NEET Test Series from KOTA - 10 Papers In MS WORD
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3 RBTS PAPER
162603
What is the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of \(10 \mathrm{~cm}\) ? (Take \(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2\) )
162604
A frictionless track \(A B C D E\) ends in a circular loop of radius \(R\). A body slides down the track from point \(A\) which is at a height \(h=5 \mathrm{~cm}\). Maximum value of \(\mathbf{R}\) for the body to successfully complete the loop is
1 \(5 \mathrm{~cm}\).
2 \(2 \mathrm{~cm}\).
3 \(\frac{10}{3} \mathrm{~cm}\).
4 \(\frac{15}{4} \mathrm{~cm}\).
Explanation:
For just completing vertical circle. Velocity at lowest point of track \(v=\sqrt{5 g R}\) Now from conservation of energy \( 0+M g h=\frac{1}{2} M^2+0 \) \( h=\frac{1}{2 g} \times 5 \mathrm{gR} \) \( \mathrm{R}=\frac{2 \mathrm{~h}}{5}=\frac{2 \times 5}{5} \Rightarrow \mathrm{R}=2 \mathrm{~cm} \)
NCERT-I- 79
3 RBTS PAPER
162606
Figure shows a plot of the potential energy as a function of \(x\) for a particle moving along the \(x\)-axis : Which of the following statement(s) is/are true?
1 a, c and d are points of equilibrium
2 a is a point of stable equilibrium
3 \(b\) is a unstable equilibrium point
4 All of the above
Explanation:
According to stable and unstable equilibrium theory.
NCERT-I-78
3 RBTS PAPER
162607
If the stone is thrown up vertically and return to ground, its potential energy is maximum :
1 During the upward journey
2 At the maximum height
3 During the return journey
4 At the bottom
Explanation:
Potential energy \(=\mathrm{mgh}\) Potential energy is maximum when \(h\) is maximum
162603
What is the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of \(10 \mathrm{~cm}\) ? (Take \(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2\) )
162604
A frictionless track \(A B C D E\) ends in a circular loop of radius \(R\). A body slides down the track from point \(A\) which is at a height \(h=5 \mathrm{~cm}\). Maximum value of \(\mathbf{R}\) for the body to successfully complete the loop is
1 \(5 \mathrm{~cm}\).
2 \(2 \mathrm{~cm}\).
3 \(\frac{10}{3} \mathrm{~cm}\).
4 \(\frac{15}{4} \mathrm{~cm}\).
Explanation:
For just completing vertical circle. Velocity at lowest point of track \(v=\sqrt{5 g R}\) Now from conservation of energy \( 0+M g h=\frac{1}{2} M^2+0 \) \( h=\frac{1}{2 g} \times 5 \mathrm{gR} \) \( \mathrm{R}=\frac{2 \mathrm{~h}}{5}=\frac{2 \times 5}{5} \Rightarrow \mathrm{R}=2 \mathrm{~cm} \)
NCERT-I- 79
3 RBTS PAPER
162606
Figure shows a plot of the potential energy as a function of \(x\) for a particle moving along the \(x\)-axis : Which of the following statement(s) is/are true?
1 a, c and d are points of equilibrium
2 a is a point of stable equilibrium
3 \(b\) is a unstable equilibrium point
4 All of the above
Explanation:
According to stable and unstable equilibrium theory.
NCERT-I-78
3 RBTS PAPER
162607
If the stone is thrown up vertically and return to ground, its potential energy is maximum :
1 During the upward journey
2 At the maximum height
3 During the return journey
4 At the bottom
Explanation:
Potential energy \(=\mathrm{mgh}\) Potential energy is maximum when \(h\) is maximum
162603
What is the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of \(10 \mathrm{~cm}\) ? (Take \(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2\) )
162604
A frictionless track \(A B C D E\) ends in a circular loop of radius \(R\). A body slides down the track from point \(A\) which is at a height \(h=5 \mathrm{~cm}\). Maximum value of \(\mathbf{R}\) for the body to successfully complete the loop is
1 \(5 \mathrm{~cm}\).
2 \(2 \mathrm{~cm}\).
3 \(\frac{10}{3} \mathrm{~cm}\).
4 \(\frac{15}{4} \mathrm{~cm}\).
Explanation:
For just completing vertical circle. Velocity at lowest point of track \(v=\sqrt{5 g R}\) Now from conservation of energy \( 0+M g h=\frac{1}{2} M^2+0 \) \( h=\frac{1}{2 g} \times 5 \mathrm{gR} \) \( \mathrm{R}=\frac{2 \mathrm{~h}}{5}=\frac{2 \times 5}{5} \Rightarrow \mathrm{R}=2 \mathrm{~cm} \)
NCERT-I- 79
3 RBTS PAPER
162606
Figure shows a plot of the potential energy as a function of \(x\) for a particle moving along the \(x\)-axis : Which of the following statement(s) is/are true?
1 a, c and d are points of equilibrium
2 a is a point of stable equilibrium
3 \(b\) is a unstable equilibrium point
4 All of the above
Explanation:
According to stable and unstable equilibrium theory.
NCERT-I-78
3 RBTS PAPER
162607
If the stone is thrown up vertically and return to ground, its potential energy is maximum :
1 During the upward journey
2 At the maximum height
3 During the return journey
4 At the bottom
Explanation:
Potential energy \(=\mathrm{mgh}\) Potential energy is maximum when \(h\) is maximum
162603
What is the velocity of the bob of a simple pendulum at its mean position if it is able to rise to a vertical height of \(10 \mathrm{~cm}\) ? (Take \(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2\) )
162604
A frictionless track \(A B C D E\) ends in a circular loop of radius \(R\). A body slides down the track from point \(A\) which is at a height \(h=5 \mathrm{~cm}\). Maximum value of \(\mathbf{R}\) for the body to successfully complete the loop is
1 \(5 \mathrm{~cm}\).
2 \(2 \mathrm{~cm}\).
3 \(\frac{10}{3} \mathrm{~cm}\).
4 \(\frac{15}{4} \mathrm{~cm}\).
Explanation:
For just completing vertical circle. Velocity at lowest point of track \(v=\sqrt{5 g R}\) Now from conservation of energy \( 0+M g h=\frac{1}{2} M^2+0 \) \( h=\frac{1}{2 g} \times 5 \mathrm{gR} \) \( \mathrm{R}=\frac{2 \mathrm{~h}}{5}=\frac{2 \times 5}{5} \Rightarrow \mathrm{R}=2 \mathrm{~cm} \)
NCERT-I- 79
3 RBTS PAPER
162606
Figure shows a plot of the potential energy as a function of \(x\) for a particle moving along the \(x\)-axis : Which of the following statement(s) is/are true?
1 a, c and d are points of equilibrium
2 a is a point of stable equilibrium
3 \(b\) is a unstable equilibrium point
4 All of the above
Explanation:
According to stable and unstable equilibrium theory.
NCERT-I-78
3 RBTS PAPER
162607
If the stone is thrown up vertically and return to ground, its potential energy is maximum :
1 During the upward journey
2 At the maximum height
3 During the return journey
4 At the bottom
Explanation:
Potential energy \(=\mathrm{mgh}\) Potential energy is maximum when \(h\) is maximum
