Law of Gases (Boyle's Law, Charles's Law, Gay-Lussac's Law, Avogadro's Law)
Kinetic Theory of Gases

138928 Equation of a gas in terms of pressure (P), absolute temperature, $(T)$ and density $(d)$ is:

1 $\frac{P_{1}}{T_{1} d_{1}}=\frac{P_{2}}{T_{2} d_{2}}$
2 $\frac{P_{1} T_{1}}{d_{1}}=\frac{P_{2} T_{2}}{d_{2}}$
3 $\frac{P_{1} d_{2}}{T_{2}}=\frac{P_{2} d_{1}}{T_{1}}$
4 $\frac{\mathrm{P}_{1} \mathrm{~d}_{1}}{\mathrm{~T}_{1}}=\frac{\mathrm{P}_{1} \mathrm{~d}_{2}}{\mathrm{~T}_{2}}$
[CGPET -2017
Kinetic Theory of Gases

138929 A metal jar has a gas of volume $10^{-3} \mathrm{~m}^{3}$ at a pressure of $2 \times 10^{5} \mathrm{~Pa}$ and temperature $400 \mathrm{~K}$. The jar has small hole and hence the gas leaks into atmosphere. The pressure and temperature of atmosphere is $10^{5} \mathrm{~Pa}$ and $300 \mathrm{~K}$ respectively. If $R$ is the gas constant, the number of moles of the gas that has leaked into atmosphere is

1 $\frac{1}{5 R}$
2 $\frac{1}{6 \mathrm{R}}$
3 $\frac{1}{7 R}$
4 $\frac{1}{8 \mathrm{R}}$
Kinetic Theory of Gases

138930 Equal volumes of mono atomic and diatomic gases at the same temperature are given equal quantities of heat. Then,

1 The temperature of diatomic gas will be more
2 The temperature of mono atomic gas will be more
3 The temperature of both will be zero
4 Nothing can be said
Kinetic Theory of Gases

138931 Volume-temperature graph at atmospheric pressure for a mono atomic gas $\left(\mathrm{V}\right.$ in $\mathrm{m}^{3}, \mathrm{~T}$ in ${ }^{\circ} \mathrm{C}$ ) is

1
2
3
4
Kinetic Theory of Gases

138928 Equation of a gas in terms of pressure (P), absolute temperature, $(T)$ and density $(d)$ is:

1 $\frac{P_{1}}{T_{1} d_{1}}=\frac{P_{2}}{T_{2} d_{2}}$
2 $\frac{P_{1} T_{1}}{d_{1}}=\frac{P_{2} T_{2}}{d_{2}}$
3 $\frac{P_{1} d_{2}}{T_{2}}=\frac{P_{2} d_{1}}{T_{1}}$
4 $\frac{\mathrm{P}_{1} \mathrm{~d}_{1}}{\mathrm{~T}_{1}}=\frac{\mathrm{P}_{1} \mathrm{~d}_{2}}{\mathrm{~T}_{2}}$
[CGPET -2017
Kinetic Theory of Gases

138929 A metal jar has a gas of volume $10^{-3} \mathrm{~m}^{3}$ at a pressure of $2 \times 10^{5} \mathrm{~Pa}$ and temperature $400 \mathrm{~K}$. The jar has small hole and hence the gas leaks into atmosphere. The pressure and temperature of atmosphere is $10^{5} \mathrm{~Pa}$ and $300 \mathrm{~K}$ respectively. If $R$ is the gas constant, the number of moles of the gas that has leaked into atmosphere is

1 $\frac{1}{5 R}$
2 $\frac{1}{6 \mathrm{R}}$
3 $\frac{1}{7 R}$
4 $\frac{1}{8 \mathrm{R}}$
Kinetic Theory of Gases

138930 Equal volumes of mono atomic and diatomic gases at the same temperature are given equal quantities of heat. Then,

1 The temperature of diatomic gas will be more
2 The temperature of mono atomic gas will be more
3 The temperature of both will be zero
4 Nothing can be said
Kinetic Theory of Gases

138931 Volume-temperature graph at atmospheric pressure for a mono atomic gas $\left(\mathrm{V}\right.$ in $\mathrm{m}^{3}, \mathrm{~T}$ in ${ }^{\circ} \mathrm{C}$ ) is

1
2
3
4
Kinetic Theory of Gases

138928 Equation of a gas in terms of pressure (P), absolute temperature, $(T)$ and density $(d)$ is:

1 $\frac{P_{1}}{T_{1} d_{1}}=\frac{P_{2}}{T_{2} d_{2}}$
2 $\frac{P_{1} T_{1}}{d_{1}}=\frac{P_{2} T_{2}}{d_{2}}$
3 $\frac{P_{1} d_{2}}{T_{2}}=\frac{P_{2} d_{1}}{T_{1}}$
4 $\frac{\mathrm{P}_{1} \mathrm{~d}_{1}}{\mathrm{~T}_{1}}=\frac{\mathrm{P}_{1} \mathrm{~d}_{2}}{\mathrm{~T}_{2}}$
[CGPET -2017
Kinetic Theory of Gases

138929 A metal jar has a gas of volume $10^{-3} \mathrm{~m}^{3}$ at a pressure of $2 \times 10^{5} \mathrm{~Pa}$ and temperature $400 \mathrm{~K}$. The jar has small hole and hence the gas leaks into atmosphere. The pressure and temperature of atmosphere is $10^{5} \mathrm{~Pa}$ and $300 \mathrm{~K}$ respectively. If $R$ is the gas constant, the number of moles of the gas that has leaked into atmosphere is

1 $\frac{1}{5 R}$
2 $\frac{1}{6 \mathrm{R}}$
3 $\frac{1}{7 R}$
4 $\frac{1}{8 \mathrm{R}}$
Kinetic Theory of Gases

138930 Equal volumes of mono atomic and diatomic gases at the same temperature are given equal quantities of heat. Then,

1 The temperature of diatomic gas will be more
2 The temperature of mono atomic gas will be more
3 The temperature of both will be zero
4 Nothing can be said
Kinetic Theory of Gases

138931 Volume-temperature graph at atmospheric pressure for a mono atomic gas $\left(\mathrm{V}\right.$ in $\mathrm{m}^{3}, \mathrm{~T}$ in ${ }^{\circ} \mathrm{C}$ ) is

1
2
3
4
Kinetic Theory of Gases

138928 Equation of a gas in terms of pressure (P), absolute temperature, $(T)$ and density $(d)$ is:

1 $\frac{P_{1}}{T_{1} d_{1}}=\frac{P_{2}}{T_{2} d_{2}}$
2 $\frac{P_{1} T_{1}}{d_{1}}=\frac{P_{2} T_{2}}{d_{2}}$
3 $\frac{P_{1} d_{2}}{T_{2}}=\frac{P_{2} d_{1}}{T_{1}}$
4 $\frac{\mathrm{P}_{1} \mathrm{~d}_{1}}{\mathrm{~T}_{1}}=\frac{\mathrm{P}_{1} \mathrm{~d}_{2}}{\mathrm{~T}_{2}}$
[CGPET -2017
Kinetic Theory of Gases

138929 A metal jar has a gas of volume $10^{-3} \mathrm{~m}^{3}$ at a pressure of $2 \times 10^{5} \mathrm{~Pa}$ and temperature $400 \mathrm{~K}$. The jar has small hole and hence the gas leaks into atmosphere. The pressure and temperature of atmosphere is $10^{5} \mathrm{~Pa}$ and $300 \mathrm{~K}$ respectively. If $R$ is the gas constant, the number of moles of the gas that has leaked into atmosphere is

1 $\frac{1}{5 R}$
2 $\frac{1}{6 \mathrm{R}}$
3 $\frac{1}{7 R}$
4 $\frac{1}{8 \mathrm{R}}$
Kinetic Theory of Gases

138930 Equal volumes of mono atomic and diatomic gases at the same temperature are given equal quantities of heat. Then,

1 The temperature of diatomic gas will be more
2 The temperature of mono atomic gas will be more
3 The temperature of both will be zero
4 Nothing can be said
Kinetic Theory of Gases

138931 Volume-temperature graph at atmospheric pressure for a mono atomic gas $\left(\mathrm{V}\right.$ in $\mathrm{m}^{3}, \mathrm{~T}$ in ${ }^{\circ} \mathrm{C}$ ) is

1
2
3
4