189348
Which of the following compound show sublimation
1 \(N{H_4}Cl\)
2 \(CaC{O_3}\)
3 \(BaS{O_4}\)
4 \(CaHP{O_3}\)
Explanation:
(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., \({I_2},\;N{H_4}Cl\) and camphor.
07. The p-BLOCK ELEMENTS (XII)
189352
Oxidation number of As in \({H_2}AsO_4^ - \) is
1 \(6\)
2 \(7\)
3 \(5\)
4 \(9\)
Explanation:
(c) Oxidation number of \(As\) in \({H_2}AsO_4^ -\) \(2 + x - 8 = - 1\) \(x - 6 = - 1\) \(x = 5\)
07. The p-BLOCK ELEMENTS (XII)
189359
The element which liberates oxygen gas from water is
1 \(P\)
2 \(Na\)
3 \(F\)
4 \(I\)
Explanation:
(c)\(2{H_2}O + 2{F_2}\, \to \,4HF + {O_2}\)
07. The p-BLOCK ELEMENTS (XII)
188313
Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?
4 $\begin{array}{*{20}{c}} O \\ {||} \\ {N{H_2} - C - N{H_2}} \end{array}$
Explanation:
Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}\) because reaction with \(\mathrm{H}_{2} \mathrm{SO}_{4},\) nitrobenzene can not give ammonia.
07. The p-BLOCK ELEMENTS (XII)
188364
When chlorine water is added to a solution of \(KBr\), the solution immediately turns orange red, because
1 Chlorine is reduced to chloride ion
2 Of the formation of \(BrCl\)
3 Bromide ion is oxidized to bromine
4 Of the formation of \(Br_3^-\)
Explanation:
\(Br_2\), formed by adding chlorine water to a solution of \(KBr\), further reacts with \(Cl_2\) to form reddish yellow or orange red \(BrCl\). \(Br_2 + Cl_2 \to 2BrCl\)
189348
Which of the following compound show sublimation
1 \(N{H_4}Cl\)
2 \(CaC{O_3}\)
3 \(BaS{O_4}\)
4 \(CaHP{O_3}\)
Explanation:
(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., \({I_2},\;N{H_4}Cl\) and camphor.
07. The p-BLOCK ELEMENTS (XII)
189352
Oxidation number of As in \({H_2}AsO_4^ - \) is
1 \(6\)
2 \(7\)
3 \(5\)
4 \(9\)
Explanation:
(c) Oxidation number of \(As\) in \({H_2}AsO_4^ -\) \(2 + x - 8 = - 1\) \(x - 6 = - 1\) \(x = 5\)
07. The p-BLOCK ELEMENTS (XII)
189359
The element which liberates oxygen gas from water is
1 \(P\)
2 \(Na\)
3 \(F\)
4 \(I\)
Explanation:
(c)\(2{H_2}O + 2{F_2}\, \to \,4HF + {O_2}\)
07. The p-BLOCK ELEMENTS (XII)
188313
Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?
4 $\begin{array}{*{20}{c}} O \\ {||} \\ {N{H_2} - C - N{H_2}} \end{array}$
Explanation:
Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}\) because reaction with \(\mathrm{H}_{2} \mathrm{SO}_{4},\) nitrobenzene can not give ammonia.
07. The p-BLOCK ELEMENTS (XII)
188364
When chlorine water is added to a solution of \(KBr\), the solution immediately turns orange red, because
1 Chlorine is reduced to chloride ion
2 Of the formation of \(BrCl\)
3 Bromide ion is oxidized to bromine
4 Of the formation of \(Br_3^-\)
Explanation:
\(Br_2\), formed by adding chlorine water to a solution of \(KBr\), further reacts with \(Cl_2\) to form reddish yellow or orange red \(BrCl\). \(Br_2 + Cl_2 \to 2BrCl\)
189348
Which of the following compound show sublimation
1 \(N{H_4}Cl\)
2 \(CaC{O_3}\)
3 \(BaS{O_4}\)
4 \(CaHP{O_3}\)
Explanation:
(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., \({I_2},\;N{H_4}Cl\) and camphor.
07. The p-BLOCK ELEMENTS (XII)
189352
Oxidation number of As in \({H_2}AsO_4^ - \) is
1 \(6\)
2 \(7\)
3 \(5\)
4 \(9\)
Explanation:
(c) Oxidation number of \(As\) in \({H_2}AsO_4^ -\) \(2 + x - 8 = - 1\) \(x - 6 = - 1\) \(x = 5\)
07. The p-BLOCK ELEMENTS (XII)
189359
The element which liberates oxygen gas from water is
1 \(P\)
2 \(Na\)
3 \(F\)
4 \(I\)
Explanation:
(c)\(2{H_2}O + 2{F_2}\, \to \,4HF + {O_2}\)
07. The p-BLOCK ELEMENTS (XII)
188313
Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?
4 $\begin{array}{*{20}{c}} O \\ {||} \\ {N{H_2} - C - N{H_2}} \end{array}$
Explanation:
Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}\) because reaction with \(\mathrm{H}_{2} \mathrm{SO}_{4},\) nitrobenzene can not give ammonia.
07. The p-BLOCK ELEMENTS (XII)
188364
When chlorine water is added to a solution of \(KBr\), the solution immediately turns orange red, because
1 Chlorine is reduced to chloride ion
2 Of the formation of \(BrCl\)
3 Bromide ion is oxidized to bromine
4 Of the formation of \(Br_3^-\)
Explanation:
\(Br_2\), formed by adding chlorine water to a solution of \(KBr\), further reacts with \(Cl_2\) to form reddish yellow or orange red \(BrCl\). \(Br_2 + Cl_2 \to 2BrCl\)
189348
Which of the following compound show sublimation
1 \(N{H_4}Cl\)
2 \(CaC{O_3}\)
3 \(BaS{O_4}\)
4 \(CaHP{O_3}\)
Explanation:
(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., \({I_2},\;N{H_4}Cl\) and camphor.
07. The p-BLOCK ELEMENTS (XII)
189352
Oxidation number of As in \({H_2}AsO_4^ - \) is
1 \(6\)
2 \(7\)
3 \(5\)
4 \(9\)
Explanation:
(c) Oxidation number of \(As\) in \({H_2}AsO_4^ -\) \(2 + x - 8 = - 1\) \(x - 6 = - 1\) \(x = 5\)
07. The p-BLOCK ELEMENTS (XII)
189359
The element which liberates oxygen gas from water is
1 \(P\)
2 \(Na\)
3 \(F\)
4 \(I\)
Explanation:
(c)\(2{H_2}O + 2{F_2}\, \to \,4HF + {O_2}\)
07. The p-BLOCK ELEMENTS (XII)
188313
Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?
4 $\begin{array}{*{20}{c}} O \\ {||} \\ {N{H_2} - C - N{H_2}} \end{array}$
Explanation:
Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}\) because reaction with \(\mathrm{H}_{2} \mathrm{SO}_{4},\) nitrobenzene can not give ammonia.
07. The p-BLOCK ELEMENTS (XII)
188364
When chlorine water is added to a solution of \(KBr\), the solution immediately turns orange red, because
1 Chlorine is reduced to chloride ion
2 Of the formation of \(BrCl\)
3 Bromide ion is oxidized to bromine
4 Of the formation of \(Br_3^-\)
Explanation:
\(Br_2\), formed by adding chlorine water to a solution of \(KBr\), further reacts with \(Cl_2\) to form reddish yellow or orange red \(BrCl\). \(Br_2 + Cl_2 \to 2BrCl\)
189348
Which of the following compound show sublimation
1 \(N{H_4}Cl\)
2 \(CaC{O_3}\)
3 \(BaS{O_4}\)
4 \(CaHP{O_3}\)
Explanation:
(a)When a solid compound on heating change into gaseous state without changing into liquid state, the phenomenon is known as sublimation. e.g., \({I_2},\;N{H_4}Cl\) and camphor.
07. The p-BLOCK ELEMENTS (XII)
189352
Oxidation number of As in \({H_2}AsO_4^ - \) is
1 \(6\)
2 \(7\)
3 \(5\)
4 \(9\)
Explanation:
(c) Oxidation number of \(As\) in \({H_2}AsO_4^ -\) \(2 + x - 8 = - 1\) \(x - 6 = - 1\) \(x = 5\)
07. The p-BLOCK ELEMENTS (XII)
189359
The element which liberates oxygen gas from water is
1 \(P\)
2 \(Na\)
3 \(F\)
4 \(I\)
Explanation:
(c)\(2{H_2}O + 2{F_2}\, \to \,4HF + {O_2}\)
07. The p-BLOCK ELEMENTS (XII)
188313
Kjeldahl's method cannot be used to estimate nitrogen for which of the following compounds?
4 $\begin{array}{*{20}{c}} O \\ {||} \\ {N{H_2} - C - N{H_2}} \end{array}$
Explanation:
Kjeldahl's method for estimation of nitrogen is not applicable for nitrobenzene \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}\) because reaction with \(\mathrm{H}_{2} \mathrm{SO}_{4},\) nitrobenzene can not give ammonia.
07. The p-BLOCK ELEMENTS (XII)
188364
When chlorine water is added to a solution of \(KBr\), the solution immediately turns orange red, because
1 Chlorine is reduced to chloride ion
2 Of the formation of \(BrCl\)
3 Bromide ion is oxidized to bromine
4 Of the formation of \(Br_3^-\)
Explanation:
\(Br_2\), formed by adding chlorine water to a solution of \(KBr\), further reacts with \(Cl_2\) to form reddish yellow or orange red \(BrCl\). \(Br_2 + Cl_2 \to 2BrCl\)
