QBManager

4 RBTS PAPER

163831 Osmotic pressure of $0.585 % w / v NaCl$ solution at $27^{\circ} C$ is:

1

2.49 atm

2

4.92 atm

3

1.2 atm

4

3.8 atm

Explanation:

$π = i C R T$
$π = 2 \times \frac{0.585}{58.5 \times 0.1} \times 0.0821 \times 300$
$π = 4.92 atm$

NCERT-XII-21

4 RBTS PAPER

163832 Which one of the following pairs of solutions will be expected to be isotonic under the same temperature?

1

0.1 M

urea and

0.1 M NaCl

2

0.1 M

urea and

0.2 M {MgCl}_{2}

3

0.1 M NaCl

and

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M Ca {({NO}_{3})}_{2}

and

0.1 M {Na}_{2} {SO}_{4}

Explanation:

$0.1 M Ca {({NO}_{3})}_{2}$
$π = iCRT$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$
$0.1 M {Na}_{2} {SO}_{4}$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$

NCERT-XII-21

4 RBTS PAPER

163833 Which of the following $0.1 M$ aqueous solutions will have the lowest freezing point:

1 Potassium Sulphate

2 Sodium Chloride

3 Urea

4 Glucose

Explanation:

(1) $K_{2} {SO}_{4}$
(2) $NaCl$
$i = 3$
$i = 2$
(3) यूरिया
(4) ग्लूकोज
$i = 1$
$i = 1$
$i \propto \frac{1}{F.P}$

NCERT-XII-24

4 RBTS PAPER

163834 Which solution will have least vapour pressure:

1

0.1 M {BaCl}_{2}

2

0.1 M

urea

3

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M {Na}_{3} {PO}_{4}

Explanation:

(1) ${BaCl}_{2}$
$i = 3$
(3) ${Na}_{2} {SO}_{4}$
$i = 3$
(2) यूरिया
$i = 1$
(4)
${Na}_{3} {PO}_{4}$
$i = 4$
${Na}_{3} {PO}_{4} = 3 {Na}^{+} + {PO}_{4}^{3 -}$
$i \propto \frac{1}{V . P}$

NCERT-XII-24

4 RBTS PAPER

163831 Osmotic pressure of $0.585 % w / v NaCl$ solution at $27^{\circ} C$ is:

1

2.49 atm

2

4.92 atm

3

1.2 atm

4

3.8 atm

Explanation:

$π = i C R T$
$π = 2 \times \frac{0.585}{58.5 \times 0.1} \times 0.0821 \times 300$
$π = 4.92 atm$

NCERT-XII-21

4 RBTS PAPER

163832 Which one of the following pairs of solutions will be expected to be isotonic under the same temperature?

1

0.1 M

urea and

0.1 M NaCl

2

0.1 M

urea and

0.2 M {MgCl}_{2}

3

0.1 M NaCl

and

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M Ca {({NO}_{3})}_{2}

and

0.1 M {Na}_{2} {SO}_{4}

Explanation:

$0.1 M Ca {({NO}_{3})}_{2}$
$π = iCRT$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$
$0.1 M {Na}_{2} {SO}_{4}$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$

NCERT-XII-21

4 RBTS PAPER

163833 Which of the following $0.1 M$ aqueous solutions will have the lowest freezing point:

1 Potassium Sulphate

2 Sodium Chloride

3 Urea

4 Glucose

Explanation:

(1) $K_{2} {SO}_{4}$
(2) $NaCl$
$i = 3$
$i = 2$
(3) यूरिया
(4) ग्लूकोज
$i = 1$
$i = 1$
$i \propto \frac{1}{F.P}$

NCERT-XII-24

4 RBTS PAPER

163834 Which solution will have least vapour pressure:

1

0.1 M {BaCl}_{2}

2

0.1 M

urea

3

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M {Na}_{3} {PO}_{4}

Explanation:

(1) ${BaCl}_{2}$
$i = 3$
(3) ${Na}_{2} {SO}_{4}$
$i = 3$
(2) यूरिया
$i = 1$
(4)
${Na}_{3} {PO}_{4}$
$i = 4$
${Na}_{3} {PO}_{4} = 3 {Na}^{+} + {PO}_{4}^{3 -}$
$i \propto \frac{1}{V . P}$

NCERT-XII-24

4 RBTS PAPER

163831 Osmotic pressure of $0.585 % w / v NaCl$ solution at $27^{\circ} C$ is:

1

2.49 atm

2

4.92 atm

3

1.2 atm

4

3.8 atm

Explanation:

$π = i C R T$
$π = 2 \times \frac{0.585}{58.5 \times 0.1} \times 0.0821 \times 300$
$π = 4.92 atm$

NCERT-XII-21

4 RBTS PAPER

163832 Which one of the following pairs of solutions will be expected to be isotonic under the same temperature?

1

0.1 M

urea and

0.1 M NaCl

2

0.1 M

urea and

0.2 M {MgCl}_{2}

3

0.1 M NaCl

and

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M Ca {({NO}_{3})}_{2}

and

0.1 M {Na}_{2} {SO}_{4}

Explanation:

$0.1 M Ca {({NO}_{3})}_{2}$
$π = iCRT$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$
$0.1 M {Na}_{2} {SO}_{4}$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$

NCERT-XII-21

4 RBTS PAPER

163833 Which of the following $0.1 M$ aqueous solutions will have the lowest freezing point:

1 Potassium Sulphate

2 Sodium Chloride

3 Urea

4 Glucose

Explanation:

(1) $K_{2} {SO}_{4}$
(2) $NaCl$
$i = 3$
$i = 2$
(3) यूरिया
(4) ग्लूकोज
$i = 1$
$i = 1$
$i \propto \frac{1}{F.P}$

NCERT-XII-24

4 RBTS PAPER

163834 Which solution will have least vapour pressure:

1

0.1 M {BaCl}_{2}

2

0.1 M

urea

3

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M {Na}_{3} {PO}_{4}

Explanation:

(1) ${BaCl}_{2}$
$i = 3$
(3) ${Na}_{2} {SO}_{4}$
$i = 3$
(2) यूरिया
$i = 1$
(4)
${Na}_{3} {PO}_{4}$
$i = 4$
${Na}_{3} {PO}_{4} = 3 {Na}^{+} + {PO}_{4}^{3 -}$
$i \propto \frac{1}{V . P}$

NCERT-XII-24

4 RBTS PAPER

163831 Osmotic pressure of $0.585 % w / v NaCl$ solution at $27^{\circ} C$ is:

1

2.49 atm

2

4.92 atm

3

1.2 atm

4

3.8 atm

Explanation:

$π = i C R T$
$π = 2 \times \frac{0.585}{58.5 \times 0.1} \times 0.0821 \times 300$
$π = 4.92 atm$

NCERT-XII-21

4 RBTS PAPER

163832 Which one of the following pairs of solutions will be expected to be isotonic under the same temperature?

1

0.1 M

urea and

0.1 M NaCl

2

0.1 M

urea and

0.2 M {MgCl}_{2}

3

0.1 M NaCl

and

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M Ca {({NO}_{3})}_{2}

and

0.1 M {Na}_{2} {SO}_{4}

Explanation:

$0.1 M Ca {({NO}_{3})}_{2}$
$π = iCRT$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$
$0.1 M {Na}_{2} {SO}_{4}$
$π = 3 \times 0.1 \times RT$
$π = 0.3 RT$

NCERT-XII-21

4 RBTS PAPER

163833 Which of the following $0.1 M$ aqueous solutions will have the lowest freezing point:

1 Potassium Sulphate

2 Sodium Chloride

3 Urea

4 Glucose

Explanation:

(1) $K_{2} {SO}_{4}$
(2) $NaCl$
$i = 3$
$i = 2$
(3) यूरिया
(4) ग्लूकोज
$i = 1$
$i = 1$
$i \propto \frac{1}{F.P}$

NCERT-XII-24

4 RBTS PAPER

163834 Which solution will have least vapour pressure:

1

0.1 M {BaCl}_{2}

2

0.1 M

urea

3

0.1 M {Na}_{2} {SO}_{4}

4

0.1 M {Na}_{3} {PO}_{4}

Explanation:

(1) ${BaCl}_{2}$
$i = 3$
(3) ${Na}_{2} {SO}_{4}$
$i = 3$
(2) यूरिया
$i = 1$
(4)
${Na}_{3} {PO}_{4}$
$i = 4$
${Na}_{3} {PO}_{4} = 3 {Na}^{+} + {PO}_{4}^{3 -}$
$i \propto \frac{1}{V . P}$

NCERT-XII-24

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