148057 If in a nuclear reactor using $U^{235}$ as fuel, the power output is $4.8 \mathrm{MW}$. The number of fissions per second is: [Energy released per fissions per fission of $\mathrm{U}^{235}=200 \mathrm{MeV}, \mathrm{l} \mathrm{eV}=\mathbf{1 . 6}$ $\left.\times 10^{-19} \mathrm{~J}\right]$
148057 If in a nuclear reactor using $U^{235}$ as fuel, the power output is $4.8 \mathrm{MW}$. The number of fissions per second is: [Energy released per fissions per fission of $\mathrm{U}^{235}=200 \mathrm{MeV}, \mathrm{l} \mathrm{eV}=\mathbf{1 . 6}$ $\left.\times 10^{-19} \mathrm{~J}\right]$
148057 If in a nuclear reactor using $U^{235}$ as fuel, the power output is $4.8 \mathrm{MW}$. The number of fissions per second is: [Energy released per fissions per fission of $\mathrm{U}^{235}=200 \mathrm{MeV}, \mathrm{l} \mathrm{eV}=\mathbf{1 . 6}$ $\left.\times 10^{-19} \mathrm{~J}\right]$
148057 If in a nuclear reactor using $U^{235}$ as fuel, the power output is $4.8 \mathrm{MW}$. The number of fissions per second is: [Energy released per fissions per fission of $\mathrm{U}^{235}=200 \mathrm{MeV}, \mathrm{l} \mathrm{eV}=\mathbf{1 . 6}$ $\left.\times 10^{-19} \mathrm{~J}\right]$