6 RBTS PAPER(CHEMISTRY)
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
6 RBTS PAPER

163221 Oxidation number of \(\mathbf{P}\) in pyrophosphoric acid is: [RBQ]

1 +5
2 +2
3 +3
4 +6
NCERT-XI-240
6 RBTS PAPER

163222 In \(\mathrm{CrO}_5\), the number of oxygen atoms whose oxidation number is -1 : [RBQ]

1 4
2 3
3 2
4 1
NCERT-XI-240
6 RBTS PAPER

163223 Oxidation number of \(\mathrm{Pt}\) in \(\left[\mathrm{Pt}\left(\mathrm{C}_2 \mathrm{H}_4\right) \mathrm{Cl}_3\right]^{-}\)is : [RBQ]

1 +1
2 +2
3 +3
4 +4
NCERT-XI-240
6 RBTS PAPER

163224 Match List-I (compound) with List-II (Oxidation state of \(\mathrm{N}\) ) and select the correct answer using the codes given below the list :


























List-I List-II
a. \(\mathrm{KNO}_3\) i. \(-1 / 3\)
b. \(\mathrm{HNO}_2\) ii. -3
c. \(\mathrm{NH}_4 \mathrm{Cl}\) iii. 0
d. \(\mathrm{NaN}_3\) iv. +3
v. +5

[RBQ]

1 a-v, b-iv, c-ii, d-i
2 a-v, b-ii, c-iv, d-i
3 a-iv, b-v, c-i, d-iii
4 a-ii, b-iii, c-iv, d-v
NCERT-XI-240
NEET DIGITAL LIBRARY
6 RBTS PAPER

163221 Oxidation number of \(\mathbf{P}\) in pyrophosphoric acid is: [RBQ]

1 +5
2 +2
3 +3
4 +6
NCERT-XI-240
6 RBTS PAPER

163222 In \(\mathrm{CrO}_5\), the number of oxygen atoms whose oxidation number is -1 : [RBQ]

1 4
2 3
3 2
4 1
NCERT-XI-240
6 RBTS PAPER

163223 Oxidation number of \(\mathrm{Pt}\) in \(\left[\mathrm{Pt}\left(\mathrm{C}_2 \mathrm{H}_4\right) \mathrm{Cl}_3\right]^{-}\)is : [RBQ]

1 +1
2 +2
3 +3
4 +4
NCERT-XI-240
6 RBTS PAPER

163224 Match List-I (compound) with List-II (Oxidation state of \(\mathrm{N}\) ) and select the correct answer using the codes given below the list :


























List-I List-II
a. \(\mathrm{KNO}_3\) i. \(-1 / 3\)
b. \(\mathrm{HNO}_2\) ii. -3
c. \(\mathrm{NH}_4 \mathrm{Cl}\) iii. 0
d. \(\mathrm{NaN}_3\) iv. +3
v. +5

[RBQ]

1 a-v, b-iv, c-ii, d-i
2 a-v, b-ii, c-iv, d-i
3 a-iv, b-v, c-i, d-iii
4 a-ii, b-iii, c-iv, d-v
NCERT-XI-240
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6 RBTS PAPER

163221 Oxidation number of \(\mathbf{P}\) in pyrophosphoric acid is: [RBQ]

1 +5
2 +2
3 +3
4 +6
NCERT-XI-240
6 RBTS PAPER

163222 In \(\mathrm{CrO}_5\), the number of oxygen atoms whose oxidation number is -1 : [RBQ]

1 4
2 3
3 2
4 1
NCERT-XI-240
6 RBTS PAPER

163223 Oxidation number of \(\mathrm{Pt}\) in \(\left[\mathrm{Pt}\left(\mathrm{C}_2 \mathrm{H}_4\right) \mathrm{Cl}_3\right]^{-}\)is : [RBQ]

1 +1
2 +2
3 +3
4 +4
NCERT-XI-240
6 RBTS PAPER

163224 Match List-I (compound) with List-II (Oxidation state of \(\mathrm{N}\) ) and select the correct answer using the codes given below the list :


























List-I List-II
a. \(\mathrm{KNO}_3\) i. \(-1 / 3\)
b. \(\mathrm{HNO}_2\) ii. -3
c. \(\mathrm{NH}_4 \mathrm{Cl}\) iii. 0
d. \(\mathrm{NaN}_3\) iv. +3
v. +5

[RBQ]

1 a-v, b-iv, c-ii, d-i
2 a-v, b-ii, c-iv, d-i
3 a-iv, b-v, c-i, d-iii
4 a-ii, b-iii, c-iv, d-v
NCERT-XI-240
For More Updates join with Us
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
6 RBTS PAPER

163221 Oxidation number of \(\mathbf{P}\) in pyrophosphoric acid is: [RBQ]

1 +5
2 +2
3 +3
4 +6
NCERT-XI-240
6 RBTS PAPER

163222 In \(\mathrm{CrO}_5\), the number of oxygen atoms whose oxidation number is -1 : [RBQ]

1 4
2 3
3 2
4 1
NCERT-XI-240
6 RBTS PAPER

163223 Oxidation number of \(\mathrm{Pt}\) in \(\left[\mathrm{Pt}\left(\mathrm{C}_2 \mathrm{H}_4\right) \mathrm{Cl}_3\right]^{-}\)is : [RBQ]

1 +1
2 +2
3 +3
4 +4
NCERT-XI-240
6 RBTS PAPER

163224 Match List-I (compound) with List-II (Oxidation state of \(\mathrm{N}\) ) and select the correct answer using the codes given below the list :


























List-I List-II
a. \(\mathrm{KNO}_3\) i. \(-1 / 3\)
b. \(\mathrm{HNO}_2\) ii. -3
c. \(\mathrm{NH}_4 \mathrm{Cl}\) iii. 0
d. \(\mathrm{NaN}_3\) iv. +3
v. +5

[RBQ]

1 a-v, b-iv, c-ii, d-i
2 a-v, b-ii, c-iv, d-i
3 a-iv, b-v, c-i, d-iii
4 a-ii, b-iii, c-iv, d-v
NCERT-XI-240
NEET DIGITAL LIBRARY