NEET Test Series from KOTA - 10 Papers In MS WORD
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GENERAL ORGANIC CHEMISTRY
232183
Which of the following will show geometrical isomerism?
1 1-butene
2 1, 2-dibromobutene
3 Propene
4 Isobutylene
Explanation:
1,2 dibromo butene It show geometrical isomerism because it satisfy the condition of geometrical isomer in which substituent are different
Manipal 2017
GENERAL ORGANIC CHEMISTRY
232189
The number of isomers in $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$ are
1 7
2 8
3 6
4 5
Explanation:
The number of possible isomer for $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
MHT CET-2012]
GENERAL ORGANIC CHEMISTRY
232191
$\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ has a chiral centre. Which one of the following represents its $R$ configuration?
1
2
3
4
Explanation:
(B) : If lowest priority group are at horizontal line then invert naming is taken,
AIPMT -2007
GENERAL ORGANIC CHEMISTRY
232193
The minimum numbers of carbon atoms in ketones which will show chain isomerism will be
1 7
2 4
3 6
4 5
Explanation:
The minimum number of carbon required to form ketone is 5 .
232183
Which of the following will show geometrical isomerism?
1 1-butene
2 1, 2-dibromobutene
3 Propene
4 Isobutylene
Explanation:
1,2 dibromo butene It show geometrical isomerism because it satisfy the condition of geometrical isomer in which substituent are different
Manipal 2017
GENERAL ORGANIC CHEMISTRY
232189
The number of isomers in $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$ are
1 7
2 8
3 6
4 5
Explanation:
The number of possible isomer for $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
MHT CET-2012]
GENERAL ORGANIC CHEMISTRY
232191
$\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ has a chiral centre. Which one of the following represents its $R$ configuration?
1
2
3
4
Explanation:
(B) : If lowest priority group are at horizontal line then invert naming is taken,
AIPMT -2007
GENERAL ORGANIC CHEMISTRY
232193
The minimum numbers of carbon atoms in ketones which will show chain isomerism will be
1 7
2 4
3 6
4 5
Explanation:
The minimum number of carbon required to form ketone is 5 .
232183
Which of the following will show geometrical isomerism?
1 1-butene
2 1, 2-dibromobutene
3 Propene
4 Isobutylene
Explanation:
1,2 dibromo butene It show geometrical isomerism because it satisfy the condition of geometrical isomer in which substituent are different
Manipal 2017
GENERAL ORGANIC CHEMISTRY
232189
The number of isomers in $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$ are
1 7
2 8
3 6
4 5
Explanation:
The number of possible isomer for $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
MHT CET-2012]
GENERAL ORGANIC CHEMISTRY
232191
$\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ has a chiral centre. Which one of the following represents its $R$ configuration?
1
2
3
4
Explanation:
(B) : If lowest priority group are at horizontal line then invert naming is taken,
AIPMT -2007
GENERAL ORGANIC CHEMISTRY
232193
The minimum numbers of carbon atoms in ketones which will show chain isomerism will be
1 7
2 4
3 6
4 5
Explanation:
The minimum number of carbon required to form ketone is 5 .
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
GENERAL ORGANIC CHEMISTRY
232183
Which of the following will show geometrical isomerism?
1 1-butene
2 1, 2-dibromobutene
3 Propene
4 Isobutylene
Explanation:
1,2 dibromo butene It show geometrical isomerism because it satisfy the condition of geometrical isomer in which substituent are different
Manipal 2017
GENERAL ORGANIC CHEMISTRY
232189
The number of isomers in $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$ are
1 7
2 8
3 6
4 5
Explanation:
The number of possible isomer for $\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}$
MHT CET-2012]
GENERAL ORGANIC CHEMISTRY
232191
$\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2}-\mathrm{CH}_{3}$ has a chiral centre. Which one of the following represents its $R$ configuration?
1
2
3
4
Explanation:
(B) : If lowest priority group are at horizontal line then invert naming is taken,
AIPMT -2007
GENERAL ORGANIC CHEMISTRY
232193
The minimum numbers of carbon atoms in ketones which will show chain isomerism will be
1 7
2 4
3 6
4 5
Explanation:
The minimum number of carbon required to form ketone is 5 .
