Semiconductor Electronics Material Devices and Simple Circuits
150726
In the following diagram, current in \(100 \Omega\), resistor will be
1 zero
2 \(10 \mathrm{~mA}\)
3 \(20 \mathrm{~mA}\)
4 \(50 \mathrm{~mA}\)
Explanation:
C Potential difference \(\mathrm{V}=3-1=2 \mathrm{~V}\) We know that, \(V=I R\) \(2=I \times 100\) \(I=\frac{2}{100}=\frac{1}{50} A=20 \mathrm{~mA}\)
CG PET- 2011
Semiconductor Electronics Material Devices and Simple Circuits
150731
In the following circuit, the equivalent resistance between \(A\) and \(B\) is
1 \((20 / 3) \Omega\)
2 \(10 \Omega\)
3 \(16 \Omega\)
4 \(20 \Omega\)
Explanation:
C Since diode behave as a open circuit. Since, A is at lower potential with respect to B. Hence both diodes are in reverse biasing. Then, \(\mathrm{R}_{\mathrm{eq}}=8+2+6=16 \Omega\)
AP EAMCET (23.09.2020) Shift-I
Semiconductor Electronics Material Devices and Simple Circuits
150729
If the input is given between \(A\) and \(C\), then the output at the ends of \(R\) will be
1 fully rectified
2 half rectified
3 \(\mathrm{AC}\)
4 None of these
Explanation:
B Since in the given circuit use four diode, in which two is in forward biased and two is reversed biased. So this circuit is fully rectified.
CG PET- 2006
Semiconductor Electronics Material Devices and Simple Circuits
150732
Assuming that the junction diode is ideal, the current in the arrangement shown in the circuit diagram is.
1 \(2 \mathrm{~mA}\)
2 \(20 \mathrm{~mA}\)
3 \(30 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B By ohm's law, \(V =I R\) \(I =\frac{V}{R}\) \(=\frac{3-1}{100}\) \(=\frac{2}{100}\) \(=\frac{20}{1000}=20 \times 10^{-3} \mathrm{~A}\) \(=20 \mathrm{~mA}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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Semiconductor Electronics Material Devices and Simple Circuits
150726
In the following diagram, current in \(100 \Omega\), resistor will be
1 zero
2 \(10 \mathrm{~mA}\)
3 \(20 \mathrm{~mA}\)
4 \(50 \mathrm{~mA}\)
Explanation:
C Potential difference \(\mathrm{V}=3-1=2 \mathrm{~V}\) We know that, \(V=I R\) \(2=I \times 100\) \(I=\frac{2}{100}=\frac{1}{50} A=20 \mathrm{~mA}\)
CG PET- 2011
Semiconductor Electronics Material Devices and Simple Circuits
150731
In the following circuit, the equivalent resistance between \(A\) and \(B\) is
1 \((20 / 3) \Omega\)
2 \(10 \Omega\)
3 \(16 \Omega\)
4 \(20 \Omega\)
Explanation:
C Since diode behave as a open circuit. Since, A is at lower potential with respect to B. Hence both diodes are in reverse biasing. Then, \(\mathrm{R}_{\mathrm{eq}}=8+2+6=16 \Omega\)
AP EAMCET (23.09.2020) Shift-I
Semiconductor Electronics Material Devices and Simple Circuits
150729
If the input is given between \(A\) and \(C\), then the output at the ends of \(R\) will be
1 fully rectified
2 half rectified
3 \(\mathrm{AC}\)
4 None of these
Explanation:
B Since in the given circuit use four diode, in which two is in forward biased and two is reversed biased. So this circuit is fully rectified.
CG PET- 2006
Semiconductor Electronics Material Devices and Simple Circuits
150732
Assuming that the junction diode is ideal, the current in the arrangement shown in the circuit diagram is.
1 \(2 \mathrm{~mA}\)
2 \(20 \mathrm{~mA}\)
3 \(30 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B By ohm's law, \(V =I R\) \(I =\frac{V}{R}\) \(=\frac{3-1}{100}\) \(=\frac{2}{100}\) \(=\frac{20}{1000}=20 \times 10^{-3} \mathrm{~A}\) \(=20 \mathrm{~mA}\)
Semiconductor Electronics Material Devices and Simple Circuits
150726
In the following diagram, current in \(100 \Omega\), resistor will be
1 zero
2 \(10 \mathrm{~mA}\)
3 \(20 \mathrm{~mA}\)
4 \(50 \mathrm{~mA}\)
Explanation:
C Potential difference \(\mathrm{V}=3-1=2 \mathrm{~V}\) We know that, \(V=I R\) \(2=I \times 100\) \(I=\frac{2}{100}=\frac{1}{50} A=20 \mathrm{~mA}\)
CG PET- 2011
Semiconductor Electronics Material Devices and Simple Circuits
150731
In the following circuit, the equivalent resistance between \(A\) and \(B\) is
1 \((20 / 3) \Omega\)
2 \(10 \Omega\)
3 \(16 \Omega\)
4 \(20 \Omega\)
Explanation:
C Since diode behave as a open circuit. Since, A is at lower potential with respect to B. Hence both diodes are in reverse biasing. Then, \(\mathrm{R}_{\mathrm{eq}}=8+2+6=16 \Omega\)
AP EAMCET (23.09.2020) Shift-I
Semiconductor Electronics Material Devices and Simple Circuits
150729
If the input is given between \(A\) and \(C\), then the output at the ends of \(R\) will be
1 fully rectified
2 half rectified
3 \(\mathrm{AC}\)
4 None of these
Explanation:
B Since in the given circuit use four diode, in which two is in forward biased and two is reversed biased. So this circuit is fully rectified.
CG PET- 2006
Semiconductor Electronics Material Devices and Simple Circuits
150732
Assuming that the junction diode is ideal, the current in the arrangement shown in the circuit diagram is.
1 \(2 \mathrm{~mA}\)
2 \(20 \mathrm{~mA}\)
3 \(30 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B By ohm's law, \(V =I R\) \(I =\frac{V}{R}\) \(=\frac{3-1}{100}\) \(=\frac{2}{100}\) \(=\frac{20}{1000}=20 \times 10^{-3} \mathrm{~A}\) \(=20 \mathrm{~mA}\)
Semiconductor Electronics Material Devices and Simple Circuits
150726
In the following diagram, current in \(100 \Omega\), resistor will be
1 zero
2 \(10 \mathrm{~mA}\)
3 \(20 \mathrm{~mA}\)
4 \(50 \mathrm{~mA}\)
Explanation:
C Potential difference \(\mathrm{V}=3-1=2 \mathrm{~V}\) We know that, \(V=I R\) \(2=I \times 100\) \(I=\frac{2}{100}=\frac{1}{50} A=20 \mathrm{~mA}\)
CG PET- 2011
Semiconductor Electronics Material Devices and Simple Circuits
150731
In the following circuit, the equivalent resistance between \(A\) and \(B\) is
1 \((20 / 3) \Omega\)
2 \(10 \Omega\)
3 \(16 \Omega\)
4 \(20 \Omega\)
Explanation:
C Since diode behave as a open circuit. Since, A is at lower potential with respect to B. Hence both diodes are in reverse biasing. Then, \(\mathrm{R}_{\mathrm{eq}}=8+2+6=16 \Omega\)
AP EAMCET (23.09.2020) Shift-I
Semiconductor Electronics Material Devices and Simple Circuits
150729
If the input is given between \(A\) and \(C\), then the output at the ends of \(R\) will be
1 fully rectified
2 half rectified
3 \(\mathrm{AC}\)
4 None of these
Explanation:
B Since in the given circuit use four diode, in which two is in forward biased and two is reversed biased. So this circuit is fully rectified.
CG PET- 2006
Semiconductor Electronics Material Devices and Simple Circuits
150732
Assuming that the junction diode is ideal, the current in the arrangement shown in the circuit diagram is.
1 \(2 \mathrm{~mA}\)
2 \(20 \mathrm{~mA}\)
3 \(30 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B By ohm's law, \(V =I R\) \(I =\frac{V}{R}\) \(=\frac{3-1}{100}\) \(=\frac{2}{100}\) \(=\frac{20}{1000}=20 \times 10^{-3} \mathrm{~A}\) \(=20 \mathrm{~mA}\)
