin \left[100 \pi t-\frac{\pi}{6}\right]\) and \(I=4 \sin \left[100 \pi t+\frac{\pi}{6}\right]\)
266468
The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is \(v\). The velocity of an electron in its fifth orbit will be -
1 v
2 \(\frac{22}{5} \mathrm{v}\)
3 \(\frac{5}{2} v\)
4 \(\frac{2}{5} v\)
Explanation:
d \[ \begin{aligned} & v=\frac{1}{\pi} \Rightarrow \frac{v_5}{v_2}=\frac{2}{5} \\ & v_5=\frac{2}{5} v_2=\frac{2}{5} v \end{aligned} \]
266467
Voltage and current in an AC circuit are given by \(V=5 \sin \left[100 \pi t-\frac{\pi}{6}\right]\) and \(I=4 \sin \left[100 \pi t+\frac{\pi}{6}\right]\)
266468
The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is \(v\). The velocity of an electron in its fifth orbit will be -
1 v
2 \(\frac{22}{5} \mathrm{v}\)
3 \(\frac{5}{2} v\)
4 \(\frac{2}{5} v\)
Explanation:
d \[ \begin{aligned} & v=\frac{1}{\pi} \Rightarrow \frac{v_5}{v_2}=\frac{2}{5} \\ & v_5=\frac{2}{5} v_2=\frac{2}{5} v \end{aligned} \]
266467
Voltage and current in an AC circuit are given by \(V=5 \sin \left[100 \pi t-\frac{\pi}{6}\right]\) and \(I=4 \sin \left[100 \pi t+\frac{\pi}{6}\right]\)
266468
The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is \(v\). The velocity of an electron in its fifth orbit will be -
1 v
2 \(\frac{22}{5} \mathrm{v}\)
3 \(\frac{5}{2} v\)
4 \(\frac{2}{5} v\)
Explanation:
d \[ \begin{aligned} & v=\frac{1}{\pi} \Rightarrow \frac{v_5}{v_2}=\frac{2}{5} \\ & v_5=\frac{2}{5} v_2=\frac{2}{5} v \end{aligned} \]
266467
Voltage and current in an AC circuit are given by \(V=5 \sin \left[100 \pi t-\frac{\pi}{6}\right]\) and \(I=4 \sin \left[100 \pi t+\frac{\pi}{6}\right]\)
266468
The velocity of an electron in the second orbit of sodium atom (atomic number = 11) is \(v\). The velocity of an electron in its fifth orbit will be -
1 v
2 \(\frac{22}{5} \mathrm{v}\)
3 \(\frac{5}{2} v\)
4 \(\frac{2}{5} v\)
Explanation:
d \[ \begin{aligned} & v=\frac{1}{\pi} \Rightarrow \frac{v_5}{v_2}=\frac{2}{5} \\ & v_5=\frac{2}{5} v_2=\frac{2}{5} v \end{aligned} \]