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NUCLEAR PHYSICS

147534 The ratio $(E / W)$ of relative strength of electromagnetic force (E) to weak nuclear force (W) is

1

10^{- 1}

2

10^{11}

3

10^{20}

4

10^{- 20}

Explanation:

B | Force | Relative strength |
| :--- | :---: |
| Gravitational force | $10^{- 39}$ |
| Weak nuclear force | $10^{- 13}$ |
| Electromagnetic force | $10^{- 2}$ |
| Strong nuclear force | 1 |
$Relative strength = \frac{10^{- 2}}{10^{- 13}} = 10^{11}$

TS EAMCET 04.08.2021

NUCLEAR PHYSICS

147536 The speed of ripples (v) on water surface depends on surface tension $(σ)$ , density $(ρ)$ and wavelength $(λ)$ Then the square of speed $(v)$ is proportional to

1

\frac{σ}{ρ λ}

2

\frac{ρ}{σ λ}

3

\frac{λ}{σ ρ}

4

\sqrt{\frac{ρ λ}{σ}}

Explanation:

A The speed of ripples (v) depends upon $v \propto σ^{a} ρ^{b} λ^{c}$
$[M^{0} {LT}^{- 1}] \propto {[{MT}^{- 2}]}^{a} {[{ML}^{- 3}]}^{b} [L]^{c}$
$[M^{0} {LT}^{- 1}] \propto [M^{a + b}] [L^{- 3 b + c}] [T^{- 2 a}]$
Equating the powers we get-
$a + b = 0$
$- 3 b + c = 1$
$- 2 a = - 1$
Then, $a = \frac{1}{2}, b = \frac{- 1}{2}, c = \frac{- 1}{2}$
So, $v \propto σ^{1 / 2} ρ^{- 1 / 2} λ^{- 1 / 2}$
$= v \propto \sqrt{\frac{σ}{ρ λ}}$
$= v^{2} \propto \frac{σ}{p λ}$

AP EAMCET-19.08.2021

NUCLEAR PHYSICS

147539 Identify the correct statement among the following.

1 Resistivity of metals decreases with temperature because more electrons are available for conduction.

2 Resistivity of metals increases with temperature because number of electrons decreases.

3 Resistivity of metals increases with temperature because number of collisions between electrons increases.

4 Resistivity of metals decreases with temperature because superconductivity sets in.

Explanation:

C When a metal is heated, the atoms is starts to vibrate, this leads to increases in number of collisions amongst the electrons thus time between successive collision or relaxation time $τ$ decreases. Since the resistivity of a metal is given by
When
$ρ = \frac{m}{n e^{2} τ}$
$m =$ mean of electron
$n =$ number of change
$e =$ change on electron
$ρ \propto \frac{1}{τ}$
When $τ$ decrease resistivity increase.

TS- EAMCET-03.05.2019

NUCLEAR PHYSICS

1 A-iv, B-iii, C-ii, D-i

2 A-ii, B-i, C-iv, D-iii

3 A-iii, B-ii, C-i, D-iv

4 A-ii, B-iii, C-iv, D-i

Explanation:

D (i) Gravitational force $\to$ Weakest force but has infinite range
(ii) Strong Nuclear force $\to$ Strongest among the forces.
(iii) Weak nuclear force $\to$ Responsible for radioactive decay.
(iv) Electromagnetic force $\to$ Has infinite range and can be both attractive and repulsive in nature.

TS EAMCET 09.05.2019

NUCLEAR PHYSICS

147537 In thermonuclear reaction $3_{1}^{2} H \to_{2}^{4} He +_{1}^{1} H +_{0}^{1} n$ $+ 21.6 MeV$ , the percentage of mass converted during fusion in to energy is nearly:
#[Qdiff: Medium, QCat: Theory Based, examname: Mass of reactants $= 6 AMU$
, $1 AMU = 931 MeV$
, $6 AMU = 6 \times 931 = 5586 MeV$
, Percentage converted
, $= \frac{21.6}{5586} \times 100$
, $= 0.38 %$
, $= 0.4 %$
, 218. Two protons are kept at a separation of $10 nm$ . Let $F_{n}$ and $F_{e}$ the nuclear force and the electromagnetic force between them :
, (a) $F_{e} = F_{n}$
, (b) $F_{e} >> F_{n}$
, (c) $F_{e} << F_{n}$
, (d) $F_{e}$ and $F_{n}$ differ only slightly
, [Karnataka CET-2020,2019]#

1

10 %

2

0.4 %

3

1 %

4

0.01 %

Explanation:

B The given thermonuclear reaction-
$3_{1} H^{2} \to 2 H_{e}^{4} +_{1} H^{1} +_{0} n^{1} + 21.6 MeV$
No of nucleons $= 6$
Ans: b : Two protons exert strong attractive nuclear force and repulsive electrostatic force on each other. Nucleus forces are short range forces existing in the range of a few fermi. Therefore at a separation of $10 nm$ the electromagnetic force is greater than the nuclear force
i.e. $F_{e} >> F_{n}$

NUCLEAR PHYSICS

147534 The ratio $(E / W)$ of relative strength of electromagnetic force (E) to weak nuclear force (W) is

1

10^{- 1}

2

10^{11}

3

10^{20}

4

10^{- 20}

Explanation:

B | Force | Relative strength |
| :--- | :---: |
| Gravitational force | $10^{- 39}$ |
| Weak nuclear force | $10^{- 13}$ |
| Electromagnetic force | $10^{- 2}$ |
| Strong nuclear force | 1 |
$Relative strength = \frac{10^{- 2}}{10^{- 13}} = 10^{11}$

TS EAMCET 04.08.2021

NUCLEAR PHYSICS

147536 The speed of ripples (v) on water surface depends on surface tension $(σ)$ , density $(ρ)$ and wavelength $(λ)$ Then the square of speed $(v)$ is proportional to

1

\frac{σ}{ρ λ}

2

\frac{ρ}{σ λ}

3

\frac{λ}{σ ρ}

4

\sqrt{\frac{ρ λ}{σ}}

Explanation:

A The speed of ripples (v) depends upon $v \propto σ^{a} ρ^{b} λ^{c}$
$[M^{0} {LT}^{- 1}] \propto {[{MT}^{- 2}]}^{a} {[{ML}^{- 3}]}^{b} [L]^{c}$
$[M^{0} {LT}^{- 1}] \propto [M^{a + b}] [L^{- 3 b + c}] [T^{- 2 a}]$
Equating the powers we get-
$a + b = 0$
$- 3 b + c = 1$
$- 2 a = - 1$
Then, $a = \frac{1}{2}, b = \frac{- 1}{2}, c = \frac{- 1}{2}$
So, $v \propto σ^{1 / 2} ρ^{- 1 / 2} λ^{- 1 / 2}$
$= v \propto \sqrt{\frac{σ}{ρ λ}}$
$= v^{2} \propto \frac{σ}{p λ}$

AP EAMCET-19.08.2021

NUCLEAR PHYSICS

147539 Identify the correct statement among the following.

1 Resistivity of metals decreases with temperature because more electrons are available for conduction.

2 Resistivity of metals increases with temperature because number of electrons decreases.

3 Resistivity of metals increases with temperature because number of collisions between electrons increases.

4 Resistivity of metals decreases with temperature because superconductivity sets in.

Explanation:

C When a metal is heated, the atoms is starts to vibrate, this leads to increases in number of collisions amongst the electrons thus time between successive collision or relaxation time $τ$ decreases. Since the resistivity of a metal is given by
When
$ρ = \frac{m}{n e^{2} τ}$
$m =$ mean of electron
$n =$ number of change
$e =$ change on electron
$ρ \propto \frac{1}{τ}$
When $τ$ decrease resistivity increase.

TS- EAMCET-03.05.2019

NUCLEAR PHYSICS

1 A-iv, B-iii, C-ii, D-i

2 A-ii, B-i, C-iv, D-iii

3 A-iii, B-ii, C-i, D-iv

4 A-ii, B-iii, C-iv, D-i

Explanation:

D (i) Gravitational force $\to$ Weakest force but has infinite range
(ii) Strong Nuclear force $\to$ Strongest among the forces.
(iii) Weak nuclear force $\to$ Responsible for radioactive decay.
(iv) Electromagnetic force $\to$ Has infinite range and can be both attractive and repulsive in nature.

TS EAMCET 09.05.2019

NUCLEAR PHYSICS

147537 In thermonuclear reaction $3_{1}^{2} H \to_{2}^{4} He +_{1}^{1} H +_{0}^{1} n$ $+ 21.6 MeV$ , the percentage of mass converted during fusion in to energy is nearly:
#[Qdiff: Medium, QCat: Theory Based, examname: Mass of reactants $= 6 AMU$
, $1 AMU = 931 MeV$
, $6 AMU = 6 \times 931 = 5586 MeV$
, Percentage converted
, $= \frac{21.6}{5586} \times 100$
, $= 0.38 %$
, $= 0.4 %$
, 218. Two protons are kept at a separation of $10 nm$ . Let $F_{n}$ and $F_{e}$ the nuclear force and the electromagnetic force between them :
, (a) $F_{e} = F_{n}$
, (b) $F_{e} >> F_{n}$
, (c) $F_{e} << F_{n}$
, (d) $F_{e}$ and $F_{n}$ differ only slightly
, [Karnataka CET-2020,2019]#

1

10 %

2

0.4 %

3

1 %

4

0.01 %

Explanation:

B The given thermonuclear reaction-
$3_{1} H^{2} \to 2 H_{e}^{4} +_{1} H^{1} +_{0} n^{1} + 21.6 MeV$
No of nucleons $= 6$
Ans: b : Two protons exert strong attractive nuclear force and repulsive electrostatic force on each other. Nucleus forces are short range forces existing in the range of a few fermi. Therefore at a separation of $10 nm$ the electromagnetic force is greater than the nuclear force
i.e. $F_{e} >> F_{n}$

NUCLEAR PHYSICS

147534 The ratio $(E / W)$ of relative strength of electromagnetic force (E) to weak nuclear force (W) is

1

10^{- 1}

2

10^{11}

3

10^{20}

4

10^{- 20}

Explanation:

B | Force | Relative strength |
| :--- | :---: |
| Gravitational force | $10^{- 39}$ |
| Weak nuclear force | $10^{- 13}$ |
| Electromagnetic force | $10^{- 2}$ |
| Strong nuclear force | 1 |
$Relative strength = \frac{10^{- 2}}{10^{- 13}} = 10^{11}$

TS EAMCET 04.08.2021

NUCLEAR PHYSICS

147536 The speed of ripples (v) on water surface depends on surface tension $(σ)$ , density $(ρ)$ and wavelength $(λ)$ Then the square of speed $(v)$ is proportional to

1

\frac{σ}{ρ λ}

2

\frac{ρ}{σ λ}

3

\frac{λ}{σ ρ}

4

\sqrt{\frac{ρ λ}{σ}}

Explanation:

A The speed of ripples (v) depends upon $v \propto σ^{a} ρ^{b} λ^{c}$
$[M^{0} {LT}^{- 1}] \propto {[{MT}^{- 2}]}^{a} {[{ML}^{- 3}]}^{b} [L]^{c}$
$[M^{0} {LT}^{- 1}] \propto [M^{a + b}] [L^{- 3 b + c}] [T^{- 2 a}]$
Equating the powers we get-
$a + b = 0$
$- 3 b + c = 1$
$- 2 a = - 1$
Then, $a = \frac{1}{2}, b = \frac{- 1}{2}, c = \frac{- 1}{2}$
So, $v \propto σ^{1 / 2} ρ^{- 1 / 2} λ^{- 1 / 2}$
$= v \propto \sqrt{\frac{σ}{ρ λ}}$
$= v^{2} \propto \frac{σ}{p λ}$

AP EAMCET-19.08.2021

NUCLEAR PHYSICS

147539 Identify the correct statement among the following.

1 Resistivity of metals decreases with temperature because more electrons are available for conduction.

2 Resistivity of metals increases with temperature because number of electrons decreases.

3 Resistivity of metals increases with temperature because number of collisions between electrons increases.

4 Resistivity of metals decreases with temperature because superconductivity sets in.

Explanation:

C When a metal is heated, the atoms is starts to vibrate, this leads to increases in number of collisions amongst the electrons thus time between successive collision or relaxation time $τ$ decreases. Since the resistivity of a metal is given by
When
$ρ = \frac{m}{n e^{2} τ}$
$m =$ mean of electron
$n =$ number of change
$e =$ change on electron
$ρ \propto \frac{1}{τ}$
When $τ$ decrease resistivity increase.

TS- EAMCET-03.05.2019

NUCLEAR PHYSICS

1 A-iv, B-iii, C-ii, D-i

2 A-ii, B-i, C-iv, D-iii

3 A-iii, B-ii, C-i, D-iv

4 A-ii, B-iii, C-iv, D-i

Explanation:

D (i) Gravitational force $\to$ Weakest force but has infinite range
(ii) Strong Nuclear force $\to$ Strongest among the forces.
(iii) Weak nuclear force $\to$ Responsible for radioactive decay.
(iv) Electromagnetic force $\to$ Has infinite range and can be both attractive and repulsive in nature.

TS EAMCET 09.05.2019

NUCLEAR PHYSICS

147537 In thermonuclear reaction $3_{1}^{2} H \to_{2}^{4} He +_{1}^{1} H +_{0}^{1} n$ $+ 21.6 MeV$ , the percentage of mass converted during fusion in to energy is nearly:
#[Qdiff: Medium, QCat: Theory Based, examname: Mass of reactants $= 6 AMU$
, $1 AMU = 931 MeV$
, $6 AMU = 6 \times 931 = 5586 MeV$
, Percentage converted
, $= \frac{21.6}{5586} \times 100$
, $= 0.38 %$
, $= 0.4 %$
, 218. Two protons are kept at a separation of $10 nm$ . Let $F_{n}$ and $F_{e}$ the nuclear force and the electromagnetic force between them :
, (a) $F_{e} = F_{n}$
, (b) $F_{e} >> F_{n}$
, (c) $F_{e} << F_{n}$
, (d) $F_{e}$ and $F_{n}$ differ only slightly
, [Karnataka CET-2020,2019]#

1

10 %

2

0.4 %

3

1 %

4

0.01 %

Explanation:

B The given thermonuclear reaction-
$3_{1} H^{2} \to 2 H_{e}^{4} +_{1} H^{1} +_{0} n^{1} + 21.6 MeV$
No of nucleons $= 6$
Ans: b : Two protons exert strong attractive nuclear force and repulsive electrostatic force on each other. Nucleus forces are short range forces existing in the range of a few fermi. Therefore at a separation of $10 nm$ the electromagnetic force is greater than the nuclear force
i.e. $F_{e} >> F_{n}$

NUCLEAR PHYSICS

147534 The ratio $(E / W)$ of relative strength of electromagnetic force (E) to weak nuclear force (W) is

1

10^{- 1}

2

10^{11}

3

10^{20}

4

10^{- 20}

Explanation:

B | Force | Relative strength |
| :--- | :---: |
| Gravitational force | $10^{- 39}$ |
| Weak nuclear force | $10^{- 13}$ |
| Electromagnetic force | $10^{- 2}$ |
| Strong nuclear force | 1 |
$Relative strength = \frac{10^{- 2}}{10^{- 13}} = 10^{11}$

TS EAMCET 04.08.2021

NUCLEAR PHYSICS

147536 The speed of ripples (v) on water surface depends on surface tension $(σ)$ , density $(ρ)$ and wavelength $(λ)$ Then the square of speed $(v)$ is proportional to

1

\frac{σ}{ρ λ}

2

\frac{ρ}{σ λ}

3

\frac{λ}{σ ρ}

4

\sqrt{\frac{ρ λ}{σ}}

Explanation:

A The speed of ripples (v) depends upon $v \propto σ^{a} ρ^{b} λ^{c}$
$[M^{0} {LT}^{- 1}] \propto {[{MT}^{- 2}]}^{a} {[{ML}^{- 3}]}^{b} [L]^{c}$
$[M^{0} {LT}^{- 1}] \propto [M^{a + b}] [L^{- 3 b + c}] [T^{- 2 a}]$
Equating the powers we get-
$a + b = 0$
$- 3 b + c = 1$
$- 2 a = - 1$
Then, $a = \frac{1}{2}, b = \frac{- 1}{2}, c = \frac{- 1}{2}$
So, $v \propto σ^{1 / 2} ρ^{- 1 / 2} λ^{- 1 / 2}$
$= v \propto \sqrt{\frac{σ}{ρ λ}}$
$= v^{2} \propto \frac{σ}{p λ}$

AP EAMCET-19.08.2021

NUCLEAR PHYSICS

147539 Identify the correct statement among the following.

1 Resistivity of metals decreases with temperature because more electrons are available for conduction.

2 Resistivity of metals increases with temperature because number of electrons decreases.

3 Resistivity of metals increases with temperature because number of collisions between electrons increases.

4 Resistivity of metals decreases with temperature because superconductivity sets in.

Explanation:

C When a metal is heated, the atoms is starts to vibrate, this leads to increases in number of collisions amongst the electrons thus time between successive collision or relaxation time $τ$ decreases. Since the resistivity of a metal is given by
When
$ρ = \frac{m}{n e^{2} τ}$
$m =$ mean of electron
$n =$ number of change
$e =$ change on electron
$ρ \propto \frac{1}{τ}$
When $τ$ decrease resistivity increase.

TS- EAMCET-03.05.2019

NUCLEAR PHYSICS

1 A-iv, B-iii, C-ii, D-i

2 A-ii, B-i, C-iv, D-iii

3 A-iii, B-ii, C-i, D-iv

4 A-ii, B-iii, C-iv, D-i

Explanation:

D (i) Gravitational force $\to$ Weakest force but has infinite range
(ii) Strong Nuclear force $\to$ Strongest among the forces.
(iii) Weak nuclear force $\to$ Responsible for radioactive decay.
(iv) Electromagnetic force $\to$ Has infinite range and can be both attractive and repulsive in nature.

TS EAMCET 09.05.2019

NUCLEAR PHYSICS

147537 In thermonuclear reaction $3_{1}^{2} H \to_{2}^{4} He +_{1}^{1} H +_{0}^{1} n$ $+ 21.6 MeV$ , the percentage of mass converted during fusion in to energy is nearly:
#[Qdiff: Medium, QCat: Theory Based, examname: Mass of reactants $= 6 AMU$
, $1 AMU = 931 MeV$
, $6 AMU = 6 \times 931 = 5586 MeV$
, Percentage converted
, $= \frac{21.6}{5586} \times 100$
, $= 0.38 %$
, $= 0.4 %$
, 218. Two protons are kept at a separation of $10 nm$ . Let $F_{n}$ and $F_{e}$ the nuclear force and the electromagnetic force between them :
, (a) $F_{e} = F_{n}$
, (b) $F_{e} >> F_{n}$
, (c) $F_{e} << F_{n}$
, (d) $F_{e}$ and $F_{n}$ differ only slightly
, [Karnataka CET-2020,2019]#

1

10 %

2

0.4 %

3

1 %

4

0.01 %

Explanation:

B The given thermonuclear reaction-
$3_{1} H^{2} \to 2 H_{e}^{4} +_{1} H^{1} +_{0} n^{1} + 21.6 MeV$
No of nucleons $= 6$
Ans: b : Two protons exert strong attractive nuclear force and repulsive electrostatic force on each other. Nucleus forces are short range forces existing in the range of a few fermi. Therefore at a separation of $10 nm$ the electromagnetic force is greater than the nuclear force
i.e. $F_{e} >> F_{n}$

NUCLEAR PHYSICS

147534 The ratio $(E / W)$ of relative strength of electromagnetic force (E) to weak nuclear force (W) is

1

10^{- 1}

2

10^{11}

3

10^{20}

4

10^{- 20}

Explanation:

B | Force | Relative strength |
| :--- | :---: |
| Gravitational force | $10^{- 39}$ |
| Weak nuclear force | $10^{- 13}$ |
| Electromagnetic force | $10^{- 2}$ |
| Strong nuclear force | 1 |
$Relative strength = \frac{10^{- 2}}{10^{- 13}} = 10^{11}$

TS EAMCET 04.08.2021

NUCLEAR PHYSICS

147536 The speed of ripples (v) on water surface depends on surface tension $(σ)$ , density $(ρ)$ and wavelength $(λ)$ Then the square of speed $(v)$ is proportional to

1

\frac{σ}{ρ λ}

2

\frac{ρ}{σ λ}

3

\frac{λ}{σ ρ}

4

\sqrt{\frac{ρ λ}{σ}}

Explanation:

A The speed of ripples (v) depends upon $v \propto σ^{a} ρ^{b} λ^{c}$
$[M^{0} {LT}^{- 1}] \propto {[{MT}^{- 2}]}^{a} {[{ML}^{- 3}]}^{b} [L]^{c}$
$[M^{0} {LT}^{- 1}] \propto [M^{a + b}] [L^{- 3 b + c}] [T^{- 2 a}]$
Equating the powers we get-
$a + b = 0$
$- 3 b + c = 1$
$- 2 a = - 1$
Then, $a = \frac{1}{2}, b = \frac{- 1}{2}, c = \frac{- 1}{2}$
So, $v \propto σ^{1 / 2} ρ^{- 1 / 2} λ^{- 1 / 2}$
$= v \propto \sqrt{\frac{σ}{ρ λ}}$
$= v^{2} \propto \frac{σ}{p λ}$

AP EAMCET-19.08.2021

NUCLEAR PHYSICS

147539 Identify the correct statement among the following.

1 Resistivity of metals decreases with temperature because more electrons are available for conduction.

2 Resistivity of metals increases with temperature because number of electrons decreases.

3 Resistivity of metals increases with temperature because number of collisions between electrons increases.

4 Resistivity of metals decreases with temperature because superconductivity sets in.

Explanation:

C When a metal is heated, the atoms is starts to vibrate, this leads to increases in number of collisions amongst the electrons thus time between successive collision or relaxation time $τ$ decreases. Since the resistivity of a metal is given by
When
$ρ = \frac{m}{n e^{2} τ}$
$m =$ mean of electron
$n =$ number of change
$e =$ change on electron
$ρ \propto \frac{1}{τ}$
When $τ$ decrease resistivity increase.

TS- EAMCET-03.05.2019

NUCLEAR PHYSICS

1 A-iv, B-iii, C-ii, D-i

2 A-ii, B-i, C-iv, D-iii

3 A-iii, B-ii, C-i, D-iv

4 A-ii, B-iii, C-iv, D-i

Explanation:

D (i) Gravitational force $\to$ Weakest force but has infinite range
(ii) Strong Nuclear force $\to$ Strongest among the forces.
(iii) Weak nuclear force $\to$ Responsible for radioactive decay.
(iv) Electromagnetic force $\to$ Has infinite range and can be both attractive and repulsive in nature.

TS EAMCET 09.05.2019

NUCLEAR PHYSICS

147537 In thermonuclear reaction $3_{1}^{2} H \to_{2}^{4} He +_{1}^{1} H +_{0}^{1} n$ $+ 21.6 MeV$ , the percentage of mass converted during fusion in to energy is nearly:
#[Qdiff: Medium, QCat: Theory Based, examname: Mass of reactants $= 6 AMU$
, $1 AMU = 931 MeV$
, $6 AMU = 6 \times 931 = 5586 MeV$
, Percentage converted
, $= \frac{21.6}{5586} \times 100$
, $= 0.38 %$
, $= 0.4 %$
, 218. Two protons are kept at a separation of $10 nm$ . Let $F_{n}$ and $F_{e}$ the nuclear force and the electromagnetic force between them :
, (a) $F_{e} = F_{n}$
, (b) $F_{e} >> F_{n}$
, (c) $F_{e} << F_{n}$
, (d) $F_{e}$ and $F_{n}$ differ only slightly
, [Karnataka CET-2020,2019]#

1

10 %

2

0.4 %

3

1 %

4

0.01 %

Explanation:

B The given thermonuclear reaction-
$3_{1} H^{2} \to 2 H_{e}^{4} +_{1} H^{1} +_{0} n^{1} + 21.6 MeV$
No of nucleons $= 6$
Ans: b : Two protons exert strong attractive nuclear force and repulsive electrostatic force on each other. Nucleus forces are short range forces existing in the range of a few fermi. Therefore at a separation of $10 nm$ the electromagnetic force is greater than the nuclear force
i.e. $F_{e} >> F_{n}$