NEET Test Series from KOTA - 10 Papers In MS WORD
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Semiconductor Electronics Material Devices and Simple Circuits
150836
The curve between charge density and distance near \(\mathrm{P}-\mathrm{N}\) junction will be
1
2
3
4
Explanation:
B Given that, In the depletion region of \(p-n\) junction positive charge exists in n-region and negative charge exist in p-region.
UP CPMT-2011
Semiconductor Electronics Material Devices and Simple Circuits
150839
In a half wave rectifier the \(\mathrm{AC}\) input source of frequency \(50 \mathrm{~Hz}\) is used. The fundamental frequency of the output is
1 \(50 \mathrm{~Hz}\)
2 \(150 \mathrm{~Hz}\)
3 \(200 \mathrm{~Hz}\)
4 \(75 \mathrm{~Hz}\)
Explanation:
B Given that, Input frequency \((f)=50 \mathrm{~Hz}\) \(\therefore\) Fundamental frequency of ripple for Half wave rectifier \(=\mathrm{f}\) \(=50 \mathrm{~Hz}\)
TS EAMCET (Engg.)-2015
Semiconductor Electronics Material Devices and Simple Circuits
150844
In a standard half wave rectifier using pn junction diode, if the voltage in the secondary of the transformer is \(12 \mathrm{~V}\) (a. c.) the average voltage (in \(\mathrm{V}\) ) output from the circuit is
1 \(\frac{12}{\sqrt{2} \pi}\)
2 \(\frac{12}{\pi}\)
3 \(\frac{12 \sqrt{2}}{\pi}\)
4 \(\frac{\pi}{6} \sqrt{2}\)
Explanation:
C Given that, Secondary voltage of transformer \(=12 \mathrm{~V}\) \(\therefore\) maximum voltage across secondary \(=12 \sqrt{2}\) \(\because\) average voltage, \(\mathrm{V}=\frac{\mathrm{V}_{\mathrm{m}}}{\pi}=\frac{12 \times \sqrt{2}}{\pi}\)
TS EAMCET 08.05.2019
Semiconductor Electronics Material Devices and Simple Circuits
150902
The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is \(10 \mathrm{~V}\). The DC component of the output voltage is
1 \(\frac{10}{\sqrt{2}} \mathrm{~V}\)
2 \(\frac{10}{\pi} \mathrm{V}\)
3 \(10 \mathrm{~V}\)
4 \(\frac{20}{\pi} \mathrm{V}\)
Explanation:
B For half wave rectifier \(P_{\text {avg }}=\frac{V_{\mathrm{m}}}{\pi}\) \(P_{\text {avg }}=\frac{10}{\pi} \mathrm{V} \quad\left(\because \mathrm{V}_{\mathrm{m}}=10 \mathrm{~V}\right)\)
Semiconductor Electronics Material Devices and Simple Circuits
150836
The curve between charge density and distance near \(\mathrm{P}-\mathrm{N}\) junction will be
1
2
3
4
Explanation:
B Given that, In the depletion region of \(p-n\) junction positive charge exists in n-region and negative charge exist in p-region.
UP CPMT-2011
Semiconductor Electronics Material Devices and Simple Circuits
150839
In a half wave rectifier the \(\mathrm{AC}\) input source of frequency \(50 \mathrm{~Hz}\) is used. The fundamental frequency of the output is
1 \(50 \mathrm{~Hz}\)
2 \(150 \mathrm{~Hz}\)
3 \(200 \mathrm{~Hz}\)
4 \(75 \mathrm{~Hz}\)
Explanation:
B Given that, Input frequency \((f)=50 \mathrm{~Hz}\) \(\therefore\) Fundamental frequency of ripple for Half wave rectifier \(=\mathrm{f}\) \(=50 \mathrm{~Hz}\)
TS EAMCET (Engg.)-2015
Semiconductor Electronics Material Devices and Simple Circuits
150844
In a standard half wave rectifier using pn junction diode, if the voltage in the secondary of the transformer is \(12 \mathrm{~V}\) (a. c.) the average voltage (in \(\mathrm{V}\) ) output from the circuit is
1 \(\frac{12}{\sqrt{2} \pi}\)
2 \(\frac{12}{\pi}\)
3 \(\frac{12 \sqrt{2}}{\pi}\)
4 \(\frac{\pi}{6} \sqrt{2}\)
Explanation:
C Given that, Secondary voltage of transformer \(=12 \mathrm{~V}\) \(\therefore\) maximum voltage across secondary \(=12 \sqrt{2}\) \(\because\) average voltage, \(\mathrm{V}=\frac{\mathrm{V}_{\mathrm{m}}}{\pi}=\frac{12 \times \sqrt{2}}{\pi}\)
TS EAMCET 08.05.2019
Semiconductor Electronics Material Devices and Simple Circuits
150902
The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is \(10 \mathrm{~V}\). The DC component of the output voltage is
1 \(\frac{10}{\sqrt{2}} \mathrm{~V}\)
2 \(\frac{10}{\pi} \mathrm{V}\)
3 \(10 \mathrm{~V}\)
4 \(\frac{20}{\pi} \mathrm{V}\)
Explanation:
B For half wave rectifier \(P_{\text {avg }}=\frac{V_{\mathrm{m}}}{\pi}\) \(P_{\text {avg }}=\frac{10}{\pi} \mathrm{V} \quad\left(\because \mathrm{V}_{\mathrm{m}}=10 \mathrm{~V}\right)\)
Semiconductor Electronics Material Devices and Simple Circuits
150836
The curve between charge density and distance near \(\mathrm{P}-\mathrm{N}\) junction will be
1
2
3
4
Explanation:
B Given that, In the depletion region of \(p-n\) junction positive charge exists in n-region and negative charge exist in p-region.
UP CPMT-2011
Semiconductor Electronics Material Devices and Simple Circuits
150839
In a half wave rectifier the \(\mathrm{AC}\) input source of frequency \(50 \mathrm{~Hz}\) is used. The fundamental frequency of the output is
1 \(50 \mathrm{~Hz}\)
2 \(150 \mathrm{~Hz}\)
3 \(200 \mathrm{~Hz}\)
4 \(75 \mathrm{~Hz}\)
Explanation:
B Given that, Input frequency \((f)=50 \mathrm{~Hz}\) \(\therefore\) Fundamental frequency of ripple for Half wave rectifier \(=\mathrm{f}\) \(=50 \mathrm{~Hz}\)
TS EAMCET (Engg.)-2015
Semiconductor Electronics Material Devices and Simple Circuits
150844
In a standard half wave rectifier using pn junction diode, if the voltage in the secondary of the transformer is \(12 \mathrm{~V}\) (a. c.) the average voltage (in \(\mathrm{V}\) ) output from the circuit is
1 \(\frac{12}{\sqrt{2} \pi}\)
2 \(\frac{12}{\pi}\)
3 \(\frac{12 \sqrt{2}}{\pi}\)
4 \(\frac{\pi}{6} \sqrt{2}\)
Explanation:
C Given that, Secondary voltage of transformer \(=12 \mathrm{~V}\) \(\therefore\) maximum voltage across secondary \(=12 \sqrt{2}\) \(\because\) average voltage, \(\mathrm{V}=\frac{\mathrm{V}_{\mathrm{m}}}{\pi}=\frac{12 \times \sqrt{2}}{\pi}\)
TS EAMCET 08.05.2019
Semiconductor Electronics Material Devices and Simple Circuits
150902
The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is \(10 \mathrm{~V}\). The DC component of the output voltage is
1 \(\frac{10}{\sqrt{2}} \mathrm{~V}\)
2 \(\frac{10}{\pi} \mathrm{V}\)
3 \(10 \mathrm{~V}\)
4 \(\frac{20}{\pi} \mathrm{V}\)
Explanation:
B For half wave rectifier \(P_{\text {avg }}=\frac{V_{\mathrm{m}}}{\pi}\) \(P_{\text {avg }}=\frac{10}{\pi} \mathrm{V} \quad\left(\because \mathrm{V}_{\mathrm{m}}=10 \mathrm{~V}\right)\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Semiconductor Electronics Material Devices and Simple Circuits
150836
The curve between charge density and distance near \(\mathrm{P}-\mathrm{N}\) junction will be
1
2
3
4
Explanation:
B Given that, In the depletion region of \(p-n\) junction positive charge exists in n-region and negative charge exist in p-region.
UP CPMT-2011
Semiconductor Electronics Material Devices and Simple Circuits
150839
In a half wave rectifier the \(\mathrm{AC}\) input source of frequency \(50 \mathrm{~Hz}\) is used. The fundamental frequency of the output is
1 \(50 \mathrm{~Hz}\)
2 \(150 \mathrm{~Hz}\)
3 \(200 \mathrm{~Hz}\)
4 \(75 \mathrm{~Hz}\)
Explanation:
B Given that, Input frequency \((f)=50 \mathrm{~Hz}\) \(\therefore\) Fundamental frequency of ripple for Half wave rectifier \(=\mathrm{f}\) \(=50 \mathrm{~Hz}\)
TS EAMCET (Engg.)-2015
Semiconductor Electronics Material Devices and Simple Circuits
150844
In a standard half wave rectifier using pn junction diode, if the voltage in the secondary of the transformer is \(12 \mathrm{~V}\) (a. c.) the average voltage (in \(\mathrm{V}\) ) output from the circuit is
1 \(\frac{12}{\sqrt{2} \pi}\)
2 \(\frac{12}{\pi}\)
3 \(\frac{12 \sqrt{2}}{\pi}\)
4 \(\frac{\pi}{6} \sqrt{2}\)
Explanation:
C Given that, Secondary voltage of transformer \(=12 \mathrm{~V}\) \(\therefore\) maximum voltage across secondary \(=12 \sqrt{2}\) \(\because\) average voltage, \(\mathrm{V}=\frac{\mathrm{V}_{\mathrm{m}}}{\pi}=\frac{12 \times \sqrt{2}}{\pi}\)
TS EAMCET 08.05.2019
Semiconductor Electronics Material Devices and Simple Circuits
150902
The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is \(10 \mathrm{~V}\). The DC component of the output voltage is
1 \(\frac{10}{\sqrt{2}} \mathrm{~V}\)
2 \(\frac{10}{\pi} \mathrm{V}\)
3 \(10 \mathrm{~V}\)
4 \(\frac{20}{\pi} \mathrm{V}\)
Explanation:
B For half wave rectifier \(P_{\text {avg }}=\frac{V_{\mathrm{m}}}{\pi}\) \(P_{\text {avg }}=\frac{10}{\pi} \mathrm{V} \quad\left(\because \mathrm{V}_{\mathrm{m}}=10 \mathrm{~V}\right)\)
