263993

1

2

3

4

264008 The equilibrium constant for the reaction ${\mathrm{H}}_2(\mathrm{g})+{\mathbf{I}}_2(\mathrm{g})\rightleftharpoons 2\mathrm{HI}(\mathrm{g})$ is 74 . If the volume of the container is reduced to half of the original volume, the value of the equilibrium constant will be:

263993

1

2

3

4