b \[ |\overrightarrow{\mathrm{C}}|^2+|\overrightarrow{\mathrm{D}}|^2=2|\overrightarrow{\mathrm{~A}}|^2+2|\overrightarrow{\mathrm{~B}}|^2 \]
**NCERT-72**
TEST SERIES (PHYSICS FST)
266634
Heat required to increase the temperature of an ideal gas is 30 jule at constant volume. The heat required to increase the temperature in same amount for same sample of gas at constant pressure will be:
1 30 doule
2 18 Joule
3 50 Joule
4 Zero
Explanation:
c \[ \frac{Q_p}{Q_V}=\frac{\pi C_p \Delta T}{\pi C_\psi \Delta T}=\gamma \]
**NCERT-120**
TEST SERIES (PHYSICS FST)
266649
Velocity of a body is expressed as \(V=G^a \mathbf{m b}^b R^c\) where \(G\) is universal gravitational constant, \(M\) is mass and R is radius. Then values of \(a, b, c\) is respectively:
266650
A student takes 50 gm wax (specific heat \(=0.6\) kcal \(/ \mathrm{kg}^{\circ} \mathrm{C}\) ) and heats it till it boils. The graph between temperature and time is as follows. Heat supplied to the wax per minute and boiling point are respectively.
1 \(500 \mathrm{cal}, 50^{\circ} \mathrm{C}\)
2 \(1000 \mathrm{cal}, 100^{\circ} \mathrm{C}\)
3 \(1500 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
4 \(1000 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
Explanation:
c Since specific heat \(=0.6 \mathrm{k}\) cali \(\mathrm{kg}{ }^{\circ} \mathrm{C}\) \(=0.6\) callgm \(^{\circ} \mathrm{C}\) From graph it is clear that in a minute that temperature is raised from \(0^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\). \(\Rightarrow\) Heat required for a minute \(=50 \times 0.6 \times 50\) \[ =1500 \mathrm{cal} . \] Also from graph, Bioling point of wax is \(200^{\circ} \mathrm{C}\)
b \[ |\overrightarrow{\mathrm{C}}|^2+|\overrightarrow{\mathrm{D}}|^2=2|\overrightarrow{\mathrm{~A}}|^2+2|\overrightarrow{\mathrm{~B}}|^2 \]
**NCERT-72**
TEST SERIES (PHYSICS FST)
266634
Heat required to increase the temperature of an ideal gas is 30 jule at constant volume. The heat required to increase the temperature in same amount for same sample of gas at constant pressure will be:
1 30 doule
2 18 Joule
3 50 Joule
4 Zero
Explanation:
c \[ \frac{Q_p}{Q_V}=\frac{\pi C_p \Delta T}{\pi C_\psi \Delta T}=\gamma \]
**NCERT-120**
TEST SERIES (PHYSICS FST)
266649
Velocity of a body is expressed as \(V=G^a \mathbf{m b}^b R^c\) where \(G\) is universal gravitational constant, \(M\) is mass and R is radius. Then values of \(a, b, c\) is respectively:
266650
A student takes 50 gm wax (specific heat \(=0.6\) kcal \(/ \mathrm{kg}^{\circ} \mathrm{C}\) ) and heats it till it boils. The graph between temperature and time is as follows. Heat supplied to the wax per minute and boiling point are respectively.
1 \(500 \mathrm{cal}, 50^{\circ} \mathrm{C}\)
2 \(1000 \mathrm{cal}, 100^{\circ} \mathrm{C}\)
3 \(1500 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
4 \(1000 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
Explanation:
c Since specific heat \(=0.6 \mathrm{k}\) cali \(\mathrm{kg}{ }^{\circ} \mathrm{C}\) \(=0.6\) callgm \(^{\circ} \mathrm{C}\) From graph it is clear that in a minute that temperature is raised from \(0^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\). \(\Rightarrow\) Heat required for a minute \(=50 \times 0.6 \times 50\) \[ =1500 \mathrm{cal} . \] Also from graph, Bioling point of wax is \(200^{\circ} \mathrm{C}\)
b \[ |\overrightarrow{\mathrm{C}}|^2+|\overrightarrow{\mathrm{D}}|^2=2|\overrightarrow{\mathrm{~A}}|^2+2|\overrightarrow{\mathrm{~B}}|^2 \]
**NCERT-72**
TEST SERIES (PHYSICS FST)
266634
Heat required to increase the temperature of an ideal gas is 30 jule at constant volume. The heat required to increase the temperature in same amount for same sample of gas at constant pressure will be:
1 30 doule
2 18 Joule
3 50 Joule
4 Zero
Explanation:
c \[ \frac{Q_p}{Q_V}=\frac{\pi C_p \Delta T}{\pi C_\psi \Delta T}=\gamma \]
**NCERT-120**
TEST SERIES (PHYSICS FST)
266649
Velocity of a body is expressed as \(V=G^a \mathbf{m b}^b R^c\) where \(G\) is universal gravitational constant, \(M\) is mass and R is radius. Then values of \(a, b, c\) is respectively:
266650
A student takes 50 gm wax (specific heat \(=0.6\) kcal \(/ \mathrm{kg}^{\circ} \mathrm{C}\) ) and heats it till it boils. The graph between temperature and time is as follows. Heat supplied to the wax per minute and boiling point are respectively.
1 \(500 \mathrm{cal}, 50^{\circ} \mathrm{C}\)
2 \(1000 \mathrm{cal}, 100^{\circ} \mathrm{C}\)
3 \(1500 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
4 \(1000 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
Explanation:
c Since specific heat \(=0.6 \mathrm{k}\) cali \(\mathrm{kg}{ }^{\circ} \mathrm{C}\) \(=0.6\) callgm \(^{\circ} \mathrm{C}\) From graph it is clear that in a minute that temperature is raised from \(0^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\). \(\Rightarrow\) Heat required for a minute \(=50 \times 0.6 \times 50\) \[ =1500 \mathrm{cal} . \] Also from graph, Bioling point of wax is \(200^{\circ} \mathrm{C}\)
b \[ |\overrightarrow{\mathrm{C}}|^2+|\overrightarrow{\mathrm{D}}|^2=2|\overrightarrow{\mathrm{~A}}|^2+2|\overrightarrow{\mathrm{~B}}|^2 \]
**NCERT-72**
TEST SERIES (PHYSICS FST)
266634
Heat required to increase the temperature of an ideal gas is 30 jule at constant volume. The heat required to increase the temperature in same amount for same sample of gas at constant pressure will be:
1 30 doule
2 18 Joule
3 50 Joule
4 Zero
Explanation:
c \[ \frac{Q_p}{Q_V}=\frac{\pi C_p \Delta T}{\pi C_\psi \Delta T}=\gamma \]
**NCERT-120**
TEST SERIES (PHYSICS FST)
266649
Velocity of a body is expressed as \(V=G^a \mathbf{m b}^b R^c\) where \(G\) is universal gravitational constant, \(M\) is mass and R is radius. Then values of \(a, b, c\) is respectively:
266650
A student takes 50 gm wax (specific heat \(=0.6\) kcal \(/ \mathrm{kg}^{\circ} \mathrm{C}\) ) and heats it till it boils. The graph between temperature and time is as follows. Heat supplied to the wax per minute and boiling point are respectively.
1 \(500 \mathrm{cal}, 50^{\circ} \mathrm{C}\)
2 \(1000 \mathrm{cal}, 100^{\circ} \mathrm{C}\)
3 \(1500 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
4 \(1000 \mathrm{cal}, 200^{\circ} \mathrm{C}\)
Explanation:
c Since specific heat \(=0.6 \mathrm{k}\) cali \(\mathrm{kg}{ }^{\circ} \mathrm{C}\) \(=0.6\) callgm \(^{\circ} \mathrm{C}\) From graph it is clear that in a minute that temperature is raised from \(0^{\circ} \mathrm{C}\) to \(50^{\circ} \mathrm{C}\). \(\Rightarrow\) Heat required for a minute \(=50 \times 0.6 \times 50\) \[ =1500 \mathrm{cal} . \] Also from graph, Bioling point of wax is \(200^{\circ} \mathrm{C}\)