160813
For a particle in circular motion the centripetal acceleration is
1 less than its tangential acceleration
2 equal to its tangential acceleration
3 more than its tangential acceleration
4 may be more or less than its tangential acceleation
Explanation:
Centripetal acceleration is may be more or less than its tangential acceleration.
NCERT- 105
2 RBTS PAPER
160814
The coefficient of static and dynamic friction between a body and the surface are $\mathbf{0 . 7 5}$ and 0.5 respectively. Aforce is applied to the body to make it just slide with a constant acceleration which is
1 $g / 4$
2 $g / 2$
3 $(3 / 2) \mathrm{g}$
4 $\mathrm{g}$
Explanation:
$\mathrm{F}($ force due to static friction $)=\mu_{\mathrm{s}} \mathrm{mg}$ $\begin{aligned} F & -F_k=m a \\ a & =\frac{F-F_k}{m}=\frac{\mu_s m g-\mu_k m g}{m} \\ & =\left(\mu_s-\mu_k\right) \cdot g=(0.75-0.5) g \\ & =\mathrm{g} / 4 \end{aligned}$
160813
For a particle in circular motion the centripetal acceleration is
1 less than its tangential acceleration
2 equal to its tangential acceleration
3 more than its tangential acceleration
4 may be more or less than its tangential acceleation
Explanation:
Centripetal acceleration is may be more or less than its tangential acceleration.
NCERT- 105
2 RBTS PAPER
160814
The coefficient of static and dynamic friction between a body and the surface are $\mathbf{0 . 7 5}$ and 0.5 respectively. Aforce is applied to the body to make it just slide with a constant acceleration which is
1 $g / 4$
2 $g / 2$
3 $(3 / 2) \mathrm{g}$
4 $\mathrm{g}$
Explanation:
$\mathrm{F}($ force due to static friction $)=\mu_{\mathrm{s}} \mathrm{mg}$ $\begin{aligned} F & -F_k=m a \\ a & =\frac{F-F_k}{m}=\frac{\mu_s m g-\mu_k m g}{m} \\ & =\left(\mu_s-\mu_k\right) \cdot g=(0.75-0.5) g \\ & =\mathrm{g} / 4 \end{aligned}$
