C • Longitudinal waves need bulk modulus of elasticity therefore they can travel in all medium solid, liquids and gases. - A progressive wave is a wave that progresses from one point of the medium to another point of medium. This wave is travels in the same direction in the same medium without changing. - A wave is a disturbance that transfer energy. However, there is no physical transfer of matter from one place to another.
TS EAMCET 31.07.2022
WAVES
172276
Identify the correct statement about a stationary wave.
1 Stationary wave is formed by superposition of two waves of different frequencies
2 The energy of oscillation is minimum at the antinode
3 Amplitude at the antinode is the same as that at the node
4 The pressure change is least at the antinode
Explanation:
D - Stationary wave is formed by superposition of two waves of same frequencies. - The energy of oscillation is maximum at the antinode. - Amplitude at the antinode is different as that at the node. It is maximum at the antinode and zero at the node. - The pressure change is least at the antinode. Hence, option (d) is correct.
J and K CET-2016
WAVES
172289
If the velocity of sound in air is $300 \mathrm{~m} / \mathrm{s}$, then the distance between two successive nodes of a stationary wave of frequency $1000 \mathrm{~Hz}$ is
1 $10 \mathrm{~cm}$
2 $20 \mathrm{~cm}$
3 $15 \mathrm{~cm}$
4 $30 \mathrm{~cm}$
Explanation:
C Given, $\mathrm{v}_{\mathrm{s}}=300 \mathrm{~m} \mathrm{~s}^{-1} \mathrm{f}=1000 \mathrm{~Hz}$ $\therefore \quad \lambda=\frac{\mathrm{v}_{\mathrm{S}}}{\mathrm{f}}=\frac{300}{1000}=0.3 \mathrm{~m}$ Hence distance between two successive nodes $=\frac{\lambda}{2}=\frac{0.3}{2}=0.15 \mathrm{~m}$ or $15 \mathrm{~cm}$.
SRMJEEE - 2010
WAVES
172314
The frequency of sinusoidal wave, 0.40 cos $(2000t+0.80)$ would be
1 $1000 \pi \mathrm{Hz}$
2 $2000 \mathrm{~Hz}$
3 $20 \mathrm{~Hz}$
4 $\frac{1000}{\pi} \mathrm{Hz}$
Explanation:
D $\mathrm{Y}=0.40 \cos (2000\mathrm{t}+0.80)$ $2 \pi \mathrm{ft}=2000\mathrm{t}$ $\mathrm{f}=\frac{1000}{\pi} \mathrm{Hz}$ $\mathrm{Y}=\mathrm{A} \cos (2 \pi \mathrm{ft}+\phi)$ $\text { On compairing equation }$
AIPMT-1992
WAVES
172317
A hospital uses an ultrasonic scanner to locate tumours in a tissue. The operating frequency of the scanner is 4.2 MHz. The speed of sound in a tissue is $1.7 \mathrm{~km} / \mathrm{s}$. The wavelength of sound in tissue is close to
C • Longitudinal waves need bulk modulus of elasticity therefore they can travel in all medium solid, liquids and gases. - A progressive wave is a wave that progresses from one point of the medium to another point of medium. This wave is travels in the same direction in the same medium without changing. - A wave is a disturbance that transfer energy. However, there is no physical transfer of matter from one place to another.
TS EAMCET 31.07.2022
WAVES
172276
Identify the correct statement about a stationary wave.
1 Stationary wave is formed by superposition of two waves of different frequencies
2 The energy of oscillation is minimum at the antinode
3 Amplitude at the antinode is the same as that at the node
4 The pressure change is least at the antinode
Explanation:
D - Stationary wave is formed by superposition of two waves of same frequencies. - The energy of oscillation is maximum at the antinode. - Amplitude at the antinode is different as that at the node. It is maximum at the antinode and zero at the node. - The pressure change is least at the antinode. Hence, option (d) is correct.
J and K CET-2016
WAVES
172289
If the velocity of sound in air is $300 \mathrm{~m} / \mathrm{s}$, then the distance between two successive nodes of a stationary wave of frequency $1000 \mathrm{~Hz}$ is
1 $10 \mathrm{~cm}$
2 $20 \mathrm{~cm}$
3 $15 \mathrm{~cm}$
4 $30 \mathrm{~cm}$
Explanation:
C Given, $\mathrm{v}_{\mathrm{s}}=300 \mathrm{~m} \mathrm{~s}^{-1} \mathrm{f}=1000 \mathrm{~Hz}$ $\therefore \quad \lambda=\frac{\mathrm{v}_{\mathrm{S}}}{\mathrm{f}}=\frac{300}{1000}=0.3 \mathrm{~m}$ Hence distance between two successive nodes $=\frac{\lambda}{2}=\frac{0.3}{2}=0.15 \mathrm{~m}$ or $15 \mathrm{~cm}$.
SRMJEEE - 2010
WAVES
172314
The frequency of sinusoidal wave, 0.40 cos $(2000t+0.80)$ would be
1 $1000 \pi \mathrm{Hz}$
2 $2000 \mathrm{~Hz}$
3 $20 \mathrm{~Hz}$
4 $\frac{1000}{\pi} \mathrm{Hz}$
Explanation:
D $\mathrm{Y}=0.40 \cos (2000\mathrm{t}+0.80)$ $2 \pi \mathrm{ft}=2000\mathrm{t}$ $\mathrm{f}=\frac{1000}{\pi} \mathrm{Hz}$ $\mathrm{Y}=\mathrm{A} \cos (2 \pi \mathrm{ft}+\phi)$ $\text { On compairing equation }$
AIPMT-1992
WAVES
172317
A hospital uses an ultrasonic scanner to locate tumours in a tissue. The operating frequency of the scanner is 4.2 MHz. The speed of sound in a tissue is $1.7 \mathrm{~km} / \mathrm{s}$. The wavelength of sound in tissue is close to
C • Longitudinal waves need bulk modulus of elasticity therefore they can travel in all medium solid, liquids and gases. - A progressive wave is a wave that progresses from one point of the medium to another point of medium. This wave is travels in the same direction in the same medium without changing. - A wave is a disturbance that transfer energy. However, there is no physical transfer of matter from one place to another.
TS EAMCET 31.07.2022
WAVES
172276
Identify the correct statement about a stationary wave.
1 Stationary wave is formed by superposition of two waves of different frequencies
2 The energy of oscillation is minimum at the antinode
3 Amplitude at the antinode is the same as that at the node
4 The pressure change is least at the antinode
Explanation:
D - Stationary wave is formed by superposition of two waves of same frequencies. - The energy of oscillation is maximum at the antinode. - Amplitude at the antinode is different as that at the node. It is maximum at the antinode and zero at the node. - The pressure change is least at the antinode. Hence, option (d) is correct.
J and K CET-2016
WAVES
172289
If the velocity of sound in air is $300 \mathrm{~m} / \mathrm{s}$, then the distance between two successive nodes of a stationary wave of frequency $1000 \mathrm{~Hz}$ is
1 $10 \mathrm{~cm}$
2 $20 \mathrm{~cm}$
3 $15 \mathrm{~cm}$
4 $30 \mathrm{~cm}$
Explanation:
C Given, $\mathrm{v}_{\mathrm{s}}=300 \mathrm{~m} \mathrm{~s}^{-1} \mathrm{f}=1000 \mathrm{~Hz}$ $\therefore \quad \lambda=\frac{\mathrm{v}_{\mathrm{S}}}{\mathrm{f}}=\frac{300}{1000}=0.3 \mathrm{~m}$ Hence distance between two successive nodes $=\frac{\lambda}{2}=\frac{0.3}{2}=0.15 \mathrm{~m}$ or $15 \mathrm{~cm}$.
SRMJEEE - 2010
WAVES
172314
The frequency of sinusoidal wave, 0.40 cos $(2000t+0.80)$ would be
1 $1000 \pi \mathrm{Hz}$
2 $2000 \mathrm{~Hz}$
3 $20 \mathrm{~Hz}$
4 $\frac{1000}{\pi} \mathrm{Hz}$
Explanation:
D $\mathrm{Y}=0.40 \cos (2000\mathrm{t}+0.80)$ $2 \pi \mathrm{ft}=2000\mathrm{t}$ $\mathrm{f}=\frac{1000}{\pi} \mathrm{Hz}$ $\mathrm{Y}=\mathrm{A} \cos (2 \pi \mathrm{ft}+\phi)$ $\text { On compairing equation }$
AIPMT-1992
WAVES
172317
A hospital uses an ultrasonic scanner to locate tumours in a tissue. The operating frequency of the scanner is 4.2 MHz. The speed of sound in a tissue is $1.7 \mathrm{~km} / \mathrm{s}$. The wavelength of sound in tissue is close to
C • Longitudinal waves need bulk modulus of elasticity therefore they can travel in all medium solid, liquids and gases. - A progressive wave is a wave that progresses from one point of the medium to another point of medium. This wave is travels in the same direction in the same medium without changing. - A wave is a disturbance that transfer energy. However, there is no physical transfer of matter from one place to another.
TS EAMCET 31.07.2022
WAVES
172276
Identify the correct statement about a stationary wave.
1 Stationary wave is formed by superposition of two waves of different frequencies
2 The energy of oscillation is minimum at the antinode
3 Amplitude at the antinode is the same as that at the node
4 The pressure change is least at the antinode
Explanation:
D - Stationary wave is formed by superposition of two waves of same frequencies. - The energy of oscillation is maximum at the antinode. - Amplitude at the antinode is different as that at the node. It is maximum at the antinode and zero at the node. - The pressure change is least at the antinode. Hence, option (d) is correct.
J and K CET-2016
WAVES
172289
If the velocity of sound in air is $300 \mathrm{~m} / \mathrm{s}$, then the distance between two successive nodes of a stationary wave of frequency $1000 \mathrm{~Hz}$ is
1 $10 \mathrm{~cm}$
2 $20 \mathrm{~cm}$
3 $15 \mathrm{~cm}$
4 $30 \mathrm{~cm}$
Explanation:
C Given, $\mathrm{v}_{\mathrm{s}}=300 \mathrm{~m} \mathrm{~s}^{-1} \mathrm{f}=1000 \mathrm{~Hz}$ $\therefore \quad \lambda=\frac{\mathrm{v}_{\mathrm{S}}}{\mathrm{f}}=\frac{300}{1000}=0.3 \mathrm{~m}$ Hence distance between two successive nodes $=\frac{\lambda}{2}=\frac{0.3}{2}=0.15 \mathrm{~m}$ or $15 \mathrm{~cm}$.
SRMJEEE - 2010
WAVES
172314
The frequency of sinusoidal wave, 0.40 cos $(2000t+0.80)$ would be
1 $1000 \pi \mathrm{Hz}$
2 $2000 \mathrm{~Hz}$
3 $20 \mathrm{~Hz}$
4 $\frac{1000}{\pi} \mathrm{Hz}$
Explanation:
D $\mathrm{Y}=0.40 \cos (2000\mathrm{t}+0.80)$ $2 \pi \mathrm{ft}=2000\mathrm{t}$ $\mathrm{f}=\frac{1000}{\pi} \mathrm{Hz}$ $\mathrm{Y}=\mathrm{A} \cos (2 \pi \mathrm{ft}+\phi)$ $\text { On compairing equation }$
AIPMT-1992
WAVES
172317
A hospital uses an ultrasonic scanner to locate tumours in a tissue. The operating frequency of the scanner is 4.2 MHz. The speed of sound in a tissue is $1.7 \mathrm{~km} / \mathrm{s}$. The wavelength of sound in tissue is close to
C • Longitudinal waves need bulk modulus of elasticity therefore they can travel in all medium solid, liquids and gases. - A progressive wave is a wave that progresses from one point of the medium to another point of medium. This wave is travels in the same direction in the same medium without changing. - A wave is a disturbance that transfer energy. However, there is no physical transfer of matter from one place to another.
TS EAMCET 31.07.2022
WAVES
172276
Identify the correct statement about a stationary wave.
1 Stationary wave is formed by superposition of two waves of different frequencies
2 The energy of oscillation is minimum at the antinode
3 Amplitude at the antinode is the same as that at the node
4 The pressure change is least at the antinode
Explanation:
D - Stationary wave is formed by superposition of two waves of same frequencies. - The energy of oscillation is maximum at the antinode. - Amplitude at the antinode is different as that at the node. It is maximum at the antinode and zero at the node. - The pressure change is least at the antinode. Hence, option (d) is correct.
J and K CET-2016
WAVES
172289
If the velocity of sound in air is $300 \mathrm{~m} / \mathrm{s}$, then the distance between two successive nodes of a stationary wave of frequency $1000 \mathrm{~Hz}$ is
1 $10 \mathrm{~cm}$
2 $20 \mathrm{~cm}$
3 $15 \mathrm{~cm}$
4 $30 \mathrm{~cm}$
Explanation:
C Given, $\mathrm{v}_{\mathrm{s}}=300 \mathrm{~m} \mathrm{~s}^{-1} \mathrm{f}=1000 \mathrm{~Hz}$ $\therefore \quad \lambda=\frac{\mathrm{v}_{\mathrm{S}}}{\mathrm{f}}=\frac{300}{1000}=0.3 \mathrm{~m}$ Hence distance between two successive nodes $=\frac{\lambda}{2}=\frac{0.3}{2}=0.15 \mathrm{~m}$ or $15 \mathrm{~cm}$.
SRMJEEE - 2010
WAVES
172314
The frequency of sinusoidal wave, 0.40 cos $(2000t+0.80)$ would be
1 $1000 \pi \mathrm{Hz}$
2 $2000 \mathrm{~Hz}$
3 $20 \mathrm{~Hz}$
4 $\frac{1000}{\pi} \mathrm{Hz}$
Explanation:
D $\mathrm{Y}=0.40 \cos (2000\mathrm{t}+0.80)$ $2 \pi \mathrm{ft}=2000\mathrm{t}$ $\mathrm{f}=\frac{1000}{\pi} \mathrm{Hz}$ $\mathrm{Y}=\mathrm{A} \cos (2 \pi \mathrm{ft}+\phi)$ $\text { On compairing equation }$
AIPMT-1992
WAVES
172317
A hospital uses an ultrasonic scanner to locate tumours in a tissue. The operating frequency of the scanner is 4.2 MHz. The speed of sound in a tissue is $1.7 \mathrm{~km} / \mathrm{s}$. The wavelength of sound in tissue is close to
