Energy Stored in Capacitor
Capacitance

165690 In the given circuit one of the $3 \mu \mathrm{F}$ capacitors has $600 \mu \mathrm{J}$ of energy. Then the potential difference across $2 \mu \mathrm{F}$ capacitor is

1 $40 \mathrm{~V}$
2 $15 \mathrm{~V}$
3 $60 \mathrm{~V}$
4 $45 \mathrm{~V}$
Capacitance

165691 Two identical condensers are joined as shown in the figure. When the switch $S$ is closed, the total energy of the system is $U_{1}$. If the switch is opened and both the condensers are filled with a dielectric of dielectric constant 3 . then the energy of the system becomes $U_{2}$.
The value of $\frac{U_{1}}{U_{2}}$ is

1 $3: 1$
2 $5: 1$
3 $3: 5$
4 $5: 3$
Capacitance

165692 Three plates $A, B$ and $C$ each of area $50 \mathrm{~cm}^{2}$ have separation $3 \mathrm{~mm}$ between $A$ and $B$ and 6 $\mathrm{mm}$ between $B$ and $C$. The energy stored when the plates are fully charged by a 12 volt battery is

1 $2 \mathrm{~nJ}$
2 $1.6 \mathrm{~nJ}$
3 $52 \mathrm{~nJ}$
4 $3.2 \mathrm{~nJ}$
Capacitance

165693 A capacitor of capacity $C_{1}$ is charged up to potential $V$ volt and then connected in parallel to an uncharged capacitor of capacity $C_{2}$. The final potential difference across each capacitor will be

1 $\frac{\mathrm{C}_{2} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
2 $\frac{\mathrm{C}_{1} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
3 $\left(1+\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$
4 $\left(1-\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$
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Capacitance

165690 In the given circuit one of the $3 \mu \mathrm{F}$ capacitors has $600 \mu \mathrm{J}$ of energy. Then the potential difference across $2 \mu \mathrm{F}$ capacitor is

1 $40 \mathrm{~V}$
2 $15 \mathrm{~V}$
3 $60 \mathrm{~V}$
4 $45 \mathrm{~V}$
Capacitance

165691 Two identical condensers are joined as shown in the figure. When the switch $S$ is closed, the total energy of the system is $U_{1}$. If the switch is opened and both the condensers are filled with a dielectric of dielectric constant 3 . then the energy of the system becomes $U_{2}$.
The value of $\frac{U_{1}}{U_{2}}$ is

1 $3: 1$
2 $5: 1$
3 $3: 5$
4 $5: 3$
Capacitance

165692 Three plates $A, B$ and $C$ each of area $50 \mathrm{~cm}^{2}$ have separation $3 \mathrm{~mm}$ between $A$ and $B$ and 6 $\mathrm{mm}$ between $B$ and $C$. The energy stored when the plates are fully charged by a 12 volt battery is

1 $2 \mathrm{~nJ}$
2 $1.6 \mathrm{~nJ}$
3 $52 \mathrm{~nJ}$
4 $3.2 \mathrm{~nJ}$
Capacitance

165693 A capacitor of capacity $C_{1}$ is charged up to potential $V$ volt and then connected in parallel to an uncharged capacitor of capacity $C_{2}$. The final potential difference across each capacitor will be

1 $\frac{\mathrm{C}_{2} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
2 $\frac{\mathrm{C}_{1} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
3 $\left(1+\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$
4 $\left(1-\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$
Capacitance

165690 In the given circuit one of the $3 \mu \mathrm{F}$ capacitors has $600 \mu \mathrm{J}$ of energy. Then the potential difference across $2 \mu \mathrm{F}$ capacitor is

1 $40 \mathrm{~V}$
2 $15 \mathrm{~V}$
3 $60 \mathrm{~V}$
4 $45 \mathrm{~V}$
Capacitance

165691 Two identical condensers are joined as shown in the figure. When the switch $S$ is closed, the total energy of the system is $U_{1}$. If the switch is opened and both the condensers are filled with a dielectric of dielectric constant 3 . then the energy of the system becomes $U_{2}$.
The value of $\frac{U_{1}}{U_{2}}$ is

1 $3: 1$
2 $5: 1$
3 $3: 5$
4 $5: 3$
Capacitance

165692 Three plates $A, B$ and $C$ each of area $50 \mathrm{~cm}^{2}$ have separation $3 \mathrm{~mm}$ between $A$ and $B$ and 6 $\mathrm{mm}$ between $B$ and $C$. The energy stored when the plates are fully charged by a 12 volt battery is

1 $2 \mathrm{~nJ}$
2 $1.6 \mathrm{~nJ}$
3 $52 \mathrm{~nJ}$
4 $3.2 \mathrm{~nJ}$
Capacitance

165693 A capacitor of capacity $C_{1}$ is charged up to potential $V$ volt and then connected in parallel to an uncharged capacitor of capacity $C_{2}$. The final potential difference across each capacitor will be

1 $\frac{\mathrm{C}_{2} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
2 $\frac{\mathrm{C}_{1} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
3 $\left(1+\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$
4 $\left(1-\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$
Capacitance

165690 In the given circuit one of the $3 \mu \mathrm{F}$ capacitors has $600 \mu \mathrm{J}$ of energy. Then the potential difference across $2 \mu \mathrm{F}$ capacitor is

1 $40 \mathrm{~V}$
2 $15 \mathrm{~V}$
3 $60 \mathrm{~V}$
4 $45 \mathrm{~V}$
Capacitance

165691 Two identical condensers are joined as shown in the figure. When the switch $S$ is closed, the total energy of the system is $U_{1}$. If the switch is opened and both the condensers are filled with a dielectric of dielectric constant 3 . then the energy of the system becomes $U_{2}$.
The value of $\frac{U_{1}}{U_{2}}$ is

1 $3: 1$
2 $5: 1$
3 $3: 5$
4 $5: 3$
Capacitance

165692 Three plates $A, B$ and $C$ each of area $50 \mathrm{~cm}^{2}$ have separation $3 \mathrm{~mm}$ between $A$ and $B$ and 6 $\mathrm{mm}$ between $B$ and $C$. The energy stored when the plates are fully charged by a 12 volt battery is

1 $2 \mathrm{~nJ}$
2 $1.6 \mathrm{~nJ}$
3 $52 \mathrm{~nJ}$
4 $3.2 \mathrm{~nJ}$
Capacitance

165693 A capacitor of capacity $C_{1}$ is charged up to potential $V$ volt and then connected in parallel to an uncharged capacitor of capacity $C_{2}$. The final potential difference across each capacitor will be

1 $\frac{\mathrm{C}_{2} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
2 $\frac{\mathrm{C}_{1} \mathrm{~V}}{\mathrm{C}_{1}+\mathrm{C}_{2}}$
3 $\left(1+\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$
4 $\left(1-\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}\right) \mathrm{V}$