8 RBTS PAPER(PHYSICS)
8 RBTS PAPER

164386 If a simple harmonic motion is represented by \(\frac{d^2 y}{d t^2}+A y=0\). Then value of time period will be :

1 \(\frac{2 \pi}{\sqrt{\mathrm{A}}}\)
2 \(\frac{2 \pi}{\mathrm{A}}\)
3 \(2 \pi \sqrt{\mathrm{A}}\)
4 \(2 \pi \mathrm{A}\)
8 RBTS PAPER

164387 A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :

1 1
2 \(1 / 2\)
3 \(1 / 4\)
4 2
8 RBTS PAPER

164388 A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :

1 \(\frac{2 \pi}{25} \mathrm{sec}\)
2 \(\frac{\pi \sqrt{2}}{5} \mathrm{sec}\)
3 \(\frac{4 \pi}{20} \mathrm{sec}\)
4 \(\frac{2 \pi \sqrt{2}}{5} \mathrm{sec}\)
8 RBTS PAPER

164389 A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :

1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)
8 RBTS PAPER

164386 If a simple harmonic motion is represented by \(\frac{d^2 y}{d t^2}+A y=0\). Then value of time period will be :

1 \(\frac{2 \pi}{\sqrt{\mathrm{A}}}\)
2 \(\frac{2 \pi}{\mathrm{A}}\)
3 \(2 \pi \sqrt{\mathrm{A}}\)
4 \(2 \pi \mathrm{A}\)
8 RBTS PAPER

164387 A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :

1 1
2 \(1 / 2\)
3 \(1 / 4\)
4 2
8 RBTS PAPER

164388 A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :

1 \(\frac{2 \pi}{25} \mathrm{sec}\)
2 \(\frac{\pi \sqrt{2}}{5} \mathrm{sec}\)
3 \(\frac{4 \pi}{20} \mathrm{sec}\)
4 \(\frac{2 \pi \sqrt{2}}{5} \mathrm{sec}\)
8 RBTS PAPER

164389 A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :

1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)
8 RBTS PAPER

164386 If a simple harmonic motion is represented by \(\frac{d^2 y}{d t^2}+A y=0\). Then value of time period will be :

1 \(\frac{2 \pi}{\sqrt{\mathrm{A}}}\)
2 \(\frac{2 \pi}{\mathrm{A}}\)
3 \(2 \pi \sqrt{\mathrm{A}}\)
4 \(2 \pi \mathrm{A}\)
8 RBTS PAPER

164387 A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :

1 1
2 \(1 / 2\)
3 \(1 / 4\)
4 2
8 RBTS PAPER

164388 A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :

1 \(\frac{2 \pi}{25} \mathrm{sec}\)
2 \(\frac{\pi \sqrt{2}}{5} \mathrm{sec}\)
3 \(\frac{4 \pi}{20} \mathrm{sec}\)
4 \(\frac{2 \pi \sqrt{2}}{5} \mathrm{sec}\)
8 RBTS PAPER

164389 A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :

1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)
8 RBTS PAPER

164386 If a simple harmonic motion is represented by \(\frac{d^2 y}{d t^2}+A y=0\). Then value of time period will be :

1 \(\frac{2 \pi}{\sqrt{\mathrm{A}}}\)
2 \(\frac{2 \pi}{\mathrm{A}}\)
3 \(2 \pi \sqrt{\mathrm{A}}\)
4 \(2 \pi \mathrm{A}\)
8 RBTS PAPER

164387 A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :

1 1
2 \(1 / 2\)
3 \(1 / 4\)
4 2
8 RBTS PAPER

164388 A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :

1 \(\frac{2 \pi}{25} \mathrm{sec}\)
2 \(\frac{\pi \sqrt{2}}{5} \mathrm{sec}\)
3 \(\frac{4 \pi}{20} \mathrm{sec}\)
4 \(\frac{2 \pi \sqrt{2}}{5} \mathrm{sec}\)
8 RBTS PAPER

164389 A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :

1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)