QBManager

6 RBTS PAPER

163225 The sum of oxidation numbers of sulphur in $H_{2} S_{2} O_{8}$ is : [RBQ]

1 2

2 6

3 14

4 12

Explanation:

O=S(=O)(O)OOS(=O)(=O)O
Both sulphur has +6 oxidation state in $H_{2} S_{2} O_{8}$

NCERT-XI-240

6 RBTS PAPER

163226 In which of the following species, peroxy link is not present? [RBQ]

1

{CrO}_{5}

2

H_{2} {SO}_{5}

3

H_{2} S_{2} O_{8}

4

{Na}_{2} S_{4} O_{6}

Explanation:

O=S(=O)(O)SSS(=O)(=O)O
No peroxy linkage in ${Na}_{2} S_{4} O_{6}$ .

NCERT-XI-240

6 RBTS PAPER

163227 ${Cr}_{2} O_{7}^{- 2} + I^{-} + H^{+} \to {Cr}^{+ 3} + I_{2} + H_{2} O$
The equivalent weight of reductant in the above equation is (At. wt. of $Cr = 52, I = 127$ ) : [RBQ]

1 26

2 52

3 63.5

4 127

Explanation:

$I^{-} \to I_{2}$
$n$ factor $= 1$
Equivalent weight $= 127 / 1$

NCERT-XI-249

6 RBTS PAPER

163228 Number of moles of $K_{2} {Cr}_{2} O_{7}$ required to oxidise one mole of sodium oxalate completely in acid medium will be : [RBQ]

1

1 / 3

2

3 / 5

3

1 / 5

4

5 / 3

Explanation:

$K_{2} {Cr}_{2} O_{7}$
${Na}_{2} C_{2} O_{4}$
No. of moles $\times n$ factor $=$ no. of moles $\times n$ factor
$n \times 6 = 1 \times 2 n = 1 / 3$

NCERT-XI-249

6 RBTS PAPER

163259 Choose the correct statement(s) from the following: [RBQ]

1 Cathode and anode are negative terminal in electrolytic and galvanic cell

2 Cathode is negative terminal in both electrolytic \& galvanic cell

3 Anode is positive terminal in both electrolytic and galvanic cell

4 All of these

NCERT-XII-32

6 RBTS PAPER

163225 The sum of oxidation numbers of sulphur in $H_{2} S_{2} O_{8}$ is : [RBQ]

1 2

2 6

3 14

4 12

Explanation:

O=S(=O)(O)OOS(=O)(=O)O
Both sulphur has +6 oxidation state in $H_{2} S_{2} O_{8}$

NCERT-XI-240

6 RBTS PAPER

163226 In which of the following species, peroxy link is not present? [RBQ]

1

{CrO}_{5}

2

H_{2} {SO}_{5}

3

H_{2} S_{2} O_{8}

4

{Na}_{2} S_{4} O_{6}

Explanation:

O=S(=O)(O)SSS(=O)(=O)O
No peroxy linkage in ${Na}_{2} S_{4} O_{6}$ .

NCERT-XI-240

6 RBTS PAPER

163227 ${Cr}_{2} O_{7}^{- 2} + I^{-} + H^{+} \to {Cr}^{+ 3} + I_{2} + H_{2} O$
The equivalent weight of reductant in the above equation is (At. wt. of $Cr = 52, I = 127$ ) : [RBQ]

1 26

2 52

3 63.5

4 127

Explanation:

$I^{-} \to I_{2}$
$n$ factor $= 1$
Equivalent weight $= 127 / 1$

NCERT-XI-249

6 RBTS PAPER

163228 Number of moles of $K_{2} {Cr}_{2} O_{7}$ required to oxidise one mole of sodium oxalate completely in acid medium will be : [RBQ]

1

1 / 3

2

3 / 5

3

1 / 5

4

5 / 3

Explanation:

$K_{2} {Cr}_{2} O_{7}$
${Na}_{2} C_{2} O_{4}$
No. of moles $\times n$ factor $=$ no. of moles $\times n$ factor
$n \times 6 = 1 \times 2 n = 1 / 3$

NCERT-XI-249

6 RBTS PAPER

163259 Choose the correct statement(s) from the following: [RBQ]

1 Cathode and anode are negative terminal in electrolytic and galvanic cell

2 Cathode is negative terminal in both electrolytic \& galvanic cell

3 Anode is positive terminal in both electrolytic and galvanic cell

4 All of these

NCERT-XII-32

6 RBTS PAPER

163225 The sum of oxidation numbers of sulphur in $H_{2} S_{2} O_{8}$ is : [RBQ]

1 2

2 6

3 14

4 12

Explanation:

O=S(=O)(O)OOS(=O)(=O)O
Both sulphur has +6 oxidation state in $H_{2} S_{2} O_{8}$

NCERT-XI-240

6 RBTS PAPER

163226 In which of the following species, peroxy link is not present? [RBQ]

1

{CrO}_{5}

2

H_{2} {SO}_{5}

3

H_{2} S_{2} O_{8}

4

{Na}_{2} S_{4} O_{6}

Explanation:

O=S(=O)(O)SSS(=O)(=O)O
No peroxy linkage in ${Na}_{2} S_{4} O_{6}$ .

NCERT-XI-240

6 RBTS PAPER

163227 ${Cr}_{2} O_{7}^{- 2} + I^{-} + H^{+} \to {Cr}^{+ 3} + I_{2} + H_{2} O$
The equivalent weight of reductant in the above equation is (At. wt. of $Cr = 52, I = 127$ ) : [RBQ]

1 26

2 52

3 63.5

4 127

Explanation:

$I^{-} \to I_{2}$
$n$ factor $= 1$
Equivalent weight $= 127 / 1$

NCERT-XI-249

6 RBTS PAPER

163228 Number of moles of $K_{2} {Cr}_{2} O_{7}$ required to oxidise one mole of sodium oxalate completely in acid medium will be : [RBQ]

1

1 / 3

2

3 / 5

3

1 / 5

4

5 / 3

Explanation:

$K_{2} {Cr}_{2} O_{7}$
${Na}_{2} C_{2} O_{4}$
No. of moles $\times n$ factor $=$ no. of moles $\times n$ factor
$n \times 6 = 1 \times 2 n = 1 / 3$

NCERT-XI-249

6 RBTS PAPER

163259 Choose the correct statement(s) from the following: [RBQ]

1 Cathode and anode are negative terminal in electrolytic and galvanic cell

2 Cathode is negative terminal in both electrolytic \& galvanic cell

3 Anode is positive terminal in both electrolytic and galvanic cell

4 All of these

NCERT-XII-32

6 RBTS PAPER

163225 The sum of oxidation numbers of sulphur in $H_{2} S_{2} O_{8}$ is : [RBQ]

1 2

2 6

3 14

4 12

Explanation:

O=S(=O)(O)OOS(=O)(=O)O
Both sulphur has +6 oxidation state in $H_{2} S_{2} O_{8}$

NCERT-XI-240

6 RBTS PAPER

163226 In which of the following species, peroxy link is not present? [RBQ]

1

{CrO}_{5}

2

H_{2} {SO}_{5}

3

H_{2} S_{2} O_{8}

4

{Na}_{2} S_{4} O_{6}

Explanation:

O=S(=O)(O)SSS(=O)(=O)O
No peroxy linkage in ${Na}_{2} S_{4} O_{6}$ .

NCERT-XI-240

6 RBTS PAPER

163227 ${Cr}_{2} O_{7}^{- 2} + I^{-} + H^{+} \to {Cr}^{+ 3} + I_{2} + H_{2} O$
The equivalent weight of reductant in the above equation is (At. wt. of $Cr = 52, I = 127$ ) : [RBQ]

1 26

2 52

3 63.5

4 127

Explanation:

$I^{-} \to I_{2}$
$n$ factor $= 1$
Equivalent weight $= 127 / 1$

NCERT-XI-249

6 RBTS PAPER

163228 Number of moles of $K_{2} {Cr}_{2} O_{7}$ required to oxidise one mole of sodium oxalate completely in acid medium will be : [RBQ]

1

1 / 3

2

3 / 5

3

1 / 5

4

5 / 3

Explanation:

$K_{2} {Cr}_{2} O_{7}$
${Na}_{2} C_{2} O_{4}$
No. of moles $\times n$ factor $=$ no. of moles $\times n$ factor
$n \times 6 = 1 \times 2 n = 1 / 3$

NCERT-XI-249

6 RBTS PAPER

163259 Choose the correct statement(s) from the following: [RBQ]

1 Cathode and anode are negative terminal in electrolytic and galvanic cell

2 Cathode is negative terminal in both electrolytic \& galvanic cell

3 Anode is positive terminal in both electrolytic and galvanic cell

4 All of these

NCERT-XII-32

6 RBTS PAPER

163225 The sum of oxidation numbers of sulphur in $H_{2} S_{2} O_{8}$ is : [RBQ]

1 2

2 6

3 14

4 12

Explanation:

O=S(=O)(O)OOS(=O)(=O)O
Both sulphur has +6 oxidation state in $H_{2} S_{2} O_{8}$

NCERT-XI-240

6 RBTS PAPER

163226 In which of the following species, peroxy link is not present? [RBQ]

1

{CrO}_{5}

2

H_{2} {SO}_{5}

3

H_{2} S_{2} O_{8}

4

{Na}_{2} S_{4} O_{6}

Explanation:

O=S(=O)(O)SSS(=O)(=O)O
No peroxy linkage in ${Na}_{2} S_{4} O_{6}$ .

NCERT-XI-240

6 RBTS PAPER

163227 ${Cr}_{2} O_{7}^{- 2} + I^{-} + H^{+} \to {Cr}^{+ 3} + I_{2} + H_{2} O$
The equivalent weight of reductant in the above equation is (At. wt. of $Cr = 52, I = 127$ ) : [RBQ]

1 26

2 52

3 63.5

4 127

Explanation:

$I^{-} \to I_{2}$
$n$ factor $= 1$
Equivalent weight $= 127 / 1$

NCERT-XI-249

6 RBTS PAPER

163228 Number of moles of $K_{2} {Cr}_{2} O_{7}$ required to oxidise one mole of sodium oxalate completely in acid medium will be : [RBQ]

1

1 / 3

2

3 / 5

3

1 / 5

4

5 / 3

Explanation:

$K_{2} {Cr}_{2} O_{7}$
${Na}_{2} C_{2} O_{4}$
No. of moles $\times n$ factor $=$ no. of moles $\times n$ factor
$n \times 6 = 1 \times 2 n = 1 / 3$

NCERT-XI-249

6 RBTS PAPER

163259 Choose the correct statement(s) from the following: [RBQ]

1 Cathode and anode are negative terminal in electrolytic and galvanic cell

2 Cathode is negative terminal in both electrolytic \& galvanic cell

3 Anode is positive terminal in both electrolytic and galvanic cell

4 All of these

NCERT-XII-32

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