139334 A gas mixture contains $n_{1}$ moles of a monoatomic gas and $n_{2}$ moles of gas of rigid diatomic molecules. Each molecule in monoatomic and diatomic gas has 3 and 5 degrees of freedom respectively. If the adiabatic exponent $\left(\frac{C_{p}}{C_{v}}\right)$ for this gas mixture is 1.5 , then the ratio $\frac{n_{1}}{n_{2}}$ will be
139334 A gas mixture contains $n_{1}$ moles of a monoatomic gas and $n_{2}$ moles of gas of rigid diatomic molecules. Each molecule in monoatomic and diatomic gas has 3 and 5 degrees of freedom respectively. If the adiabatic exponent $\left(\frac{C_{p}}{C_{v}}\right)$ for this gas mixture is 1.5 , then the ratio $\frac{n_{1}}{n_{2}}$ will be
139334 A gas mixture contains $n_{1}$ moles of a monoatomic gas and $n_{2}$ moles of gas of rigid diatomic molecules. Each molecule in monoatomic and diatomic gas has 3 and 5 degrees of freedom respectively. If the adiabatic exponent $\left(\frac{C_{p}}{C_{v}}\right)$ for this gas mixture is 1.5 , then the ratio $\frac{n_{1}}{n_{2}}$ will be
139334 A gas mixture contains $n_{1}$ moles of a monoatomic gas and $n_{2}$ moles of gas of rigid diatomic molecules. Each molecule in monoatomic and diatomic gas has 3 and 5 degrees of freedom respectively. If the adiabatic exponent $\left(\frac{C_{p}}{C_{v}}\right)$ for this gas mixture is 1.5 , then the ratio $\frac{n_{1}}{n_{2}}$ will be
139334 A gas mixture contains $n_{1}$ moles of a monoatomic gas and $n_{2}$ moles of gas of rigid diatomic molecules. Each molecule in monoatomic and diatomic gas has 3 and 5 degrees of freedom respectively. If the adiabatic exponent $\left(\frac{C_{p}}{C_{v}}\right)$ for this gas mixture is 1.5 , then the ratio $\frac{n_{1}}{n_{2}}$ will be