163863
\(200 \mathrm{ml} \mathrm{M} / 10, \mathrm{H}_2 \mathrm{SO}_4\) is mixed with \(300 \mathrm{ml} \mathrm{M} / 10\), \(\mathrm{NaOH}\) solution. The molarity of \(\mathrm{H}_2 \mathrm{SO}_4\) in resulting solution will be :
1 \(0.01 \mathrm{M}\)
2 \(0.02 \mathrm{M}\)
3 \(0.03 \mathrm{M}\)
4 \(0.04 \mathrm{M}\)
Explanation:
Mili-moles of \(\mathrm{H}_2 \mathrm{SO}_4\) in residual solution \(=5\) Volume of residual solution \(=500 \mathrm{ml}\) Therefore molarity of \(\mathrm{H}_2 \mathrm{SO}_4\) in resulting solution \(=0.01 \mathrm{M}\)
NCERT-XII-04
4 RBTS PAPER
163864
The example of positive deviation of :
1 \(\mathrm{CH}_3 \mathrm{COOH}\) and water
2 \(\mathrm{NaOH}\) and water
3 Ethyl alcohol \& water
4 Nitric acid and water
Explanation:
Ethyl alcohol and water are the example of \(+\mathrm{ve}\) deviation.
163863
\(200 \mathrm{ml} \mathrm{M} / 10, \mathrm{H}_2 \mathrm{SO}_4\) is mixed with \(300 \mathrm{ml} \mathrm{M} / 10\), \(\mathrm{NaOH}\) solution. The molarity of \(\mathrm{H}_2 \mathrm{SO}_4\) in resulting solution will be :
1 \(0.01 \mathrm{M}\)
2 \(0.02 \mathrm{M}\)
3 \(0.03 \mathrm{M}\)
4 \(0.04 \mathrm{M}\)
Explanation:
Mili-moles of \(\mathrm{H}_2 \mathrm{SO}_4\) in residual solution \(=5\) Volume of residual solution \(=500 \mathrm{ml}\) Therefore molarity of \(\mathrm{H}_2 \mathrm{SO}_4\) in resulting solution \(=0.01 \mathrm{M}\)
NCERT-XII-04
4 RBTS PAPER
163864
The example of positive deviation of :
1 \(\mathrm{CH}_3 \mathrm{COOH}\) and water
2 \(\mathrm{NaOH}\) and water
3 Ethyl alcohol \& water
4 Nitric acid and water
Explanation:
Ethyl alcohol and water are the example of \(+\mathrm{ve}\) deviation.
