In the given structure one of the carbon atom, along the double bond has identical group (methyl), hence it cannot show geometrical isomerism. Tautomerism is not possible because of the absence of $\mathrm{CO}$ group. It shows optical isomerism because it has chiral $\mathrm{C}$ atom with four different groups $\mathrm{H}, \mathrm{CH}_{3}, \mathrm{COOH}$ and $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CH}$, which consist of at least one assemetric carbon atom that is capable of showing the phenomenon of optical isomerism.
UPTU/ UPSEE-2015
GENERAL ORGANIC CHEMISTRY
232218
Which of the following is optically active molecule?
1
2
3
4
Explanation:
In the given molecule only those molecule is optically active which does not have plane of symmetry center of symmetry and axis of symmetry and molecule does not have super imposable mirror image is called optically active molecule. having plane of symmetry It also have plane of symmetry It does not have plane of symmetry so it is optically, active. It also have plane of symmetry. In compound (a) (b) and (d) have plane of symmetry with superimposable mirror image. So, it is optically inactive while in option (c) it does not have plane of symmetry so it forms non-superimposable mirror image which is optically active.
UPTU/ UPSEE-2018]
GENERAL ORGANIC CHEMISTRY
232219
Which of the following is a meso compound?
1 Cis-1,3-dimethylcyclohexane
2 Trans-1,3-dimethylcyclohexane
3 Cis-1,4-dimethylcyclohexane
4 Trans-1,4-dimethylcyclohexane
Explanation:
Cis, 1, 3 dimethyl cyclohexane In case of 1,3 dimethyl cyclohexane two cis and trans chair conformation are possible The (e, e) and (a, a) forms are conformational isomer is interconvertible. In cis isomer, it has plane of symmetry and chiral. Hence, it is meso-compound.
UPTU/ UPSEE-2017
GENERAL ORGANIC CHEMISTRY
232222
Which of the following molecules is optically active?
1 (I) and (III)
2 (II) and (III)
3 (I) ,(II) and (III)
4 (I) and (II)
Explanation:
(A) : (i) and (iii) have chiral carbon atom in their stretcher while (ii) have plane of symmetry. An imaginary plane passing through a molecule bisecting in two equal parts which one is mirror image to each other.
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GENERAL ORGANIC CHEMISTRY
232227
The following compound can exhibit
1 geometrical isomerism
2 geometrical and optical isomerism
3 optical isomerism
4 tautomerism
Explanation:
In the given structure one of the carbon atom, along the double bond has identical group (methyl), hence it cannot show geometrical isomerism. Tautomerism is not possible because of the absence of $\mathrm{CO}$ group. It shows optical isomerism because it has chiral $\mathrm{C}$ atom with four different groups $\mathrm{H}, \mathrm{CH}_{3}, \mathrm{COOH}$ and $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CH}$, which consist of at least one assemetric carbon atom that is capable of showing the phenomenon of optical isomerism.
UPTU/ UPSEE-2015
GENERAL ORGANIC CHEMISTRY
232218
Which of the following is optically active molecule?
1
2
3
4
Explanation:
In the given molecule only those molecule is optically active which does not have plane of symmetry center of symmetry and axis of symmetry and molecule does not have super imposable mirror image is called optically active molecule. having plane of symmetry It also have plane of symmetry It does not have plane of symmetry so it is optically, active. It also have plane of symmetry. In compound (a) (b) and (d) have plane of symmetry with superimposable mirror image. So, it is optically inactive while in option (c) it does not have plane of symmetry so it forms non-superimposable mirror image which is optically active.
UPTU/ UPSEE-2018]
GENERAL ORGANIC CHEMISTRY
232219
Which of the following is a meso compound?
1 Cis-1,3-dimethylcyclohexane
2 Trans-1,3-dimethylcyclohexane
3 Cis-1,4-dimethylcyclohexane
4 Trans-1,4-dimethylcyclohexane
Explanation:
Cis, 1, 3 dimethyl cyclohexane In case of 1,3 dimethyl cyclohexane two cis and trans chair conformation are possible The (e, e) and (a, a) forms are conformational isomer is interconvertible. In cis isomer, it has plane of symmetry and chiral. Hence, it is meso-compound.
UPTU/ UPSEE-2017
GENERAL ORGANIC CHEMISTRY
232222
Which of the following molecules is optically active?
1 (I) and (III)
2 (II) and (III)
3 (I) ,(II) and (III)
4 (I) and (II)
Explanation:
(A) : (i) and (iii) have chiral carbon atom in their stretcher while (ii) have plane of symmetry. An imaginary plane passing through a molecule bisecting in two equal parts which one is mirror image to each other.
In the given structure one of the carbon atom, along the double bond has identical group (methyl), hence it cannot show geometrical isomerism. Tautomerism is not possible because of the absence of $\mathrm{CO}$ group. It shows optical isomerism because it has chiral $\mathrm{C}$ atom with four different groups $\mathrm{H}, \mathrm{CH}_{3}, \mathrm{COOH}$ and $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CH}$, which consist of at least one assemetric carbon atom that is capable of showing the phenomenon of optical isomerism.
UPTU/ UPSEE-2015
GENERAL ORGANIC CHEMISTRY
232218
Which of the following is optically active molecule?
1
2
3
4
Explanation:
In the given molecule only those molecule is optically active which does not have plane of symmetry center of symmetry and axis of symmetry and molecule does not have super imposable mirror image is called optically active molecule. having plane of symmetry It also have plane of symmetry It does not have plane of symmetry so it is optically, active. It also have plane of symmetry. In compound (a) (b) and (d) have plane of symmetry with superimposable mirror image. So, it is optically inactive while in option (c) it does not have plane of symmetry so it forms non-superimposable mirror image which is optically active.
UPTU/ UPSEE-2018]
GENERAL ORGANIC CHEMISTRY
232219
Which of the following is a meso compound?
1 Cis-1,3-dimethylcyclohexane
2 Trans-1,3-dimethylcyclohexane
3 Cis-1,4-dimethylcyclohexane
4 Trans-1,4-dimethylcyclohexane
Explanation:
Cis, 1, 3 dimethyl cyclohexane In case of 1,3 dimethyl cyclohexane two cis and trans chair conformation are possible The (e, e) and (a, a) forms are conformational isomer is interconvertible. In cis isomer, it has plane of symmetry and chiral. Hence, it is meso-compound.
UPTU/ UPSEE-2017
GENERAL ORGANIC CHEMISTRY
232222
Which of the following molecules is optically active?
1 (I) and (III)
2 (II) and (III)
3 (I) ,(II) and (III)
4 (I) and (II)
Explanation:
(A) : (i) and (iii) have chiral carbon atom in their stretcher while (ii) have plane of symmetry. An imaginary plane passing through a molecule bisecting in two equal parts which one is mirror image to each other.
In the given structure one of the carbon atom, along the double bond has identical group (methyl), hence it cannot show geometrical isomerism. Tautomerism is not possible because of the absence of $\mathrm{CO}$ group. It shows optical isomerism because it has chiral $\mathrm{C}$ atom with four different groups $\mathrm{H}, \mathrm{CH}_{3}, \mathrm{COOH}$ and $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CH}$, which consist of at least one assemetric carbon atom that is capable of showing the phenomenon of optical isomerism.
UPTU/ UPSEE-2015
GENERAL ORGANIC CHEMISTRY
232218
Which of the following is optically active molecule?
1
2
3
4
Explanation:
In the given molecule only those molecule is optically active which does not have plane of symmetry center of symmetry and axis of symmetry and molecule does not have super imposable mirror image is called optically active molecule. having plane of symmetry It also have plane of symmetry It does not have plane of symmetry so it is optically, active. It also have plane of symmetry. In compound (a) (b) and (d) have plane of symmetry with superimposable mirror image. So, it is optically inactive while in option (c) it does not have plane of symmetry so it forms non-superimposable mirror image which is optically active.
UPTU/ UPSEE-2018]
GENERAL ORGANIC CHEMISTRY
232219
Which of the following is a meso compound?
1 Cis-1,3-dimethylcyclohexane
2 Trans-1,3-dimethylcyclohexane
3 Cis-1,4-dimethylcyclohexane
4 Trans-1,4-dimethylcyclohexane
Explanation:
Cis, 1, 3 dimethyl cyclohexane In case of 1,3 dimethyl cyclohexane two cis and trans chair conformation are possible The (e, e) and (a, a) forms are conformational isomer is interconvertible. In cis isomer, it has plane of symmetry and chiral. Hence, it is meso-compound.
UPTU/ UPSEE-2017
GENERAL ORGANIC CHEMISTRY
232222
Which of the following molecules is optically active?
1 (I) and (III)
2 (II) and (III)
3 (I) ,(II) and (III)
4 (I) and (II)
Explanation:
(A) : (i) and (iii) have chiral carbon atom in their stretcher while (ii) have plane of symmetry. An imaginary plane passing through a molecule bisecting in two equal parts which one is mirror image to each other.
