NEET Test Series from KOTA - 10 Papers In MS WORD
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TEST SERIES (PHYSICS FST)
263818
A particle of mass \(m\) moving with velocity \(v\) north wards, collides with another particle of mass m moving with velocity v east wards. After the collision the two particles coalesce. The velocity of the new particle is :
1 \(\sqrt{2}\) v north -east
2 \(\frac{v}{\sqrt{2}}\) north - east
3 2 v north east
4 \(\frac{v}{2}\) north -east
Explanation:
b \( m v \hat{i}+m v \hat{j}=2 m \overrightarrow{v^{\prime}}\) or, \(m v \sqrt{2}=2 m v^{\prime}\) or, \(v^{\prime}=\frac{v \sqrt{2}}{2}=\frac{v}{\sqrt{2}}\) north - east
NCERT-XI-I-83
TEST SERIES (PHYSICS FST)
263819
An electric field is applied to a semiconductor. Let the number of charge carriers be \(n\) and the average drift speed be v . If the temperature is increased-
1 both \(n\) and \(v\) will increased
2 \(\pi\) will increased but \(v\) will decreased
3 v will increassed but \(n\) will decreased
4 both \(n\) and \(v\) will decrease
Explanation:
a 11.2 lit \(\mathrm{H}_2=\mathrm{N}_{\mathrm{g}} / 2\) molecule
NCERT-XII-II-335
TEST SERIES (PHYSICS FST)
263820
An electric field \(E=(20 \hat{i}+25 \hat{j})\) exist in space . If the potential at the origin is zero, then the potential at point \((2 \mathrm{~m}, 4 \mathrm{~m})\) is :
1 130 wolt
2 -130 wolt
3 140 wolt
4 -140 wolt
Explanation:
d \[ \begin{aligned} & E=-\frac{d V}{d x} \\ & d V=-E d x \\ & V=-\int E d x \\ & V x=-20(2-0)=-40 \\ & V y=-25(4-0)=-100 \\ & \therefore V=-40-100=-140 \end{aligned} \]
NCERT-XII-I-55
TEST SERIES (PHYSICS FST)
263821
The force between two short electric dipoles separated by a distance r varies as:
1 \(\mathrm{r}^{-4}\)
2 \(\mathrm{r}^{-2}\)
3 \(\mathrm{r}^2\)
4 \(\Gamma^4\)
Explanation:
a \[ F=\frac{1}{4 \pi \varepsilon_0} \frac{6 p_1 p_2}{r^4} \] (force between two short electric dipoles is) \[ s o F \propto \frac{1}{r^4} \] \(\mathrm{F}_{\mathrm{Cc}}{ }^{+4}\)
263818
A particle of mass \(m\) moving with velocity \(v\) north wards, collides with another particle of mass m moving with velocity v east wards. After the collision the two particles coalesce. The velocity of the new particle is :
1 \(\sqrt{2}\) v north -east
2 \(\frac{v}{\sqrt{2}}\) north - east
3 2 v north east
4 \(\frac{v}{2}\) north -east
Explanation:
b \( m v \hat{i}+m v \hat{j}=2 m \overrightarrow{v^{\prime}}\) or, \(m v \sqrt{2}=2 m v^{\prime}\) or, \(v^{\prime}=\frac{v \sqrt{2}}{2}=\frac{v}{\sqrt{2}}\) north - east
NCERT-XI-I-83
TEST SERIES (PHYSICS FST)
263819
An electric field is applied to a semiconductor. Let the number of charge carriers be \(n\) and the average drift speed be v . If the temperature is increased-
1 both \(n\) and \(v\) will increased
2 \(\pi\) will increased but \(v\) will decreased
3 v will increassed but \(n\) will decreased
4 both \(n\) and \(v\) will decrease
Explanation:
a 11.2 lit \(\mathrm{H}_2=\mathrm{N}_{\mathrm{g}} / 2\) molecule
NCERT-XII-II-335
TEST SERIES (PHYSICS FST)
263820
An electric field \(E=(20 \hat{i}+25 \hat{j})\) exist in space . If the potential at the origin is zero, then the potential at point \((2 \mathrm{~m}, 4 \mathrm{~m})\) is :
1 130 wolt
2 -130 wolt
3 140 wolt
4 -140 wolt
Explanation:
d \[ \begin{aligned} & E=-\frac{d V}{d x} \\ & d V=-E d x \\ & V=-\int E d x \\ & V x=-20(2-0)=-40 \\ & V y=-25(4-0)=-100 \\ & \therefore V=-40-100=-140 \end{aligned} \]
NCERT-XII-I-55
TEST SERIES (PHYSICS FST)
263821
The force between two short electric dipoles separated by a distance r varies as:
1 \(\mathrm{r}^{-4}\)
2 \(\mathrm{r}^{-2}\)
3 \(\mathrm{r}^2\)
4 \(\Gamma^4\)
Explanation:
a \[ F=\frac{1}{4 \pi \varepsilon_0} \frac{6 p_1 p_2}{r^4} \] (force between two short electric dipoles is) \[ s o F \propto \frac{1}{r^4} \] \(\mathrm{F}_{\mathrm{Cc}}{ }^{+4}\)
263818
A particle of mass \(m\) moving with velocity \(v\) north wards, collides with another particle of mass m moving with velocity v east wards. After the collision the two particles coalesce. The velocity of the new particle is :
1 \(\sqrt{2}\) v north -east
2 \(\frac{v}{\sqrt{2}}\) north - east
3 2 v north east
4 \(\frac{v}{2}\) north -east
Explanation:
b \( m v \hat{i}+m v \hat{j}=2 m \overrightarrow{v^{\prime}}\) or, \(m v \sqrt{2}=2 m v^{\prime}\) or, \(v^{\prime}=\frac{v \sqrt{2}}{2}=\frac{v}{\sqrt{2}}\) north - east
NCERT-XI-I-83
TEST SERIES (PHYSICS FST)
263819
An electric field is applied to a semiconductor. Let the number of charge carriers be \(n\) and the average drift speed be v . If the temperature is increased-
1 both \(n\) and \(v\) will increased
2 \(\pi\) will increased but \(v\) will decreased
3 v will increassed but \(n\) will decreased
4 both \(n\) and \(v\) will decrease
Explanation:
a 11.2 lit \(\mathrm{H}_2=\mathrm{N}_{\mathrm{g}} / 2\) molecule
NCERT-XII-II-335
TEST SERIES (PHYSICS FST)
263820
An electric field \(E=(20 \hat{i}+25 \hat{j})\) exist in space . If the potential at the origin is zero, then the potential at point \((2 \mathrm{~m}, 4 \mathrm{~m})\) is :
1 130 wolt
2 -130 wolt
3 140 wolt
4 -140 wolt
Explanation:
d \[ \begin{aligned} & E=-\frac{d V}{d x} \\ & d V=-E d x \\ & V=-\int E d x \\ & V x=-20(2-0)=-40 \\ & V y=-25(4-0)=-100 \\ & \therefore V=-40-100=-140 \end{aligned} \]
NCERT-XII-I-55
TEST SERIES (PHYSICS FST)
263821
The force between two short electric dipoles separated by a distance r varies as:
1 \(\mathrm{r}^{-4}\)
2 \(\mathrm{r}^{-2}\)
3 \(\mathrm{r}^2\)
4 \(\Gamma^4\)
Explanation:
a \[ F=\frac{1}{4 \pi \varepsilon_0} \frac{6 p_1 p_2}{r^4} \] (force between two short electric dipoles is) \[ s o F \propto \frac{1}{r^4} \] \(\mathrm{F}_{\mathrm{Cc}}{ }^{+4}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
TEST SERIES (PHYSICS FST)
263818
A particle of mass \(m\) moving with velocity \(v\) north wards, collides with another particle of mass m moving with velocity v east wards. After the collision the two particles coalesce. The velocity of the new particle is :
1 \(\sqrt{2}\) v north -east
2 \(\frac{v}{\sqrt{2}}\) north - east
3 2 v north east
4 \(\frac{v}{2}\) north -east
Explanation:
b \( m v \hat{i}+m v \hat{j}=2 m \overrightarrow{v^{\prime}}\) or, \(m v \sqrt{2}=2 m v^{\prime}\) or, \(v^{\prime}=\frac{v \sqrt{2}}{2}=\frac{v}{\sqrt{2}}\) north - east
NCERT-XI-I-83
TEST SERIES (PHYSICS FST)
263819
An electric field is applied to a semiconductor. Let the number of charge carriers be \(n\) and the average drift speed be v . If the temperature is increased-
1 both \(n\) and \(v\) will increased
2 \(\pi\) will increased but \(v\) will decreased
3 v will increassed but \(n\) will decreased
4 both \(n\) and \(v\) will decrease
Explanation:
a 11.2 lit \(\mathrm{H}_2=\mathrm{N}_{\mathrm{g}} / 2\) molecule
NCERT-XII-II-335
TEST SERIES (PHYSICS FST)
263820
An electric field \(E=(20 \hat{i}+25 \hat{j})\) exist in space . If the potential at the origin is zero, then the potential at point \((2 \mathrm{~m}, 4 \mathrm{~m})\) is :
1 130 wolt
2 -130 wolt
3 140 wolt
4 -140 wolt
Explanation:
d \[ \begin{aligned} & E=-\frac{d V}{d x} \\ & d V=-E d x \\ & V=-\int E d x \\ & V x=-20(2-0)=-40 \\ & V y=-25(4-0)=-100 \\ & \therefore V=-40-100=-140 \end{aligned} \]
NCERT-XII-I-55
TEST SERIES (PHYSICS FST)
263821
The force between two short electric dipoles separated by a distance r varies as:
1 \(\mathrm{r}^{-4}\)
2 \(\mathrm{r}^{-2}\)
3 \(\mathrm{r}^2\)
4 \(\Gamma^4\)
Explanation:
a \[ F=\frac{1}{4 \pi \varepsilon_0} \frac{6 p_1 p_2}{r^4} \] (force between two short electric dipoles is) \[ s o F \propto \frac{1}{r^4} \] \(\mathrm{F}_{\mathrm{Cc}}{ }^{+4}\)
