12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181718
\({H_2}C = CH - \mathop {\mathop {CH\,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_2}C \equiv CH\) का \(IUPAC\) नाम है
1 \(3-\) मेथिल \(-1-\) हैक्सीन \(- 5-\) आइन
2 \(4-\) मेथिल \(- 5-\) हैक्सीन \(- 1-\) आइन
3 \(4-(\)एथिनिल\( )-1-\) पेण्टाइन
4 \(3-(2-\) प्रोपिनिल$)$ ब्यूटीन \(-1\)
Explanation:
In the given compound the parent chair consist of \(6\)-carbon atoms with one double \(f\) ane triple bond. In a double and triple bond, when both of them are at a similar position, then the priority is given to double bond over the triple bond. Thus, the numbering will be done from thatend from where double bond come first. Thus, IUPAC name of the combound is \(3\)-methyl-\(1\)-hexen-\(5\)-yne
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181719
\({(C{H_3})_2}CH - C{H_2} - C{H_2}Br\) का \(IUPAC\) नाम है
1 \(1-\) ब्रोमो पेण्टेन
2 \(2-\) मेथिल \(- 4 -\) ब्रोमो ब्यूटेन
3 \(1-\) ब्रोमो \(3-\) मेथिल ब्यूटेन
4 \(2-\) मेथिल \(3\) ब्रोमो प्रोपेन
Explanation:
\(IUPAC\) name of \(\left( CH _3\right)_2 CH - CH _2- CH _2 Br\) is \(1\)-Bromo-\(3\)-methylbutane. The parent chain has \(4\) carbon atoms with a methyl substituent \(\left( CH _3\right)\) at \(C -3\) and a bromine atom at \(C -1\)
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181720
\(\mathop {C{H_3}}\limits^{{\text{III}}} - \mathop {C{H_2}}\limits^{{\text{II}}} - C \equiv \mathop {CH}\limits^{\text{I}} \), इस संरचना में कौनसा कार्बन सबसे अधिक विद्युत ऋणात्मक है
1 \(I\)
2 \(II\)
3 \(III\)
4 सभी बराबर विद्युत ऋणात्मक हैे
Explanation:
\(\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} \) Elecronegativity \(\propto\) \(s\)-character. In \(sp\) hybrid orbitals, \(s\) character \(=50\, \%\) and in \(sp ^3\) hybrid orbitals, \(s\) character \(=33.3 \,\%\) Thus, option \(I\) is the most electronegative.
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181718
\({H_2}C = CH - \mathop {\mathop {CH\,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_2}C \equiv CH\) का \(IUPAC\) नाम है
1 \(3-\) मेथिल \(-1-\) हैक्सीन \(- 5-\) आइन
2 \(4-\) मेथिल \(- 5-\) हैक्सीन \(- 1-\) आइन
3 \(4-(\)एथिनिल\( )-1-\) पेण्टाइन
4 \(3-(2-\) प्रोपिनिल$)$ ब्यूटीन \(-1\)
Explanation:
In the given compound the parent chair consist of \(6\)-carbon atoms with one double \(f\) ane triple bond. In a double and triple bond, when both of them are at a similar position, then the priority is given to double bond over the triple bond. Thus, the numbering will be done from thatend from where double bond come first. Thus, IUPAC name of the combound is \(3\)-methyl-\(1\)-hexen-\(5\)-yne
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181719
\({(C{H_3})_2}CH - C{H_2} - C{H_2}Br\) का \(IUPAC\) नाम है
1 \(1-\) ब्रोमो पेण्टेन
2 \(2-\) मेथिल \(- 4 -\) ब्रोमो ब्यूटेन
3 \(1-\) ब्रोमो \(3-\) मेथिल ब्यूटेन
4 \(2-\) मेथिल \(3\) ब्रोमो प्रोपेन
Explanation:
\(IUPAC\) name of \(\left( CH _3\right)_2 CH - CH _2- CH _2 Br\) is \(1\)-Bromo-\(3\)-methylbutane. The parent chain has \(4\) carbon atoms with a methyl substituent \(\left( CH _3\right)\) at \(C -3\) and a bromine atom at \(C -1\)
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181720
\(\mathop {C{H_3}}\limits^{{\text{III}}} - \mathop {C{H_2}}\limits^{{\text{II}}} - C \equiv \mathop {CH}\limits^{\text{I}} \), इस संरचना में कौनसा कार्बन सबसे अधिक विद्युत ऋणात्मक है
1 \(I\)
2 \(II\)
3 \(III\)
4 सभी बराबर विद्युत ऋणात्मक हैे
Explanation:
\(\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} \) Elecronegativity \(\propto\) \(s\)-character. In \(sp\) hybrid orbitals, \(s\) character \(=50\, \%\) and in \(sp ^3\) hybrid orbitals, \(s\) character \(=33.3 \,\%\) Thus, option \(I\) is the most electronegative.
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181718
\({H_2}C = CH - \mathop {\mathop {CH\,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_2}C \equiv CH\) का \(IUPAC\) नाम है
1 \(3-\) मेथिल \(-1-\) हैक्सीन \(- 5-\) आइन
2 \(4-\) मेथिल \(- 5-\) हैक्सीन \(- 1-\) आइन
3 \(4-(\)एथिनिल\( )-1-\) पेण्टाइन
4 \(3-(2-\) प्रोपिनिल$)$ ब्यूटीन \(-1\)
Explanation:
In the given compound the parent chair consist of \(6\)-carbon atoms with one double \(f\) ane triple bond. In a double and triple bond, when both of them are at a similar position, then the priority is given to double bond over the triple bond. Thus, the numbering will be done from thatend from where double bond come first. Thus, IUPAC name of the combound is \(3\)-methyl-\(1\)-hexen-\(5\)-yne
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181719
\({(C{H_3})_2}CH - C{H_2} - C{H_2}Br\) का \(IUPAC\) नाम है
1 \(1-\) ब्रोमो पेण्टेन
2 \(2-\) मेथिल \(- 4 -\) ब्रोमो ब्यूटेन
3 \(1-\) ब्रोमो \(3-\) मेथिल ब्यूटेन
4 \(2-\) मेथिल \(3\) ब्रोमो प्रोपेन
Explanation:
\(IUPAC\) name of \(\left( CH _3\right)_2 CH - CH _2- CH _2 Br\) is \(1\)-Bromo-\(3\)-methylbutane. The parent chain has \(4\) carbon atoms with a methyl substituent \(\left( CH _3\right)\) at \(C -3\) and a bromine atom at \(C -1\)
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181720
\(\mathop {C{H_3}}\limits^{{\text{III}}} - \mathop {C{H_2}}\limits^{{\text{II}}} - C \equiv \mathop {CH}\limits^{\text{I}} \), इस संरचना में कौनसा कार्बन सबसे अधिक विद्युत ऋणात्मक है
1 \(I\)
2 \(II\)
3 \(III\)
4 सभी बराबर विद्युत ऋणात्मक हैे
Explanation:
\(\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} \) Elecronegativity \(\propto\) \(s\)-character. In \(sp\) hybrid orbitals, \(s\) character \(=50\, \%\) and in \(sp ^3\) hybrid orbitals, \(s\) character \(=33.3 \,\%\) Thus, option \(I\) is the most electronegative.
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181718
\({H_2}C = CH - \mathop {\mathop {CH\,}\limits_{|\,\,\,\,\,\,\,\,\,} }\limits_{C{H_3}} - C{H_2}C \equiv CH\) का \(IUPAC\) नाम है
1 \(3-\) मेथिल \(-1-\) हैक्सीन \(- 5-\) आइन
2 \(4-\) मेथिल \(- 5-\) हैक्सीन \(- 1-\) आइन
3 \(4-(\)एथिनिल\( )-1-\) पेण्टाइन
4 \(3-(2-\) प्रोपिनिल$)$ ब्यूटीन \(-1\)
Explanation:
In the given compound the parent chair consist of \(6\)-carbon atoms with one double \(f\) ane triple bond. In a double and triple bond, when both of them are at a similar position, then the priority is given to double bond over the triple bond. Thus, the numbering will be done from thatend from where double bond come first. Thus, IUPAC name of the combound is \(3\)-methyl-\(1\)-hexen-\(5\)-yne
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181719
\({(C{H_3})_2}CH - C{H_2} - C{H_2}Br\) का \(IUPAC\) नाम है
1 \(1-\) ब्रोमो पेण्टेन
2 \(2-\) मेथिल \(- 4 -\) ब्रोमो ब्यूटेन
3 \(1-\) ब्रोमो \(3-\) मेथिल ब्यूटेन
4 \(2-\) मेथिल \(3\) ब्रोमो प्रोपेन
Explanation:
\(IUPAC\) name of \(\left( CH _3\right)_2 CH - CH _2- CH _2 Br\) is \(1\)-Bromo-\(3\)-methylbutane. The parent chain has \(4\) carbon atoms with a methyl substituent \(\left( CH _3\right)\) at \(C -3\) and a bromine atom at \(C -1\)
12. ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES (HM)
181720
\(\mathop {C{H_3}}\limits^{{\text{III}}} - \mathop {C{H_2}}\limits^{{\text{II}}} - C \equiv \mathop {CH}\limits^{\text{I}} \), इस संरचना में कौनसा कार्बन सबसे अधिक विद्युत ऋणात्मक है
1 \(I\)
2 \(II\)
3 \(III\)
4 सभी बराबर विद्युत ऋणात्मक हैे
Explanation:
\(\mathop {C{H_3}}\limits^{{\rm{III}}} - \mathop {C{H_2}}\limits^{{\rm{II}}} - C \equiv \mathop {CH}\limits^{\rm{I}} \) Elecronegativity \(\propto\) \(s\)-character. In \(sp\) hybrid orbitals, \(s\) character \(=50\, \%\) and in \(sp ^3\) hybrid orbitals, \(s\) character \(=33.3 \,\%\) Thus, option \(I\) is the most electronegative.