Semiconductor Electronics Material Devices and Simple Circuits
151353
The output of given logic circuit is :
1 A. (B + C)
2 A. (B . C)
3 \((A+B) \cdot(A+C)\)
4 \(\mathrm{A}+\mathrm{B}+\mathrm{C}\)
Explanation:
C Given logic circuit Then the Boolean expression will be \(y=(A+B) \cdot(A+C)\)
Karnataka CET-2011
Semiconductor Electronics Material Devices and Simple Circuits
151354
Identify the logic operation performed by the circuit given here :
1 OR
2 NOR
3 NOT
4 NAND
Explanation:
B Given that logic operation will be Then Boolean expression will be \(y=\overline{\overline{A+B}}\) \(y=A+B\)So, this is OR gate.
Karnataka CET-2010
Semiconductor Electronics Material Devices and Simple Circuits
151355
To get an output \(Y=1\) from the circuit shown, the inputs \(A, B\) and \(C\) must be respectively :
1 \(0,1,0\)
2 \(1,0,0\)
3 \(1,0,1\)
4 \(1,1,0\)
Explanation:
C In the given, circuit the output \(\mathrm{y}=1\) when the volume of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\), will be - which indicates NOT gate,
AMUAOU5SxJOOI8DQ.original.fullsize.png)
Semiconductor Electronics Material Devices and Simple Circuits
151356
Indentify the true statement of OR gate.
1 Output Y will be 1 when the input A or B or both are 1 .
2 Output \(\mathrm{Y}\) will be 0 when either of the inputs \(\mathrm{A}\) or \(\mathrm{B}\) is 1 .
3 Output \(\mathrm{Y}\) will be 1 only when both the inputs \(\mathrm{A}\) and \(\mathrm{B}\) are 1 .
4 Output Y will be 1 only when either of the inputs A or B is 1 .
Explanation:
B In OR gate operation \(\mathrm{y}=\mathrm{A}+\mathrm{B}\) So, by Truth table Output y will be 1 when the input A or B or both are 1 Truth table of OR gate is- {|c|c|c|} | \(\) \(\) \(=\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \(
Semiconductor Electronics Material Devices and Simple Circuits
151353
The output of given logic circuit is :
1 A. (B + C)
2 A. (B . C)
3 \((A+B) \cdot(A+C)\)
4 \(\mathrm{A}+\mathrm{B}+\mathrm{C}\)
Explanation:
C Given logic circuit Then the Boolean expression will be \(y=(A+B) \cdot(A+C)\)
Karnataka CET-2011
Semiconductor Electronics Material Devices and Simple Circuits
151354
Identify the logic operation performed by the circuit given here :
1 OR
2 NOR
3 NOT
4 NAND
Explanation:
B Given that logic operation will be Then Boolean expression will be \(y=\overline{\overline{A+B}}\) \(y=A+B\)So, this is OR gate.
Karnataka CET-2010
Semiconductor Electronics Material Devices and Simple Circuits
151355
To get an output \(Y=1\) from the circuit shown, the inputs \(A, B\) and \(C\) must be respectively :
1 \(0,1,0\)
2 \(1,0,0\)
3 \(1,0,1\)
4 \(1,1,0\)
Explanation:
C In the given, circuit the output \(\mathrm{y}=1\) when the volume of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\), will be - which indicates NOT gate,
AMUAOU5SxJOOI8DQ.original.fullsize.png)
Semiconductor Electronics Material Devices and Simple Circuits
151356
Indentify the true statement of OR gate.
1 Output Y will be 1 when the input A or B or both are 1 .
2 Output \(\mathrm{Y}\) will be 0 when either of the inputs \(\mathrm{A}\) or \(\mathrm{B}\) is 1 .
3 Output \(\mathrm{Y}\) will be 1 only when both the inputs \(\mathrm{A}\) and \(\mathrm{B}\) are 1 .
4 Output Y will be 1 only when either of the inputs A or B is 1 .
Explanation:
B In OR gate operation \(\mathrm{y}=\mathrm{A}+\mathrm{B}\) So, by Truth table Output y will be 1 when the input A or B or both are 1 Truth table of OR gate is- {|c|c|c|} | \(\) \(\) \(=\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \(
Semiconductor Electronics Material Devices and Simple Circuits
151353
The output of given logic circuit is :
1 A. (B + C)
2 A. (B . C)
3 \((A+B) \cdot(A+C)\)
4 \(\mathrm{A}+\mathrm{B}+\mathrm{C}\)
Explanation:
C Given logic circuit Then the Boolean expression will be \(y=(A+B) \cdot(A+C)\)
Karnataka CET-2011
Semiconductor Electronics Material Devices and Simple Circuits
151354
Identify the logic operation performed by the circuit given here :
1 OR
2 NOR
3 NOT
4 NAND
Explanation:
B Given that logic operation will be Then Boolean expression will be \(y=\overline{\overline{A+B}}\) \(y=A+B\)So, this is OR gate.
Karnataka CET-2010
Semiconductor Electronics Material Devices and Simple Circuits
151355
To get an output \(Y=1\) from the circuit shown, the inputs \(A, B\) and \(C\) must be respectively :
1 \(0,1,0\)
2 \(1,0,0\)
3 \(1,0,1\)
4 \(1,1,0\)
Explanation:
C In the given, circuit the output \(\mathrm{y}=1\) when the volume of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\), will be - which indicates NOT gate,
AMUAOU5SxJOOI8DQ.original.fullsize.png)
Semiconductor Electronics Material Devices and Simple Circuits
151356
Indentify the true statement of OR gate.
1 Output Y will be 1 when the input A or B or both are 1 .
2 Output \(\mathrm{Y}\) will be 0 when either of the inputs \(\mathrm{A}\) or \(\mathrm{B}\) is 1 .
3 Output \(\mathrm{Y}\) will be 1 only when both the inputs \(\mathrm{A}\) and \(\mathrm{B}\) are 1 .
4 Output Y will be 1 only when either of the inputs A or B is 1 .
Explanation:
B In OR gate operation \(\mathrm{y}=\mathrm{A}+\mathrm{B}\) So, by Truth table Output y will be 1 when the input A or B or both are 1 Truth table of OR gate is- {|c|c|c|} | \(\) \(\) \(=\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \(
Semiconductor Electronics Material Devices and Simple Circuits
151353
The output of given logic circuit is :
1 A. (B + C)
2 A. (B . C)
3 \((A+B) \cdot(A+C)\)
4 \(\mathrm{A}+\mathrm{B}+\mathrm{C}\)
Explanation:
C Given logic circuit Then the Boolean expression will be \(y=(A+B) \cdot(A+C)\)
Karnataka CET-2011
Semiconductor Electronics Material Devices and Simple Circuits
151354
Identify the logic operation performed by the circuit given here :
1 OR
2 NOR
3 NOT
4 NAND
Explanation:
B Given that logic operation will be Then Boolean expression will be \(y=\overline{\overline{A+B}}\) \(y=A+B\)So, this is OR gate.
Karnataka CET-2010
Semiconductor Electronics Material Devices and Simple Circuits
151355
To get an output \(Y=1\) from the circuit shown, the inputs \(A, B\) and \(C\) must be respectively :
1 \(0,1,0\)
2 \(1,0,0\)
3 \(1,0,1\)
4 \(1,1,0\)
Explanation:
C In the given, circuit the output \(\mathrm{y}=1\) when the volume of \(\mathrm{A}, \mathrm{B}, \mathrm{C}\), will be - which indicates NOT gate,
AMUAOU5SxJOOI8DQ.original.fullsize.png)
Semiconductor Electronics Material Devices and Simple Circuits
151356
Indentify the true statement of OR gate.
1 Output Y will be 1 when the input A or B or both are 1 .
2 Output \(\mathrm{Y}\) will be 0 when either of the inputs \(\mathrm{A}\) or \(\mathrm{B}\) is 1 .
3 Output \(\mathrm{Y}\) will be 1 only when both the inputs \(\mathrm{A}\) and \(\mathrm{B}\) are 1 .
4 Output Y will be 1 only when either of the inputs A or B is 1 .
Explanation:
B In OR gate operation \(\mathrm{y}=\mathrm{A}+\mathrm{B}\) So, by Truth table Output y will be 1 when the input A or B or both are 1 Truth table of OR gate is- {|c|c|c|} | \(\) \(\) \(=\)\)| |---| \( 0 0 0\) \(0 1 1\) \(1 0 1\) \(1 1 1\) \(
