232020
The $\mathrm{Z}$ isomer among the following is
1
2
3
4
Explanation:
Z-isomer among the following is. Only option (a) h as Z-isomer If same priority group will be present on same side then the isomer is nazned as $Z$. means same side $\rightarrow$ Zussamann E- means opposite side $\rightarrow$ Entagen
AMU-2011
GENERAL ORGANIC CHEMISTRY
232032
The type of isomerism observed in benzaldoxime is-
1 optical
2 functional
3 geometrial
4 tautomerism
Explanation:
The type of isomerism observed in benzaldoxime No chiral center present no change in functional group presence of double bond but cis trans isomers not possible. Form the above observations it is clear that benzeldoxime does not show geometrical functional isomerism. So, we can say that it is simple proton transfer. So, it is show tautomerism.
BCECE-2011
GENERAL ORGANIC CHEMISTRY
232036
Number of geometrical isomers for 1, 8dichloro-octa-1,3,5,7-tetraene are-
1 10
2 9
3 8
4 12
Explanation:
(A) : $\mathrm{C} \ell-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{C} \ell$ End is same and even no. of double bond. Hence, No. of geometrical isomers $=2^{\mathrm{n}-1}+2^{\frac{\mathrm{n}}{2}-1}$ Where $\mathrm{n}=$ No. of double bond $=2^{3}+2^{1}=10$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232037
How many optical isomer will the tartaric acid show?
1 3
2 4
3 0
4 2
Explanation:
As we know that the molecule has an element of symmetry and $n$ is even. The number of double and single bonds form $\mathrm{a}=2^{\mathrm{n}-1}$ Meso form $\mathrm{m}=2^{\left(\frac{\mathrm{n}}{2}-1\right)}$ Total $a+m$ $\mathrm{n}=2$ $\mathrm{a}=2^{\mathrm{n}-1}=2^{2-1}=2^{1}$ $\mathrm{~m}=2^{1-1}=2^{0}=1$ Total $=2+1=3$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232040
In the following structures, which two forms are staggered conformations of ethane?
1 1 and 4
2 2 and 3
3 1 and 2
4 1 and 3
Explanation:
The two forms of staggered ethane is given as In this form all atoms are placed at angled $120^{\circ}$.
232020
The $\mathrm{Z}$ isomer among the following is
1
2
3
4
Explanation:
Z-isomer among the following is. Only option (a) h as Z-isomer If same priority group will be present on same side then the isomer is nazned as $Z$. means same side $\rightarrow$ Zussamann E- means opposite side $\rightarrow$ Entagen
AMU-2011
GENERAL ORGANIC CHEMISTRY
232032
The type of isomerism observed in benzaldoxime is-
1 optical
2 functional
3 geometrial
4 tautomerism
Explanation:
The type of isomerism observed in benzaldoxime No chiral center present no change in functional group presence of double bond but cis trans isomers not possible. Form the above observations it is clear that benzeldoxime does not show geometrical functional isomerism. So, we can say that it is simple proton transfer. So, it is show tautomerism.
BCECE-2011
GENERAL ORGANIC CHEMISTRY
232036
Number of geometrical isomers for 1, 8dichloro-octa-1,3,5,7-tetraene are-
1 10
2 9
3 8
4 12
Explanation:
(A) : $\mathrm{C} \ell-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{C} \ell$ End is same and even no. of double bond. Hence, No. of geometrical isomers $=2^{\mathrm{n}-1}+2^{\frac{\mathrm{n}}{2}-1}$ Where $\mathrm{n}=$ No. of double bond $=2^{3}+2^{1}=10$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232037
How many optical isomer will the tartaric acid show?
1 3
2 4
3 0
4 2
Explanation:
As we know that the molecule has an element of symmetry and $n$ is even. The number of double and single bonds form $\mathrm{a}=2^{\mathrm{n}-1}$ Meso form $\mathrm{m}=2^{\left(\frac{\mathrm{n}}{2}-1\right)}$ Total $a+m$ $\mathrm{n}=2$ $\mathrm{a}=2^{\mathrm{n}-1}=2^{2-1}=2^{1}$ $\mathrm{~m}=2^{1-1}=2^{0}=1$ Total $=2+1=3$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232040
In the following structures, which two forms are staggered conformations of ethane?
1 1 and 4
2 2 and 3
3 1 and 2
4 1 and 3
Explanation:
The two forms of staggered ethane is given as In this form all atoms are placed at angled $120^{\circ}$.
232020
The $\mathrm{Z}$ isomer among the following is
1
2
3
4
Explanation:
Z-isomer among the following is. Only option (a) h as Z-isomer If same priority group will be present on same side then the isomer is nazned as $Z$. means same side $\rightarrow$ Zussamann E- means opposite side $\rightarrow$ Entagen
AMU-2011
GENERAL ORGANIC CHEMISTRY
232032
The type of isomerism observed in benzaldoxime is-
1 optical
2 functional
3 geometrial
4 tautomerism
Explanation:
The type of isomerism observed in benzaldoxime No chiral center present no change in functional group presence of double bond but cis trans isomers not possible. Form the above observations it is clear that benzeldoxime does not show geometrical functional isomerism. So, we can say that it is simple proton transfer. So, it is show tautomerism.
BCECE-2011
GENERAL ORGANIC CHEMISTRY
232036
Number of geometrical isomers for 1, 8dichloro-octa-1,3,5,7-tetraene are-
1 10
2 9
3 8
4 12
Explanation:
(A) : $\mathrm{C} \ell-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{C} \ell$ End is same and even no. of double bond. Hence, No. of geometrical isomers $=2^{\mathrm{n}-1}+2^{\frac{\mathrm{n}}{2}-1}$ Where $\mathrm{n}=$ No. of double bond $=2^{3}+2^{1}=10$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232037
How many optical isomer will the tartaric acid show?
1 3
2 4
3 0
4 2
Explanation:
As we know that the molecule has an element of symmetry and $n$ is even. The number of double and single bonds form $\mathrm{a}=2^{\mathrm{n}-1}$ Meso form $\mathrm{m}=2^{\left(\frac{\mathrm{n}}{2}-1\right)}$ Total $a+m$ $\mathrm{n}=2$ $\mathrm{a}=2^{\mathrm{n}-1}=2^{2-1}=2^{1}$ $\mathrm{~m}=2^{1-1}=2^{0}=1$ Total $=2+1=3$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232040
In the following structures, which two forms are staggered conformations of ethane?
1 1 and 4
2 2 and 3
3 1 and 2
4 1 and 3
Explanation:
The two forms of staggered ethane is given as In this form all atoms are placed at angled $120^{\circ}$.
232020
The $\mathrm{Z}$ isomer among the following is
1
2
3
4
Explanation:
Z-isomer among the following is. Only option (a) h as Z-isomer If same priority group will be present on same side then the isomer is nazned as $Z$. means same side $\rightarrow$ Zussamann E- means opposite side $\rightarrow$ Entagen
AMU-2011
GENERAL ORGANIC CHEMISTRY
232032
The type of isomerism observed in benzaldoxime is-
1 optical
2 functional
3 geometrial
4 tautomerism
Explanation:
The type of isomerism observed in benzaldoxime No chiral center present no change in functional group presence of double bond but cis trans isomers not possible. Form the above observations it is clear that benzeldoxime does not show geometrical functional isomerism. So, we can say that it is simple proton transfer. So, it is show tautomerism.
BCECE-2011
GENERAL ORGANIC CHEMISTRY
232036
Number of geometrical isomers for 1, 8dichloro-octa-1,3,5,7-tetraene are-
1 10
2 9
3 8
4 12
Explanation:
(A) : $\mathrm{C} \ell-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{C} \ell$ End is same and even no. of double bond. Hence, No. of geometrical isomers $=2^{\mathrm{n}-1}+2^{\frac{\mathrm{n}}{2}-1}$ Where $\mathrm{n}=$ No. of double bond $=2^{3}+2^{1}=10$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232037
How many optical isomer will the tartaric acid show?
1 3
2 4
3 0
4 2
Explanation:
As we know that the molecule has an element of symmetry and $n$ is even. The number of double and single bonds form $\mathrm{a}=2^{\mathrm{n}-1}$ Meso form $\mathrm{m}=2^{\left(\frac{\mathrm{n}}{2}-1\right)}$ Total $a+m$ $\mathrm{n}=2$ $\mathrm{a}=2^{\mathrm{n}-1}=2^{2-1}=2^{1}$ $\mathrm{~m}=2^{1-1}=2^{0}=1$ Total $=2+1=3$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232040
In the following structures, which two forms are staggered conformations of ethane?
1 1 and 4
2 2 and 3
3 1 and 2
4 1 and 3
Explanation:
The two forms of staggered ethane is given as In this form all atoms are placed at angled $120^{\circ}$.
232020
The $\mathrm{Z}$ isomer among the following is
1
2
3
4
Explanation:
Z-isomer among the following is. Only option (a) h as Z-isomer If same priority group will be present on same side then the isomer is nazned as $Z$. means same side $\rightarrow$ Zussamann E- means opposite side $\rightarrow$ Entagen
AMU-2011
GENERAL ORGANIC CHEMISTRY
232032
The type of isomerism observed in benzaldoxime is-
1 optical
2 functional
3 geometrial
4 tautomerism
Explanation:
The type of isomerism observed in benzaldoxime No chiral center present no change in functional group presence of double bond but cis trans isomers not possible. Form the above observations it is clear that benzeldoxime does not show geometrical functional isomerism. So, we can say that it is simple proton transfer. So, it is show tautomerism.
BCECE-2011
GENERAL ORGANIC CHEMISTRY
232036
Number of geometrical isomers for 1, 8dichloro-octa-1,3,5,7-tetraene are-
1 10
2 9
3 8
4 12
Explanation:
(A) : $\mathrm{C} \ell-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}-\mathrm{C} \ell$ End is same and even no. of double bond. Hence, No. of geometrical isomers $=2^{\mathrm{n}-1}+2^{\frac{\mathrm{n}}{2}-1}$ Where $\mathrm{n}=$ No. of double bond $=2^{3}+2^{1}=10$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232037
How many optical isomer will the tartaric acid show?
1 3
2 4
3 0
4 2
Explanation:
As we know that the molecule has an element of symmetry and $n$ is even. The number of double and single bonds form $\mathrm{a}=2^{\mathrm{n}-1}$ Meso form $\mathrm{m}=2^{\left(\frac{\mathrm{n}}{2}-1\right)}$ Total $a+m$ $\mathrm{n}=2$ $\mathrm{a}=2^{\mathrm{n}-1}=2^{2-1}=2^{1}$ $\mathrm{~m}=2^{1-1}=2^{0}=1$ Total $=2+1=3$
BCECE-2016
GENERAL ORGANIC CHEMISTRY
232040
In the following structures, which two forms are staggered conformations of ethane?
1 1 and 4
2 2 and 3
3 1 and 2
4 1 and 3
Explanation:
The two forms of staggered ethane is given as In this form all atoms are placed at angled $120^{\circ}$.
