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3 RBTS PAPER

162567 A body is onithy at rest. It undergoes one dimensions ingtion with constant acceleration. The Power delerved to it at time $t$ is proportional

1

t^{1 / 2}

2

t

3

t^{3 / 2}

4

t^{2}

NCERT-I-90

3 RBTS PAPER

162568 Two particles are seen to collide and move jointly together after the collision. During such a collision, for the total system

1 neither the mechanical energy nor the linear momentum is conserved

2 both the mechanical energy and the linear momentum are conserved

3 mechanical energy is conserved, but not the linear momentum

4 linear momentum is conserved, but not the mechanical energy

NCERT-I-84

3 RBTS PAPER

162569 A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled $3 m$ is :

1

6.5 J

2

2.5 J

3

4 J

4

5 J

.

Explanation:

According to work energy theorem
Work done by force on the particle $=$ change in $KE$
Work done $=$ Area under F-x graph
$\int F . dx = 2 \times 2 + \frac{(2 + 3) \times 1}{2}$
$W = {KE}_{final} - {KE}_{initial} = 6.5$
${KE}_{initial} = 0$
${KE}_{final} = 6.5 J .$

NCERT-I-76

3 RBTS PAPER

162570 Consider a force vector $\vec{F} = - x \hat{i} + y \hat{j}$ . The work done by this force in moving a particle from point $A (1, 0)$ to $B (0, 1)$ along the line segment is :

1 2

2 1

3

3 / 2

4

1 / 2

Explanation:

$Misplaced &$
$Misplaced &$
$= - (\frac{0^{2}}{2} - \frac{1^{2}}{2}) + (\frac{1^{2}}{2} - \frac{0^{2}}{2}) \Rightarrow W = 1 J$

NCERT-I-76

3 RBTS PAPER

162567 A body is onithy at rest. It undergoes one dimensions ingtion with constant acceleration. The Power delerved to it at time $t$ is proportional

1

t^{1 / 2}

2

t

3

t^{3 / 2}

4

t^{2}

NCERT-I-90

3 RBTS PAPER

162568 Two particles are seen to collide and move jointly together after the collision. During such a collision, for the total system

1 neither the mechanical energy nor the linear momentum is conserved

2 both the mechanical energy and the linear momentum are conserved

3 mechanical energy is conserved, but not the linear momentum

4 linear momentum is conserved, but not the mechanical energy

NCERT-I-84

3 RBTS PAPER

162569 A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled $3 m$ is :

1

6.5 J

2

2.5 J

3

4 J

4

5 J

.

Explanation:

According to work energy theorem
Work done by force on the particle $=$ change in $KE$
Work done $=$ Area under F-x graph
$\int F . dx = 2 \times 2 + \frac{(2 + 3) \times 1}{2}$
$W = {KE}_{final} - {KE}_{initial} = 6.5$
${KE}_{initial} = 0$
${KE}_{final} = 6.5 J .$

NCERT-I-76

3 RBTS PAPER

162570 Consider a force vector $\vec{F} = - x \hat{i} + y \hat{j}$ . The work done by this force in moving a particle from point $A (1, 0)$ to $B (0, 1)$ along the line segment is :

1 2

2 1

3

3 / 2

4

1 / 2

Explanation:

$Misplaced &$
$Misplaced &$
$= - (\frac{0^{2}}{2} - \frac{1^{2}}{2}) + (\frac{1^{2}}{2} - \frac{0^{2}}{2}) \Rightarrow W = 1 J$

NCERT-I-76

3 RBTS PAPER

162567 A body is onithy at rest. It undergoes one dimensions ingtion with constant acceleration. The Power delerved to it at time $t$ is proportional

1

t^{1 / 2}

2

t

3

t^{3 / 2}

4

t^{2}

NCERT-I-90

3 RBTS PAPER

162568 Two particles are seen to collide and move jointly together after the collision. During such a collision, for the total system

1 neither the mechanical energy nor the linear momentum is conserved

2 both the mechanical energy and the linear momentum are conserved

3 mechanical energy is conserved, but not the linear momentum

4 linear momentum is conserved, but not the mechanical energy

NCERT-I-84

3 RBTS PAPER

162569 A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled $3 m$ is :

1

6.5 J

2

2.5 J

3

4 J

4

5 J

.

Explanation:

According to work energy theorem
Work done by force on the particle $=$ change in $KE$
Work done $=$ Area under F-x graph
$\int F . dx = 2 \times 2 + \frac{(2 + 3) \times 1}{2}$
$W = {KE}_{final} - {KE}_{initial} = 6.5$
${KE}_{initial} = 0$
${KE}_{final} = 6.5 J .$

NCERT-I-76

3 RBTS PAPER

162570 Consider a force vector $\vec{F} = - x \hat{i} + y \hat{j}$ . The work done by this force in moving a particle from point $A (1, 0)$ to $B (0, 1)$ along the line segment is :

1 2

2 1

3

3 / 2

4

1 / 2

Explanation:

$Misplaced &$
$Misplaced &$
$= - (\frac{0^{2}}{2} - \frac{1^{2}}{2}) + (\frac{1^{2}}{2} - \frac{0^{2}}{2}) \Rightarrow W = 1 J$

NCERT-I-76

3 RBTS PAPER

162567 A body is onithy at rest. It undergoes one dimensions ingtion with constant acceleration. The Power delerved to it at time $t$ is proportional

1

t^{1 / 2}

2

t

3

t^{3 / 2}

4

t^{2}

NCERT-I-90

3 RBTS PAPER

162568 Two particles are seen to collide and move jointly together after the collision. During such a collision, for the total system

1 neither the mechanical energy nor the linear momentum is conserved

2 both the mechanical energy and the linear momentum are conserved

3 mechanical energy is conserved, but not the linear momentum

4 linear momentum is conserved, but not the mechanical energy

NCERT-I-84

3 RBTS PAPER

162569 A particle moves in one dimension from rest under the influence of a force that varies with the distance travelled by the particle as shown in the figure. The kinetic energy of the particle after it has travelled $3 m$ is :

1

6.5 J

2

2.5 J

3

4 J

4

5 J

.

Explanation:

According to work energy theorem
Work done by force on the particle $=$ change in $KE$
Work done $=$ Area under F-x graph
$\int F . dx = 2 \times 2 + \frac{(2 + 3) \times 1}{2}$
$W = {KE}_{final} - {KE}_{initial} = 6.5$
${KE}_{initial} = 0$
${KE}_{final} = 6.5 J .$

NCERT-I-76

3 RBTS PAPER

162570 Consider a force vector $\vec{F} = - x \hat{i} + y \hat{j}$ . The work done by this force in moving a particle from point $A (1, 0)$ to $B (0, 1)$ along the line segment is :

1 2

2 1

3

3 / 2

4

1 / 2

Explanation:

$Misplaced &$
$Misplaced &$
$= - (\frac{0^{2}}{2} - \frac{1^{2}}{2}) + (\frac{1^{2}}{2} - \frac{0^{2}}{2}) \Rightarrow W = 1 J$

NCERT-I-76

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