266461
A body of mass 100 g is sliding from an inclined plane of inclination \(30^{\circ}\). What is the frictional force experienced if \(\boldsymbol{\mu}=\mathbf{1 . 7}\).
266462
The radius and mass of earth are increased by \(0.5 \%\), Which of the following statement is not true at the surface of the earth.
1 9 will increase
2 g will decrease
3 escape velocity will remain unchanged
4 potentialenergy will remain unchanged
Explanation:
a \[ \begin{aligned} & g=\frac{G M}{R^2}, V_e=\sqrt{\frac{2 G M}{R}} \text { and } U=-\frac{G M m}{R} \\ \therefore \quad & g=\frac{M}{R^2}, V_e=\sqrt{\frac{M}{R}} \text { and } U \infty \frac{M}{R} \end{aligned} \] If both mass and radius are increased by \(0.5 \%\) then \(V_e\) and \(U\) remains unchanged where as \(g\) decreases by \(0.5 \%\).
**NCERT-XI-I-134**
TEST SERIES (PHYSICS FST)
266463
The graph shows the variation of displacement of a particle executing SHM with time. We infer from this graph that
1 The force is zero at time 3T/4
2 The velocity is maximum at time \(T / 2\)
3 The acceleration is maximum at time \(T\)
4 The PE is equal to total energy at time T/2
Explanation:
b At time \(\frac{T}{2} ; y=0\) Particle is at mean position hence, velocity is maximum.
**NCERT-XI-II-269**
TEST SERIES (PHYSICS FST)
266464
Resistance of 6 ohm each are connected in the manner shown in adjoining figure. With the current 0.5 ampere as shown in figure, the potential difference \(V_P-V_Q\) is
NEET Test Series from KOTA - 10 Papers In MS WORD
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TEST SERIES (PHYSICS FST)
266461
A body of mass 100 g is sliding from an inclined plane of inclination \(30^{\circ}\). What is the frictional force experienced if \(\boldsymbol{\mu}=\mathbf{1 . 7}\).
266462
The radius and mass of earth are increased by \(0.5 \%\), Which of the following statement is not true at the surface of the earth.
1 9 will increase
2 g will decrease
3 escape velocity will remain unchanged
4 potentialenergy will remain unchanged
Explanation:
a \[ \begin{aligned} & g=\frac{G M}{R^2}, V_e=\sqrt{\frac{2 G M}{R}} \text { and } U=-\frac{G M m}{R} \\ \therefore \quad & g=\frac{M}{R^2}, V_e=\sqrt{\frac{M}{R}} \text { and } U \infty \frac{M}{R} \end{aligned} \] If both mass and radius are increased by \(0.5 \%\) then \(V_e\) and \(U\) remains unchanged where as \(g\) decreases by \(0.5 \%\).
**NCERT-XI-I-134**
TEST SERIES (PHYSICS FST)
266463
The graph shows the variation of displacement of a particle executing SHM with time. We infer from this graph that
1 The force is zero at time 3T/4
2 The velocity is maximum at time \(T / 2\)
3 The acceleration is maximum at time \(T\)
4 The PE is equal to total energy at time T/2
Explanation:
b At time \(\frac{T}{2} ; y=0\) Particle is at mean position hence, velocity is maximum.
**NCERT-XI-II-269**
TEST SERIES (PHYSICS FST)
266464
Resistance of 6 ohm each are connected in the manner shown in adjoining figure. With the current 0.5 ampere as shown in figure, the potential difference \(V_P-V_Q\) is
266461
A body of mass 100 g is sliding from an inclined plane of inclination \(30^{\circ}\). What is the frictional force experienced if \(\boldsymbol{\mu}=\mathbf{1 . 7}\).
266462
The radius and mass of earth are increased by \(0.5 \%\), Which of the following statement is not true at the surface of the earth.
1 9 will increase
2 g will decrease
3 escape velocity will remain unchanged
4 potentialenergy will remain unchanged
Explanation:
a \[ \begin{aligned} & g=\frac{G M}{R^2}, V_e=\sqrt{\frac{2 G M}{R}} \text { and } U=-\frac{G M m}{R} \\ \therefore \quad & g=\frac{M}{R^2}, V_e=\sqrt{\frac{M}{R}} \text { and } U \infty \frac{M}{R} \end{aligned} \] If both mass and radius are increased by \(0.5 \%\) then \(V_e\) and \(U\) remains unchanged where as \(g\) decreases by \(0.5 \%\).
**NCERT-XI-I-134**
TEST SERIES (PHYSICS FST)
266463
The graph shows the variation of displacement of a particle executing SHM with time. We infer from this graph that
1 The force is zero at time 3T/4
2 The velocity is maximum at time \(T / 2\)
3 The acceleration is maximum at time \(T\)
4 The PE is equal to total energy at time T/2
Explanation:
b At time \(\frac{T}{2} ; y=0\) Particle is at mean position hence, velocity is maximum.
**NCERT-XI-II-269**
TEST SERIES (PHYSICS FST)
266464
Resistance of 6 ohm each are connected in the manner shown in adjoining figure. With the current 0.5 ampere as shown in figure, the potential difference \(V_P-V_Q\) is
266461
A body of mass 100 g is sliding from an inclined plane of inclination \(30^{\circ}\). What is the frictional force experienced if \(\boldsymbol{\mu}=\mathbf{1 . 7}\).
266462
The radius and mass of earth are increased by \(0.5 \%\), Which of the following statement is not true at the surface of the earth.
1 9 will increase
2 g will decrease
3 escape velocity will remain unchanged
4 potentialenergy will remain unchanged
Explanation:
a \[ \begin{aligned} & g=\frac{G M}{R^2}, V_e=\sqrt{\frac{2 G M}{R}} \text { and } U=-\frac{G M m}{R} \\ \therefore \quad & g=\frac{M}{R^2}, V_e=\sqrt{\frac{M}{R}} \text { and } U \infty \frac{M}{R} \end{aligned} \] If both mass and radius are increased by \(0.5 \%\) then \(V_e\) and \(U\) remains unchanged where as \(g\) decreases by \(0.5 \%\).
**NCERT-XI-I-134**
TEST SERIES (PHYSICS FST)
266463
The graph shows the variation of displacement of a particle executing SHM with time. We infer from this graph that
1 The force is zero at time 3T/4
2 The velocity is maximum at time \(T / 2\)
3 The acceleration is maximum at time \(T\)
4 The PE is equal to total energy at time T/2
Explanation:
b At time \(\frac{T}{2} ; y=0\) Particle is at mean position hence, velocity is maximum.
**NCERT-XI-II-269**
TEST SERIES (PHYSICS FST)
266464
Resistance of 6 ohm each are connected in the manner shown in adjoining figure. With the current 0.5 ampere as shown in figure, the potential difference \(V_P-V_Q\) is
