QBManager

07. The p-BLOCK ELEMENTS (XII)

189348 Which of the following compound show sublimation

1

N H_{4} C l

2

C a C O_{3}

3

B a S O_{4}

4

C a H P O_{3}

Explanation:

(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., $I_{2}, N H_{4} C l$ and camphor.

07. The p-BLOCK ELEMENTS (XII)

189352 Oxidation number of As in $H_{2} A s O_{4}^{-}$ is

1

6

2

7

3

5

4

9

Explanation:

(c) Oxidation number of $A s$ in $H_{2} A s O_{4}^{-}$
$2 + x - 8 = - 1$
$x - 6 = - 1$
$x = 5$

07. The p-BLOCK ELEMENTS (XII)

189359 The element which liberates oxygen gas from water is

1

P

2

N a

3

F

4

I

Explanation:

(c) $2 H_{2} O + 2 F_{2} \to 4 H F + O_{2}$

07. The p-BLOCK ELEMENTS (XII)

188313 Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?

1

C_{6} H_{5} {NO}_{2}

2

C_{6} H_{5} N H_{2}

3

{CH}_{3} {CH}_{2} - C \equiv N

4

\begin{matrix} O \\ | | \\ N H_{2} - C - N H_{2} \end{matrix}

Explanation:

Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene $C_{6} H_{5} {NO}_{2}$ because reaction with $H_{2} {SO}_{4},$ nitrobenzene can not give ammonia.

07. The p-BLOCK ELEMENTS (XII)

188364 When chlorine water is added to a solution of $K B r$ , the solution immediately turns orange red, because

1 Chlorine is reduced to chloride ion

2 Of the formation of

B r C l

3 Bromide ion is oxidized to bromine

4 Of the formation of

B r_{3}^{-}

Explanation:

$B r_{2}$ , formed by adding chlorine water to a solution of $K B r$ , further reacts with $C l_{2}$ to form reddish yellow or orange red $B r C l$ .
$B r_{2} + C l_{2} \to 2 B r C l$

07. The p-BLOCK ELEMENTS (XII)

189348 Which of the following compound show sublimation

1

N H_{4} C l

2

C a C O_{3}

3

B a S O_{4}

4

C a H P O_{3}

Explanation:

(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., $I_{2}, N H_{4} C l$ and camphor.

07. The p-BLOCK ELEMENTS (XII)

189352 Oxidation number of As in $H_{2} A s O_{4}^{-}$ is

1

6

2

7

3

5

4

9

Explanation:

(c) Oxidation number of $A s$ in $H_{2} A s O_{4}^{-}$
$2 + x - 8 = - 1$
$x - 6 = - 1$
$x = 5$

07. The p-BLOCK ELEMENTS (XII)

189359 The element which liberates oxygen gas from water is

1

P

2

N a

3

F

4

I

Explanation:

(c) $2 H_{2} O + 2 F_{2} \to 4 H F + O_{2}$

07. The p-BLOCK ELEMENTS (XII)

188313 Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?

1

C_{6} H_{5} {NO}_{2}

2

C_{6} H_{5} N H_{2}

3

{CH}_{3} {CH}_{2} - C \equiv N

4

\begin{matrix} O \\ | | \\ N H_{2} - C - N H_{2} \end{matrix}

Explanation:

Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene $C_{6} H_{5} {NO}_{2}$ because reaction with $H_{2} {SO}_{4},$ nitrobenzene can not give ammonia.

07. The p-BLOCK ELEMENTS (XII)

188364 When chlorine water is added to a solution of $K B r$ , the solution immediately turns orange red, because

1 Chlorine is reduced to chloride ion

2 Of the formation of

B r C l

3 Bromide ion is oxidized to bromine

4 Of the formation of

B r_{3}^{-}

Explanation:

$B r_{2}$ , formed by adding chlorine water to a solution of $K B r$ , further reacts with $C l_{2}$ to form reddish yellow or orange red $B r C l$ .
$B r_{2} + C l_{2} \to 2 B r C l$

07. The p-BLOCK ELEMENTS (XII)

189348 Which of the following compound show sublimation

1

N H_{4} C l

2

C a C O_{3}

3

B a S O_{4}

4

C a H P O_{3}

Explanation:

(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., $I_{2}, N H_{4} C l$ and camphor.

07. The p-BLOCK ELEMENTS (XII)

189352 Oxidation number of As in $H_{2} A s O_{4}^{-}$ is

1

6

2

7

3

5

4

9

Explanation:

(c) Oxidation number of $A s$ in $H_{2} A s O_{4}^{-}$
$2 + x - 8 = - 1$
$x - 6 = - 1$
$x = 5$

07. The p-BLOCK ELEMENTS (XII)

189359 The element which liberates oxygen gas from water is

1

P

2

N a

3

F

4

I

Explanation:

(c) $2 H_{2} O + 2 F_{2} \to 4 H F + O_{2}$

07. The p-BLOCK ELEMENTS (XII)

188313 Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?

1

C_{6} H_{5} {NO}_{2}

2

C_{6} H_{5} N H_{2}

3

{CH}_{3} {CH}_{2} - C \equiv N

4

\begin{matrix} O \\ | | \\ N H_{2} - C - N H_{2} \end{matrix}

Explanation:

Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene $C_{6} H_{5} {NO}_{2}$ because reaction with $H_{2} {SO}_{4},$ nitrobenzene can not give ammonia.

07. The p-BLOCK ELEMENTS (XII)

188364 When chlorine water is added to a solution of $K B r$ , the solution immediately turns orange red, because

1 Chlorine is reduced to chloride ion

2 Of the formation of

B r C l

3 Bromide ion is oxidized to bromine

4 Of the formation of

B r_{3}^{-}

Explanation:

$B r_{2}$ , formed by adding chlorine water to a solution of $K B r$ , further reacts with $C l_{2}$ to form reddish yellow or orange red $B r C l$ .
$B r_{2} + C l_{2} \to 2 B r C l$

07. The p-BLOCK ELEMENTS (XII)

189348 Which of the following compound show sublimation

1

N H_{4} C l

2

C a C O_{3}

3

B a S O_{4}

4

C a H P O_{3}

Explanation:

(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., $I_{2}, N H_{4} C l$ and camphor.

07. The p-BLOCK ELEMENTS (XII)

189352 Oxidation number of As in $H_{2} A s O_{4}^{-}$ is

1

6

2

7

3

5

4

9

Explanation:

(c) Oxidation number of $A s$ in $H_{2} A s O_{4}^{-}$
$2 + x - 8 = - 1$
$x - 6 = - 1$
$x = 5$

07. The p-BLOCK ELEMENTS (XII)

189359 The element which liberates oxygen gas from water is

1

P

2

N a

3

F

4

I

Explanation:

(c) $2 H_{2} O + 2 F_{2} \to 4 H F + O_{2}$

07. The p-BLOCK ELEMENTS (XII)

188313 Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?

1

C_{6} H_{5} {NO}_{2}

2

C_{6} H_{5} N H_{2}

3

{CH}_{3} {CH}_{2} - C \equiv N

4

\begin{matrix} O \\ | | \\ N H_{2} - C - N H_{2} \end{matrix}

Explanation:

Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene $C_{6} H_{5} {NO}_{2}$ because reaction with $H_{2} {SO}_{4},$ nitrobenzene can not give ammonia.

07. The p-BLOCK ELEMENTS (XII)

188364 When chlorine water is added to a solution of $K B r$ , the solution immediately turns orange red, because

1 Chlorine is reduced to chloride ion

2 Of the formation of

B r C l

3 Bromide ion is oxidized to bromine

4 Of the formation of

B r_{3}^{-}

Explanation:

$B r_{2}$ , formed by adding chlorine water to a solution of $K B r$ , further reacts with $C l_{2}$ to form reddish yellow or orange red $B r C l$ .
$B r_{2} + C l_{2} \to 2 B r C l$

07. The p-BLOCK ELEMENTS (XII)

189348 Which of the following compound show sublimation

1

N H_{4} C l

2

C a C O_{3}

3

B a S O_{4}

4

C a H P O_{3}

Explanation:

(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., $I_{2}, N H_{4} C l$ and camphor.

07. The p-BLOCK ELEMENTS (XII)

189352 Oxidation number of As in $H_{2} A s O_{4}^{-}$ is

1

6

2

7

3

5

4

9

Explanation:

(c) Oxidation number of $A s$ in $H_{2} A s O_{4}^{-}$
$2 + x - 8 = - 1$
$x - 6 = - 1$
$x = 5$

07. The p-BLOCK ELEMENTS (XII)

189359 The element which liberates oxygen gas from water is

1

P

2

N a

3

F

4

I

Explanation:

(c) $2 H_{2} O + 2 F_{2} \to 4 H F + O_{2}$

07. The p-BLOCK ELEMENTS (XII)

188313 Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?

1

C_{6} H_{5} {NO}_{2}

2

C_{6} H_{5} N H_{2}

3

{CH}_{3} {CH}_{2} - C \equiv N

4

\begin{matrix} O \\ | | \\ N H_{2} - C - N H_{2} \end{matrix}

Explanation:

Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene $C_{6} H_{5} {NO}_{2}$ because reaction with $H_{2} {SO}_{4},$ nitrobenzene can not give ammonia.

07. The p-BLOCK ELEMENTS (XII)

188364 When chlorine water is added to a solution of $K B r$ , the solution immediately turns orange red, because

1 Chlorine is reduced to chloride ion

2 Of the formation of

B r C l

3 Bromide ion is oxidized to bromine

4 Of the formation of

B r_{3}^{-}

Explanation:

$B r_{2}$ , formed by adding chlorine water to a solution of $K B r$ , further reacts with $C l_{2}$ to form reddish yellow or orange red $B r C l$ .
$B r_{2} + C l_{2} \to 2 B r C l$