232195
Two possible stereo-structures of $\mathrm{CH}_{3}$ СНОНСООН, which are optically active, are called
1 atropisomers
2 enantiomers
3 mesomers
4 diastereomers
Explanation:
Two possible stereo starchier of $\mathrm{CH}_{3} \mathrm{CH}-\mathrm{O}+\mathrm{CH}_{3} \mathrm{OOH}$ It has one chiral center with non superimposable mirror image.
NEET-2015
GENERAL ORGANIC CHEMISTRY
232196
In an $S_{N} 1$ reaction on chiral centres, there is
1 inversion more than retention leading to partial racemisation
2 $100 \%$ retention
3 $100 \%$ inversion
4 $100 \%$ racemisation
Explanation:
In an $\mathrm{S}_{\mathrm{N}} 1$ reaction on chiral center there is inversion more than retention leading to racemisation. If we take an example of pure enantiomer and carry out $\mathrm{S}_{\mathrm{N}} 1$ substitution on chiral carbon the product will be racemic. This is because planer carbocation ion is obtained. The nucleophile can attack from either side of this intermediate
NEET-2015
GENERAL ORGANIC CHEMISTRY
232197
With respect to the conformers of ethane, which of the following statements is true?
1 Bond angle changes but bond length remains same.
2 Both bond angle and bond length change.
3 Both bond angle and bond length remain same.
4 Bond angle remains same but bond length changes.
Explanation:
Both bond and bond length remain same because comformer of ethane has different dihedral angle It is an interfacial angle between front carbonhydrogen and rear carbon-hydrogen bond called dihedral angle $\theta=0^{\circ}\left|120^{\circ}\right| 240^{\circ} \mid 360^{\circ} \rightarrow$ eclipsed form $\theta=60^{\circ}\left|180^{\circ}\right| 360^{\circ} \rightarrow$ staggered form.
NEET-2017
GENERAL ORGANIC CHEMISTRY
232198
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is
1 The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
2 The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
3 The staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
4 The eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has no torsional strain.
Explanation:
The Staggered conformation of ethane is more stable than eclipsed because in staggered conformation has no tersional strain. Torsional strain- It is a repulsive force due to bonded pair of electrons.
NEET-I 2016
GENERAL ORGANIC CHEMISTRY
232199
In the following the most stable conformation of n-butane is
1
2
3
4
Explanation:
The most stable conformation of n-butane is $\mathrm{b}$ molecule because in this case there is no repulsive interaction, so energy is less and stability is more and also in the case atoms are placed at an angle $180^{\circ}$. Anti/staggered form no repulsive interaction
232195
Two possible stereo-structures of $\mathrm{CH}_{3}$ СНОНСООН, which are optically active, are called
1 atropisomers
2 enantiomers
3 mesomers
4 diastereomers
Explanation:
Two possible stereo starchier of $\mathrm{CH}_{3} \mathrm{CH}-\mathrm{O}+\mathrm{CH}_{3} \mathrm{OOH}$ It has one chiral center with non superimposable mirror image.
NEET-2015
GENERAL ORGANIC CHEMISTRY
232196
In an $S_{N} 1$ reaction on chiral centres, there is
1 inversion more than retention leading to partial racemisation
2 $100 \%$ retention
3 $100 \%$ inversion
4 $100 \%$ racemisation
Explanation:
In an $\mathrm{S}_{\mathrm{N}} 1$ reaction on chiral center there is inversion more than retention leading to racemisation. If we take an example of pure enantiomer and carry out $\mathrm{S}_{\mathrm{N}} 1$ substitution on chiral carbon the product will be racemic. This is because planer carbocation ion is obtained. The nucleophile can attack from either side of this intermediate
NEET-2015
GENERAL ORGANIC CHEMISTRY
232197
With respect to the conformers of ethane, which of the following statements is true?
1 Bond angle changes but bond length remains same.
2 Both bond angle and bond length change.
3 Both bond angle and bond length remain same.
4 Bond angle remains same but bond length changes.
Explanation:
Both bond and bond length remain same because comformer of ethane has different dihedral angle It is an interfacial angle between front carbonhydrogen and rear carbon-hydrogen bond called dihedral angle $\theta=0^{\circ}\left|120^{\circ}\right| 240^{\circ} \mid 360^{\circ} \rightarrow$ eclipsed form $\theta=60^{\circ}\left|180^{\circ}\right| 360^{\circ} \rightarrow$ staggered form.
NEET-2017
GENERAL ORGANIC CHEMISTRY
232198
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is
1 The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
2 The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
3 The staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
4 The eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has no torsional strain.
Explanation:
The Staggered conformation of ethane is more stable than eclipsed because in staggered conformation has no tersional strain. Torsional strain- It is a repulsive force due to bonded pair of electrons.
NEET-I 2016
GENERAL ORGANIC CHEMISTRY
232199
In the following the most stable conformation of n-butane is
1
2
3
4
Explanation:
The most stable conformation of n-butane is $\mathrm{b}$ molecule because in this case there is no repulsive interaction, so energy is less and stability is more and also in the case atoms are placed at an angle $180^{\circ}$. Anti/staggered form no repulsive interaction
232195
Two possible stereo-structures of $\mathrm{CH}_{3}$ СНОНСООН, which are optically active, are called
1 atropisomers
2 enantiomers
3 mesomers
4 diastereomers
Explanation:
Two possible stereo starchier of $\mathrm{CH}_{3} \mathrm{CH}-\mathrm{O}+\mathrm{CH}_{3} \mathrm{OOH}$ It has one chiral center with non superimposable mirror image.
NEET-2015
GENERAL ORGANIC CHEMISTRY
232196
In an $S_{N} 1$ reaction on chiral centres, there is
1 inversion more than retention leading to partial racemisation
2 $100 \%$ retention
3 $100 \%$ inversion
4 $100 \%$ racemisation
Explanation:
In an $\mathrm{S}_{\mathrm{N}} 1$ reaction on chiral center there is inversion more than retention leading to racemisation. If we take an example of pure enantiomer and carry out $\mathrm{S}_{\mathrm{N}} 1$ substitution on chiral carbon the product will be racemic. This is because planer carbocation ion is obtained. The nucleophile can attack from either side of this intermediate
NEET-2015
GENERAL ORGANIC CHEMISTRY
232197
With respect to the conformers of ethane, which of the following statements is true?
1 Bond angle changes but bond length remains same.
2 Both bond angle and bond length change.
3 Both bond angle and bond length remain same.
4 Bond angle remains same but bond length changes.
Explanation:
Both bond and bond length remain same because comformer of ethane has different dihedral angle It is an interfacial angle between front carbonhydrogen and rear carbon-hydrogen bond called dihedral angle $\theta=0^{\circ}\left|120^{\circ}\right| 240^{\circ} \mid 360^{\circ} \rightarrow$ eclipsed form $\theta=60^{\circ}\left|180^{\circ}\right| 360^{\circ} \rightarrow$ staggered form.
NEET-2017
GENERAL ORGANIC CHEMISTRY
232198
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is
1 The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
2 The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
3 The staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
4 The eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has no torsional strain.
Explanation:
The Staggered conformation of ethane is more stable than eclipsed because in staggered conformation has no tersional strain. Torsional strain- It is a repulsive force due to bonded pair of electrons.
NEET-I 2016
GENERAL ORGANIC CHEMISTRY
232199
In the following the most stable conformation of n-butane is
1
2
3
4
Explanation:
The most stable conformation of n-butane is $\mathrm{b}$ molecule because in this case there is no repulsive interaction, so energy is less and stability is more and also in the case atoms are placed at an angle $180^{\circ}$. Anti/staggered form no repulsive interaction
232195
Two possible stereo-structures of $\mathrm{CH}_{3}$ СНОНСООН, which are optically active, are called
1 atropisomers
2 enantiomers
3 mesomers
4 diastereomers
Explanation:
Two possible stereo starchier of $\mathrm{CH}_{3} \mathrm{CH}-\mathrm{O}+\mathrm{CH}_{3} \mathrm{OOH}$ It has one chiral center with non superimposable mirror image.
NEET-2015
GENERAL ORGANIC CHEMISTRY
232196
In an $S_{N} 1$ reaction on chiral centres, there is
1 inversion more than retention leading to partial racemisation
2 $100 \%$ retention
3 $100 \%$ inversion
4 $100 \%$ racemisation
Explanation:
In an $\mathrm{S}_{\mathrm{N}} 1$ reaction on chiral center there is inversion more than retention leading to racemisation. If we take an example of pure enantiomer and carry out $\mathrm{S}_{\mathrm{N}} 1$ substitution on chiral carbon the product will be racemic. This is because planer carbocation ion is obtained. The nucleophile can attack from either side of this intermediate
NEET-2015
GENERAL ORGANIC CHEMISTRY
232197
With respect to the conformers of ethane, which of the following statements is true?
1 Bond angle changes but bond length remains same.
2 Both bond angle and bond length change.
3 Both bond angle and bond length remain same.
4 Bond angle remains same but bond length changes.
Explanation:
Both bond and bond length remain same because comformer of ethane has different dihedral angle It is an interfacial angle between front carbonhydrogen and rear carbon-hydrogen bond called dihedral angle $\theta=0^{\circ}\left|120^{\circ}\right| 240^{\circ} \mid 360^{\circ} \rightarrow$ eclipsed form $\theta=60^{\circ}\left|180^{\circ}\right| 360^{\circ} \rightarrow$ staggered form.
NEET-2017
GENERAL ORGANIC CHEMISTRY
232198
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is
1 The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
2 The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
3 The staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
4 The eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has no torsional strain.
Explanation:
The Staggered conformation of ethane is more stable than eclipsed because in staggered conformation has no tersional strain. Torsional strain- It is a repulsive force due to bonded pair of electrons.
NEET-I 2016
GENERAL ORGANIC CHEMISTRY
232199
In the following the most stable conformation of n-butane is
1
2
3
4
Explanation:
The most stable conformation of n-butane is $\mathrm{b}$ molecule because in this case there is no repulsive interaction, so energy is less and stability is more and also in the case atoms are placed at an angle $180^{\circ}$. Anti/staggered form no repulsive interaction
232195
Two possible stereo-structures of $\mathrm{CH}_{3}$ СНОНСООН, which are optically active, are called
1 atropisomers
2 enantiomers
3 mesomers
4 diastereomers
Explanation:
Two possible stereo starchier of $\mathrm{CH}_{3} \mathrm{CH}-\mathrm{O}+\mathrm{CH}_{3} \mathrm{OOH}$ It has one chiral center with non superimposable mirror image.
NEET-2015
GENERAL ORGANIC CHEMISTRY
232196
In an $S_{N} 1$ reaction on chiral centres, there is
1 inversion more than retention leading to partial racemisation
2 $100 \%$ retention
3 $100 \%$ inversion
4 $100 \%$ racemisation
Explanation:
In an $\mathrm{S}_{\mathrm{N}} 1$ reaction on chiral center there is inversion more than retention leading to racemisation. If we take an example of pure enantiomer and carry out $\mathrm{S}_{\mathrm{N}} 1$ substitution on chiral carbon the product will be racemic. This is because planer carbocation ion is obtained. The nucleophile can attack from either side of this intermediate
NEET-2015
GENERAL ORGANIC CHEMISTRY
232197
With respect to the conformers of ethane, which of the following statements is true?
1 Bond angle changes but bond length remains same.
2 Both bond angle and bond length change.
3 Both bond angle and bond length remain same.
4 Bond angle remains same but bond length changes.
Explanation:
Both bond and bond length remain same because comformer of ethane has different dihedral angle It is an interfacial angle between front carbonhydrogen and rear carbon-hydrogen bond called dihedral angle $\theta=0^{\circ}\left|120^{\circ}\right| 240^{\circ} \mid 360^{\circ} \rightarrow$ eclipsed form $\theta=60^{\circ}\left|180^{\circ}\right| 360^{\circ} \rightarrow$ staggered form.
NEET-2017
GENERAL ORGANIC CHEMISTRY
232198
The correct statement regarding the comparison of staggered and eclipsed conformations of ethane, is
1 The eclipsed conformation of ethane is more stable than staggered conformation even though the eclipsed conformation has torsional strain
2 The staggered conformation of ethane is more stable than eclipsed conformation, because staggered conformation has no torsional strain
3 The staggered conformation of ethane is less stable than eclipsed conformation, because staggered conformation has torsional strain
4 The eclipsed conformation of ethane is more stable than staggered conformation, because eclipsed conformation has no torsional strain.
Explanation:
The Staggered conformation of ethane is more stable than eclipsed because in staggered conformation has no tersional strain. Torsional strain- It is a repulsive force due to bonded pair of electrons.
NEET-I 2016
GENERAL ORGANIC CHEMISTRY
232199
In the following the most stable conformation of n-butane is
1
2
3
4
Explanation:
The most stable conformation of n-butane is $\mathrm{b}$ molecule because in this case there is no repulsive interaction, so energy is less and stability is more and also in the case atoms are placed at an angle $180^{\circ}$. Anti/staggered form no repulsive interaction
