263986
The hybridisation of \(\left[\mathrm{CoF}_4\right]^{3-}\) is:
1 \(s p^3 d^2\)
2 \(d^2 s p^3\)
3 \(s \mathrm{p}^3\)
4 \(d s p^2\)
Explanation:
a \(s p^3 \mathrm{~d}^2\)
**NCERT-XII-I-129**
TEST SERIES (CHEMISTRY FST)
263987
The atomic number 114 belongs to:
1 Halogens
2 C family
3 Noble gas
4 B family
Explanation:
b
**NCERT-XI-I-80**
TEST SERIES (CHEMISTRY FST)
263988
\(\mathrm{R}-\mathrm{Rr} \xrightarrow{\mathrm{NaCN}} X \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\mathrm{DIBAL}-\mathrm{H}} \mathrm{Y}\), Compound \(Y\) is:
1 An aldehyde
2 Analcohol
3 An ether
4 An ester
Explanation:
a \(\mathrm{R}-\mathrm{Br} \xrightarrow{\mathrm{NaCN}} \mathrm{R}-\mathrm{CN} \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\stackrel{\mathrm{DiBAL}-\mathrm{H}}{\longrightarrow}} \mathrm{R}-\mathrm{CHO}\)
**NCERT-XII-II-164**
TEST SERIES (CHEMISTRY FST)
263989
Mass of \(11.2 \mathrm{~L}^{-} \mathrm{NH}_3\) gas at STP is
1 0.5 g
2 4.5 g
3 6.75 g
4 8.5 g
Explanation:
d At STP \(11.2 \mathrm{LNH}_3=0.5\) mole \(\mathrm{NH}_3=8.5 \mathrm{~g} \mathrm{NH}_3\)
263986
The hybridisation of \(\left[\mathrm{CoF}_4\right]^{3-}\) is:
1 \(s p^3 d^2\)
2 \(d^2 s p^3\)
3 \(s \mathrm{p}^3\)
4 \(d s p^2\)
Explanation:
a \(s p^3 \mathrm{~d}^2\)
**NCERT-XII-I-129**
TEST SERIES (CHEMISTRY FST)
263987
The atomic number 114 belongs to:
1 Halogens
2 C family
3 Noble gas
4 B family
Explanation:
b
**NCERT-XI-I-80**
TEST SERIES (CHEMISTRY FST)
263988
\(\mathrm{R}-\mathrm{Rr} \xrightarrow{\mathrm{NaCN}} X \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\mathrm{DIBAL}-\mathrm{H}} \mathrm{Y}\), Compound \(Y\) is:
1 An aldehyde
2 Analcohol
3 An ether
4 An ester
Explanation:
a \(\mathrm{R}-\mathrm{Br} \xrightarrow{\mathrm{NaCN}} \mathrm{R}-\mathrm{CN} \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\stackrel{\mathrm{DiBAL}-\mathrm{H}}{\longrightarrow}} \mathrm{R}-\mathrm{CHO}\)
**NCERT-XII-II-164**
TEST SERIES (CHEMISTRY FST)
263989
Mass of \(11.2 \mathrm{~L}^{-} \mathrm{NH}_3\) gas at STP is
1 0.5 g
2 4.5 g
3 6.75 g
4 8.5 g
Explanation:
d At STP \(11.2 \mathrm{LNH}_3=0.5\) mole \(\mathrm{NH}_3=8.5 \mathrm{~g} \mathrm{NH}_3\)
263986
The hybridisation of \(\left[\mathrm{CoF}_4\right]^{3-}\) is:
1 \(s p^3 d^2\)
2 \(d^2 s p^3\)
3 \(s \mathrm{p}^3\)
4 \(d s p^2\)
Explanation:
a \(s p^3 \mathrm{~d}^2\)
**NCERT-XII-I-129**
TEST SERIES (CHEMISTRY FST)
263987
The atomic number 114 belongs to:
1 Halogens
2 C family
3 Noble gas
4 B family
Explanation:
b
**NCERT-XI-I-80**
TEST SERIES (CHEMISTRY FST)
263988
\(\mathrm{R}-\mathrm{Rr} \xrightarrow{\mathrm{NaCN}} X \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\mathrm{DIBAL}-\mathrm{H}} \mathrm{Y}\), Compound \(Y\) is:
1 An aldehyde
2 Analcohol
3 An ether
4 An ester
Explanation:
a \(\mathrm{R}-\mathrm{Br} \xrightarrow{\mathrm{NaCN}} \mathrm{R}-\mathrm{CN} \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\stackrel{\mathrm{DiBAL}-\mathrm{H}}{\longrightarrow}} \mathrm{R}-\mathrm{CHO}\)
**NCERT-XII-II-164**
TEST SERIES (CHEMISTRY FST)
263989
Mass of \(11.2 \mathrm{~L}^{-} \mathrm{NH}_3\) gas at STP is
1 0.5 g
2 4.5 g
3 6.75 g
4 8.5 g
Explanation:
d At STP \(11.2 \mathrm{LNH}_3=0.5\) mole \(\mathrm{NH}_3=8.5 \mathrm{~g} \mathrm{NH}_3\)
263986
The hybridisation of \(\left[\mathrm{CoF}_4\right]^{3-}\) is:
1 \(s p^3 d^2\)
2 \(d^2 s p^3\)
3 \(s \mathrm{p}^3\)
4 \(d s p^2\)
Explanation:
a \(s p^3 \mathrm{~d}^2\)
**NCERT-XII-I-129**
TEST SERIES (CHEMISTRY FST)
263987
The atomic number 114 belongs to:
1 Halogens
2 C family
3 Noble gas
4 B family
Explanation:
b
**NCERT-XI-I-80**
TEST SERIES (CHEMISTRY FST)
263988
\(\mathrm{R}-\mathrm{Rr} \xrightarrow{\mathrm{NaCN}} X \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\mathrm{DIBAL}-\mathrm{H}} \mathrm{Y}\), Compound \(Y\) is:
1 An aldehyde
2 Analcohol
3 An ether
4 An ester
Explanation:
a \(\mathrm{R}-\mathrm{Br} \xrightarrow{\mathrm{NaCN}} \mathrm{R}-\mathrm{CN} \xrightarrow[\mathrm{H}_2 \mathrm{O}]{\stackrel{\mathrm{DiBAL}-\mathrm{H}}{\longrightarrow}} \mathrm{R}-\mathrm{CHO}\)
**NCERT-XII-II-164**
TEST SERIES (CHEMISTRY FST)
263989
Mass of \(11.2 \mathrm{~L}^{-} \mathrm{NH}_3\) gas at STP is
1 0.5 g
2 4.5 g
3 6.75 g
4 8.5 g
Explanation:
d At STP \(11.2 \mathrm{LNH}_3=0.5\) mole \(\mathrm{NH}_3=8.5 \mathrm{~g} \mathrm{NH}_3\)