164387
A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :
164388
A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :
164389
A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :
1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)
Explanation:
\(3 / 8\) osscillation can be written as \(=\frac{(2+1)}{8}=\frac{2}{8}+\frac{1}{8}\) \( =\frac{1}{4}+\frac{1}{8} \) Time taken to complete \(3 / 8\) osscillation \(=\) time taken to \(1 / 4\) osscillation \(\left(\frac{T}{4}\right)+\) time taken to complete \(1 / 8\) osscilation \(\left(\frac{T}{6}\right)\). \( =\frac{\mathrm{T}}{4}+\frac{\mathrm{T}}{6}=\frac{3 \mathrm{~T}+2 \mathrm{~T}}{12}=\frac{5 \mathrm{~T}}{12} \mathrm{sec} \)
164387
A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :
164388
A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :
164389
A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :
1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)
Explanation:
\(3 / 8\) osscillation can be written as \(=\frac{(2+1)}{8}=\frac{2}{8}+\frac{1}{8}\) \( =\frac{1}{4}+\frac{1}{8} \) Time taken to complete \(3 / 8\) osscillation \(=\) time taken to \(1 / 4\) osscillation \(\left(\frac{T}{4}\right)+\) time taken to complete \(1 / 8\) osscilation \(\left(\frac{T}{6}\right)\). \( =\frac{\mathrm{T}}{4}+\frac{\mathrm{T}}{6}=\frac{3 \mathrm{~T}+2 \mathrm{~T}}{12}=\frac{5 \mathrm{~T}}{12} \mathrm{sec} \)
164387
A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :
164388
A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :
164389
A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :
1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)
Explanation:
\(3 / 8\) osscillation can be written as \(=\frac{(2+1)}{8}=\frac{2}{8}+\frac{1}{8}\) \( =\frac{1}{4}+\frac{1}{8} \) Time taken to complete \(3 / 8\) osscillation \(=\) time taken to \(1 / 4\) osscillation \(\left(\frac{T}{4}\right)+\) time taken to complete \(1 / 8\) osscilation \(\left(\frac{T}{6}\right)\). \( =\frac{\mathrm{T}}{4}+\frac{\mathrm{T}}{6}=\frac{3 \mathrm{~T}+2 \mathrm{~T}}{12}=\frac{5 \mathrm{~T}}{12} \mathrm{sec} \)
164387
A particle executes SHM of amplitude A. If \(\mathbf{T}_1\) and \(T_2\) are the times taken by the particle to traverse from 0 to \(A / 2\) and from \(A / 2\) to \(A\) respectively. Then \(T_1 / T_2\) will be equal to :
164388
A particle of mass \(\mathbf{2} \mathbf{~ k g}\) moves simple harmonically such that its PE (U) varies with position \(x\), as shown. The period of oscillations is :
164389
A particle is executing SHM with the periode \(\mathrm{T}\). Starting from mean position, time taken by it to complete \(3 / 8\) oscillations, is :
1 \(T / 12\)
2 \(T / 6\)
3 \(5 T / 12\)
4 \(7 \mathrm{~T} / 12\)
Explanation:
\(3 / 8\) osscillation can be written as \(=\frac{(2+1)}{8}=\frac{2}{8}+\frac{1}{8}\) \( =\frac{1}{4}+\frac{1}{8} \) Time taken to complete \(3 / 8\) osscillation \(=\) time taken to \(1 / 4\) osscillation \(\left(\frac{T}{4}\right)+\) time taken to complete \(1 / 8\) osscilation \(\left(\frac{T}{6}\right)\). \( =\frac{\mathrm{T}}{4}+\frac{\mathrm{T}}{6}=\frac{3 \mathrm{~T}+2 \mathrm{~T}}{12}=\frac{5 \mathrm{~T}}{12} \mathrm{sec} \)