QBManager

5 RBTS PAPER

164050 The figure shows the change in concentrations of species A and $B$ as a function of time. The equilibrium constant $Kc$ for the reaction
$A (g) ⇌ 2 B (g)$ is :

1

K_{C} > 1

2

K < 1

3

K = 1

4 Data insufficient

Explanation:

For the above data we can say conc. of $A$ and $B$ at equilibrium are : 0.4 and 0.1
$K_{C} = \frac{^{2}}{} = \frac{(0.4)^{2}}{(0.1)} = \frac{0.16}{0.1} = 1.6$
so, $(K_{c} > 1)$

NCERT-XI-178

5 RBTS PAPER

164051 The degree of dissociation of ${PCl}_{5}$ obeying the equilibrium ${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$ is related to the pressure at equilibrium by : (If $\propto< 1$ )

1

α \propto P

2

α \propto \frac{1}{\sqrt{P}}

3

α \propto \frac{1}{P^{2}}

4

α \propto \frac{1}{P^{4}}

Explanation:

${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
Total $= 1 - α + α + α = (1 + α)$
$K_{P} = \frac{(\frac{α}{1 + α}) P (\frac{α}{1 + α}) P}{(\frac{1 - α}{1 + α}) P}$
$K_{P} = \frac{{(\frac{α}{1 + α})}^{2} P^{2}}{(\frac{1 - α}{1 + α}) P} = K_{P} = (\frac{α^{2}}{1 - α^{2}}) P$
If $a - α^{2} = 1$ then
$α = \sqrt{\frac{K_{P}}{P}}$
$K_{P}$ is const.
$(α \propto \frac{1}{\sqrt{P}})$

NCERT-XI-178

5 RBTS PAPER

164052 Which of the following not behave as buffer :

1

{CH}_{3} COOH + {CH}_{3} COONa

2

{NH}_{4} OH + {({NH}_{4})}_{2} {SO}_{4}

3 Mixture of

1 M 20 ml NaOH

and

1 M, 40 ml HCN

4 All behave as buffer

NCERT-XI-202

5 RBTS PAPER

164053 Boric acid is an acid because its molecule :

1 accepts

{OH}^{-}

from water releasing proton

2 combines with proton from water molecule

3 contains replaceable

H^{+}

ion

4 gives up a proton

NCERT-XI-192

5 RBTS PAPER

164050 The figure shows the change in concentrations of species A and $B$ as a function of time. The equilibrium constant $Kc$ for the reaction
$A (g) ⇌ 2 B (g)$ is :

1

K_{C} > 1

2

K < 1

3

K = 1

4 Data insufficient

Explanation:

For the above data we can say conc. of $A$ and $B$ at equilibrium are : 0.4 and 0.1
$K_{C} = \frac{^{2}}{} = \frac{(0.4)^{2}}{(0.1)} = \frac{0.16}{0.1} = 1.6$
so, $(K_{c} > 1)$

NCERT-XI-178

5 RBTS PAPER

164051 The degree of dissociation of ${PCl}_{5}$ obeying the equilibrium ${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$ is related to the pressure at equilibrium by : (If $\propto< 1$ )

1

α \propto P

2

α \propto \frac{1}{\sqrt{P}}

3

α \propto \frac{1}{P^{2}}

4

α \propto \frac{1}{P^{4}}

Explanation:

${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
Total $= 1 - α + α + α = (1 + α)$
$K_{P} = \frac{(\frac{α}{1 + α}) P (\frac{α}{1 + α}) P}{(\frac{1 - α}{1 + α}) P}$
$K_{P} = \frac{{(\frac{α}{1 + α})}^{2} P^{2}}{(\frac{1 - α}{1 + α}) P} = K_{P} = (\frac{α^{2}}{1 - α^{2}}) P$
If $a - α^{2} = 1$ then
$α = \sqrt{\frac{K_{P}}{P}}$
$K_{P}$ is const.
$(α \propto \frac{1}{\sqrt{P}})$

NCERT-XI-178

5 RBTS PAPER

164052 Which of the following not behave as buffer :

1

{CH}_{3} COOH + {CH}_{3} COONa

2

{NH}_{4} OH + {({NH}_{4})}_{2} {SO}_{4}

3 Mixture of

1 M 20 ml NaOH

and

1 M, 40 ml HCN

4 All behave as buffer

NCERT-XI-202

5 RBTS PAPER

164053 Boric acid is an acid because its molecule :

1 accepts

{OH}^{-}

from water releasing proton

2 combines with proton from water molecule

3 contains replaceable

H^{+}

ion

4 gives up a proton

NCERT-XI-192

5 RBTS PAPER

164050 The figure shows the change in concentrations of species A and $B$ as a function of time. The equilibrium constant $Kc$ for the reaction
$A (g) ⇌ 2 B (g)$ is :

1

K_{C} > 1

2

K < 1

3

K = 1

4 Data insufficient

Explanation:

For the above data we can say conc. of $A$ and $B$ at equilibrium are : 0.4 and 0.1
$K_{C} = \frac{^{2}}{} = \frac{(0.4)^{2}}{(0.1)} = \frac{0.16}{0.1} = 1.6$
so, $(K_{c} > 1)$

NCERT-XI-178

5 RBTS PAPER

164051 The degree of dissociation of ${PCl}_{5}$ obeying the equilibrium ${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$ is related to the pressure at equilibrium by : (If $\propto< 1$ )

1

α \propto P

2

α \propto \frac{1}{\sqrt{P}}

3

α \propto \frac{1}{P^{2}}

4

α \propto \frac{1}{P^{4}}

Explanation:

${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
Total $= 1 - α + α + α = (1 + α)$
$K_{P} = \frac{(\frac{α}{1 + α}) P (\frac{α}{1 + α}) P}{(\frac{1 - α}{1 + α}) P}$
$K_{P} = \frac{{(\frac{α}{1 + α})}^{2} P^{2}}{(\frac{1 - α}{1 + α}) P} = K_{P} = (\frac{α^{2}}{1 - α^{2}}) P$
If $a - α^{2} = 1$ then
$α = \sqrt{\frac{K_{P}}{P}}$
$K_{P}$ is const.
$(α \propto \frac{1}{\sqrt{P}})$

NCERT-XI-178

5 RBTS PAPER

164052 Which of the following not behave as buffer :

1

{CH}_{3} COOH + {CH}_{3} COONa

2

{NH}_{4} OH + {({NH}_{4})}_{2} {SO}_{4}

3 Mixture of

1 M 20 ml NaOH

and

1 M, 40 ml HCN

4 All behave as buffer

NCERT-XI-202

5 RBTS PAPER

164053 Boric acid is an acid because its molecule :

1 accepts

{OH}^{-}

from water releasing proton

2 combines with proton from water molecule

3 contains replaceable

H^{+}

ion

4 gives up a proton

NCERT-XI-192

5 RBTS PAPER

164050 The figure shows the change in concentrations of species A and $B$ as a function of time. The equilibrium constant $Kc$ for the reaction
$A (g) ⇌ 2 B (g)$ is :

1

K_{C} > 1

2

K < 1

3

K = 1

4 Data insufficient

Explanation:

For the above data we can say conc. of $A$ and $B$ at equilibrium are : 0.4 and 0.1
$K_{C} = \frac{^{2}}{} = \frac{(0.4)^{2}}{(0.1)} = \frac{0.16}{0.1} = 1.6$
so, $(K_{c} > 1)$

NCERT-XI-178

5 RBTS PAPER

164051 The degree of dissociation of ${PCl}_{5}$ obeying the equilibrium ${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$ is related to the pressure at equilibrium by : (If $\propto< 1$ )

1

α \propto P

2

α \propto \frac{1}{\sqrt{P}}

3

α \propto \frac{1}{P^{2}}

4

α \propto \frac{1}{P^{4}}

Explanation:

${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$
100
(1- $α) α α$
Total $= 1 - α + α + α = (1 + α)$
$K_{P} = \frac{(\frac{α}{1 + α}) P (\frac{α}{1 + α}) P}{(\frac{1 - α}{1 + α}) P}$
$K_{P} = \frac{{(\frac{α}{1 + α})}^{2} P^{2}}{(\frac{1 - α}{1 + α}) P} = K_{P} = (\frac{α^{2}}{1 - α^{2}}) P$
If $a - α^{2} = 1$ then
$α = \sqrt{\frac{K_{P}}{P}}$
$K_{P}$ is const.
$(α \propto \frac{1}{\sqrt{P}})$

NCERT-XI-178

5 RBTS PAPER

164052 Which of the following not behave as buffer :

1

{CH}_{3} COOH + {CH}_{3} COONa

2

{NH}_{4} OH + {({NH}_{4})}_{2} {SO}_{4}

3 Mixture of

1 M 20 ml NaOH

and

1 M, 40 ml HCN

4 All behave as buffer

NCERT-XI-202

5 RBTS PAPER

164053 Boric acid is an acid because its molecule :

1 accepts

{OH}^{-}

from water releasing proton

2 combines with proton from water molecule

3 contains replaceable

H^{+}

ion

4 gives up a proton

NCERT-XI-192