Combination of Capacitor
Capacitance

165804 The capacity of a parallel plate capacitor with no dielectric but with a separation $0.4 \mathrm{~cm}$ is $2 \mu \mathrm{F}$. The separation is reduced to half and it is filled with a dielectric of value 2.8 . The final capacity of the capacitor is:

1 $11.2 \mu \mathrm{F}$
2 $5.6 \mu \mathrm{F}$
3 $4.0 \mu \mathrm{F}$
4 $22.4 \mu \mathrm{F}$
Capacitance

165805 Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

1 $1: 1$
2 $1: 2$
3 $1: 3$
4 $1: 4$
Capacitance

165806 What is the total capacitance of the combination when 3 capacitors each of capacitance 9 pF are connected in series?

1 $3 \mathrm{pF}$
2 $1 / 3 \mathrm{pF}$
3 $4 \mathrm{pF}$
4 $1 / 4 \mathrm{pF}$
Capacitance

165808 Two capacitors having capacitance $C_{1}$ and $C_{2}$ respectively are connected as shown in figure. Initially, capacitor $C_{1}$ is charged to a potential difference $V$ volt by a battery. The battery is then removed and the charged capacitor $C_{1}$ is now connected to uncharged capacitor $C_{2}$, by closing the switch $\mathrm{S}$. The amount of charge on the capacitor $C_{2}$ after equilibrium is:

1 $\frac{\mathrm{C}_{1} \mathrm{C}_{2}}{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)} \mathrm{V}$
2 $\frac{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)}{\mathrm{C}_{1} \mathrm{C}_{2}} \mathrm{~V}$
3 $\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right) \mathrm{V}$
4 $\left(\mathrm{C}_{1}-\mathrm{C}_{2}\right) \mathrm{V}$
Capacitance

165809 The charge on capacitor of capacitance $15 \mu \mathrm{F}$ in the figure given below is:

1 $60 \mu \mathrm{C}$
2 $130 \mu \mathrm{C}$
3 $260 \mu \mathrm{C}$
4 $585 \mu \mathrm{C}$
Capacitance

165804 The capacity of a parallel plate capacitor with no dielectric but with a separation $0.4 \mathrm{~cm}$ is $2 \mu \mathrm{F}$. The separation is reduced to half and it is filled with a dielectric of value 2.8 . The final capacity of the capacitor is:

1 $11.2 \mu \mathrm{F}$
2 $5.6 \mu \mathrm{F}$
3 $4.0 \mu \mathrm{F}$
4 $22.4 \mu \mathrm{F}$
Capacitance

165805 Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

1 $1: 1$
2 $1: 2$
3 $1: 3$
4 $1: 4$
Capacitance

165806 What is the total capacitance of the combination when 3 capacitors each of capacitance 9 pF are connected in series?

1 $3 \mathrm{pF}$
2 $1 / 3 \mathrm{pF}$
3 $4 \mathrm{pF}$
4 $1 / 4 \mathrm{pF}$
Capacitance

165808 Two capacitors having capacitance $C_{1}$ and $C_{2}$ respectively are connected as shown in figure. Initially, capacitor $C_{1}$ is charged to a potential difference $V$ volt by a battery. The battery is then removed and the charged capacitor $C_{1}$ is now connected to uncharged capacitor $C_{2}$, by closing the switch $\mathrm{S}$. The amount of charge on the capacitor $C_{2}$ after equilibrium is:

1 $\frac{\mathrm{C}_{1} \mathrm{C}_{2}}{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)} \mathrm{V}$
2 $\frac{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)}{\mathrm{C}_{1} \mathrm{C}_{2}} \mathrm{~V}$
3 $\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right) \mathrm{V}$
4 $\left(\mathrm{C}_{1}-\mathrm{C}_{2}\right) \mathrm{V}$
Capacitance

165809 The charge on capacitor of capacitance $15 \mu \mathrm{F}$ in the figure given below is:

1 $60 \mu \mathrm{C}$
2 $130 \mu \mathrm{C}$
3 $260 \mu \mathrm{C}$
4 $585 \mu \mathrm{C}$
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Capacitance

165804 The capacity of a parallel plate capacitor with no dielectric but with a separation $0.4 \mathrm{~cm}$ is $2 \mu \mathrm{F}$. The separation is reduced to half and it is filled with a dielectric of value 2.8 . The final capacity of the capacitor is:

1 $11.2 \mu \mathrm{F}$
2 $5.6 \mu \mathrm{F}$
3 $4.0 \mu \mathrm{F}$
4 $22.4 \mu \mathrm{F}$
Capacitance

165805 Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

1 $1: 1$
2 $1: 2$
3 $1: 3$
4 $1: 4$
Capacitance

165806 What is the total capacitance of the combination when 3 capacitors each of capacitance 9 pF are connected in series?

1 $3 \mathrm{pF}$
2 $1 / 3 \mathrm{pF}$
3 $4 \mathrm{pF}$
4 $1 / 4 \mathrm{pF}$
Capacitance

165808 Two capacitors having capacitance $C_{1}$ and $C_{2}$ respectively are connected as shown in figure. Initially, capacitor $C_{1}$ is charged to a potential difference $V$ volt by a battery. The battery is then removed and the charged capacitor $C_{1}$ is now connected to uncharged capacitor $C_{2}$, by closing the switch $\mathrm{S}$. The amount of charge on the capacitor $C_{2}$ after equilibrium is:

1 $\frac{\mathrm{C}_{1} \mathrm{C}_{2}}{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)} \mathrm{V}$
2 $\frac{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)}{\mathrm{C}_{1} \mathrm{C}_{2}} \mathrm{~V}$
3 $\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right) \mathrm{V}$
4 $\left(\mathrm{C}_{1}-\mathrm{C}_{2}\right) \mathrm{V}$
Capacitance

165809 The charge on capacitor of capacitance $15 \mu \mathrm{F}$ in the figure given below is:

1 $60 \mu \mathrm{C}$
2 $130 \mu \mathrm{C}$
3 $260 \mu \mathrm{C}$
4 $585 \mu \mathrm{C}$
Capacitance

165804 The capacity of a parallel plate capacitor with no dielectric but with a separation $0.4 \mathrm{~cm}$ is $2 \mu \mathrm{F}$. The separation is reduced to half and it is filled with a dielectric of value 2.8 . The final capacity of the capacitor is:

1 $11.2 \mu \mathrm{F}$
2 $5.6 \mu \mathrm{F}$
3 $4.0 \mu \mathrm{F}$
4 $22.4 \mu \mathrm{F}$
Capacitance

165805 Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

1 $1: 1$
2 $1: 2$
3 $1: 3$
4 $1: 4$
Capacitance

165806 What is the total capacitance of the combination when 3 capacitors each of capacitance 9 pF are connected in series?

1 $3 \mathrm{pF}$
2 $1 / 3 \mathrm{pF}$
3 $4 \mathrm{pF}$
4 $1 / 4 \mathrm{pF}$
Capacitance

165808 Two capacitors having capacitance $C_{1}$ and $C_{2}$ respectively are connected as shown in figure. Initially, capacitor $C_{1}$ is charged to a potential difference $V$ volt by a battery. The battery is then removed and the charged capacitor $C_{1}$ is now connected to uncharged capacitor $C_{2}$, by closing the switch $\mathrm{S}$. The amount of charge on the capacitor $C_{2}$ after equilibrium is:

1 $\frac{\mathrm{C}_{1} \mathrm{C}_{2}}{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)} \mathrm{V}$
2 $\frac{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)}{\mathrm{C}_{1} \mathrm{C}_{2}} \mathrm{~V}$
3 $\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right) \mathrm{V}$
4 $\left(\mathrm{C}_{1}-\mathrm{C}_{2}\right) \mathrm{V}$
Capacitance

165809 The charge on capacitor of capacitance $15 \mu \mathrm{F}$ in the figure given below is:

1 $60 \mu \mathrm{C}$
2 $130 \mu \mathrm{C}$
3 $260 \mu \mathrm{C}$
4 $585 \mu \mathrm{C}$
Capacitance

165804 The capacity of a parallel plate capacitor with no dielectric but with a separation $0.4 \mathrm{~cm}$ is $2 \mu \mathrm{F}$. The separation is reduced to half and it is filled with a dielectric of value 2.8 . The final capacity of the capacitor is:

1 $11.2 \mu \mathrm{F}$
2 $5.6 \mu \mathrm{F}$
3 $4.0 \mu \mathrm{F}$
4 $22.4 \mu \mathrm{F}$
Capacitance

165805 Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

1 $1: 1$
2 $1: 2$
3 $1: 3$
4 $1: 4$
Capacitance

165806 What is the total capacitance of the combination when 3 capacitors each of capacitance 9 pF are connected in series?

1 $3 \mathrm{pF}$
2 $1 / 3 \mathrm{pF}$
3 $4 \mathrm{pF}$
4 $1 / 4 \mathrm{pF}$
Capacitance

165808 Two capacitors having capacitance $C_{1}$ and $C_{2}$ respectively are connected as shown in figure. Initially, capacitor $C_{1}$ is charged to a potential difference $V$ volt by a battery. The battery is then removed and the charged capacitor $C_{1}$ is now connected to uncharged capacitor $C_{2}$, by closing the switch $\mathrm{S}$. The amount of charge on the capacitor $C_{2}$ after equilibrium is:

1 $\frac{\mathrm{C}_{1} \mathrm{C}_{2}}{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)} \mathrm{V}$
2 $\frac{\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right)}{\mathrm{C}_{1} \mathrm{C}_{2}} \mathrm{~V}$
3 $\left(\mathrm{C}_{1}+\mathrm{C}_{2}\right) \mathrm{V}$
4 $\left(\mathrm{C}_{1}-\mathrm{C}_{2}\right) \mathrm{V}$
Capacitance

165809 The charge on capacitor of capacitance $15 \mu \mathrm{F}$ in the figure given below is:

1 $60 \mu \mathrm{C}$
2 $130 \mu \mathrm{C}$
3 $260 \mu \mathrm{C}$
4 $585 \mu \mathrm{C}$