The compound which does not satisfy these two condition will not be exhibit geometrical isomerism 1- These should be restricted rotation around carbon double bond 2- The substituent attached to alkene must be different i.e. If compound satisfy these condition then it only exhibit geometrical isomer.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232237
The chirality of the compound
1 $\mathrm{R}$
2 $\mathrm{S}$
3 $\mathrm{Z}$
4 $E$
Explanation:
Chirality of a molecule is given by due to presence of Asymmetric center. Asymmetric center - An atom having $\mathrm{sp}^{3}$ hybridisation and attached to four different group or an atom. It is also known as chiral center. $\mathrm{R}$ configuration is come.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232241
The following compound differ in
1 configuration
2 conformation
3 structure
4 chirality
Explanation:
The following differ compound structure Far configuration it must have follow condition of geometrical isomer. In conformation it must have rotation about $\mathrm{C}-\mathrm{C}$ single bond. To show chiarality in compound it must have asymmetric carbon. So from above explanation only (c) option is correct.
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232243
Example of geometrical isomerism is
1 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond.
2 2-butene- It show geometrical isomerism
3 butanal- It also does not have restricted rotation
4 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
Explanation:
Compound to show geometrical isomerism it must have restricted rotation around carbon- carbon double bond and substituent attached to double bond will be different like this (a.) 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond. (b.) 2-butene- It show geometrical isomerism (c.) butanal- It also does not have restricted rotation (d.) 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
The compound which does not satisfy these two condition will not be exhibit geometrical isomerism 1- These should be restricted rotation around carbon double bond 2- The substituent attached to alkene must be different i.e. If compound satisfy these condition then it only exhibit geometrical isomer.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232237
The chirality of the compound
1 $\mathrm{R}$
2 $\mathrm{S}$
3 $\mathrm{Z}$
4 $E$
Explanation:
Chirality of a molecule is given by due to presence of Asymmetric center. Asymmetric center - An atom having $\mathrm{sp}^{3}$ hybridisation and attached to four different group or an atom. It is also known as chiral center. $\mathrm{R}$ configuration is come.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232241
The following compound differ in
1 configuration
2 conformation
3 structure
4 chirality
Explanation:
The following differ compound structure Far configuration it must have follow condition of geometrical isomer. In conformation it must have rotation about $\mathrm{C}-\mathrm{C}$ single bond. To show chiarality in compound it must have asymmetric carbon. So from above explanation only (c) option is correct.
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232243
Example of geometrical isomerism is
1 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond.
2 2-butene- It show geometrical isomerism
3 butanal- It also does not have restricted rotation
4 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
Explanation:
Compound to show geometrical isomerism it must have restricted rotation around carbon- carbon double bond and substituent attached to double bond will be different like this (a.) 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond. (b.) 2-butene- It show geometrical isomerism (c.) butanal- It also does not have restricted rotation (d.) 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
The compound which does not satisfy these two condition will not be exhibit geometrical isomerism 1- These should be restricted rotation around carbon double bond 2- The substituent attached to alkene must be different i.e. If compound satisfy these condition then it only exhibit geometrical isomer.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232237
The chirality of the compound
1 $\mathrm{R}$
2 $\mathrm{S}$
3 $\mathrm{Z}$
4 $E$
Explanation:
Chirality of a molecule is given by due to presence of Asymmetric center. Asymmetric center - An atom having $\mathrm{sp}^{3}$ hybridisation and attached to four different group or an atom. It is also known as chiral center. $\mathrm{R}$ configuration is come.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232241
The following compound differ in
1 configuration
2 conformation
3 structure
4 chirality
Explanation:
The following differ compound structure Far configuration it must have follow condition of geometrical isomer. In conformation it must have rotation about $\mathrm{C}-\mathrm{C}$ single bond. To show chiarality in compound it must have asymmetric carbon. So from above explanation only (c) option is correct.
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232243
Example of geometrical isomerism is
1 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond.
2 2-butene- It show geometrical isomerism
3 butanal- It also does not have restricted rotation
4 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
Explanation:
Compound to show geometrical isomerism it must have restricted rotation around carbon- carbon double bond and substituent attached to double bond will be different like this (a.) 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond. (b.) 2-butene- It show geometrical isomerism (c.) butanal- It also does not have restricted rotation (d.) 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
The compound which does not satisfy these two condition will not be exhibit geometrical isomerism 1- These should be restricted rotation around carbon double bond 2- The substituent attached to alkene must be different i.e. If compound satisfy these condition then it only exhibit geometrical isomer.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232237
The chirality of the compound
1 $\mathrm{R}$
2 $\mathrm{S}$
3 $\mathrm{Z}$
4 $E$
Explanation:
Chirality of a molecule is given by due to presence of Asymmetric center. Asymmetric center - An atom having $\mathrm{sp}^{3}$ hybridisation and attached to four different group or an atom. It is also known as chiral center. $\mathrm{R}$ configuration is come.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232241
The following compound differ in
1 configuration
2 conformation
3 structure
4 chirality
Explanation:
The following differ compound structure Far configuration it must have follow condition of geometrical isomer. In conformation it must have rotation about $\mathrm{C}-\mathrm{C}$ single bond. To show chiarality in compound it must have asymmetric carbon. So from above explanation only (c) option is correct.
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232243
Example of geometrical isomerism is
1 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond.
2 2-butene- It show geometrical isomerism
3 butanal- It also does not have restricted rotation
4 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
Explanation:
Compound to show geometrical isomerism it must have restricted rotation around carbon- carbon double bond and substituent attached to double bond will be different like this (a.) 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond. (b.) 2-butene- It show geometrical isomerism (c.) butanal- It also does not have restricted rotation (d.) 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
The compound which does not satisfy these two condition will not be exhibit geometrical isomerism 1- These should be restricted rotation around carbon double bond 2- The substituent attached to alkene must be different i.e. If compound satisfy these condition then it only exhibit geometrical isomer.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232237
The chirality of the compound
1 $\mathrm{R}$
2 $\mathrm{S}$
3 $\mathrm{Z}$
4 $E$
Explanation:
Chirality of a molecule is given by due to presence of Asymmetric center. Asymmetric center - An atom having $\mathrm{sp}^{3}$ hybridisation and attached to four different group or an atom. It is also known as chiral center. $\mathrm{R}$ configuration is come.
UPTU/ UPSEE-2010
GENERAL ORGANIC CHEMISTRY
232241
The following compound differ in
1 configuration
2 conformation
3 structure
4 chirality
Explanation:
The following differ compound structure Far configuration it must have follow condition of geometrical isomer. In conformation it must have rotation about $\mathrm{C}-\mathrm{C}$ single bond. To show chiarality in compound it must have asymmetric carbon. So from above explanation only (c) option is correct.
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232243
Example of geometrical isomerism is
1 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond.
2 2-butene- It show geometrical isomerism
3 butanal- It also does not have restricted rotation
4 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer
Explanation:
Compound to show geometrical isomerism it must have restricted rotation around carbon- carbon double bond and substituent attached to double bond will be different like this (a.) 2-butanol- $\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}$-OH. It does not have restricted rotation around double bond. (b.) 2-butene- It show geometrical isomerism (c.) butanal- It also does not have restricted rotation (d.) 2 butyne- $\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}$ It has triple bond so it does not show geometrical isomer