12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
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बेंजीन में प्रत्येक कार्बन परमाणु इस संकरण अवस्था में हैं
1 \(s{p^3}\)
2 \(s{p^2}\)
3 \(sp\)
4 \({s^3}p\)
Explanation:
In benzene, each Carbon atom has \(3 \sigma\) bonds and \(1 \pi\) bond. Since it has \(3 \sigma\) bonds, it has to be \(sp ^2\) hybridization.