B The given element $-{ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ $Z=$ no. of proton $A=$ mass number of electron $\mathrm{A}-\mathrm{Z}=$ number of neutron The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created. $\mathrm{m} \lt (\mathrm{A}-\mathrm{Z}) \mathrm{m}_{\mathrm{n}}+\mathrm{Z} \mathrm{m}_{\mathrm{P}}$
Karnataka CET-2003
NUCLEAR PHYSICS
147404
A nucleus represented by the $\operatorname{symbol}_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ has
1 $\mathrm{Z}$ neutrons and $(\mathrm{A}-\mathrm{Z})$ protons
2 $\mathrm{Z}$ protons and $(\mathrm{A}-\mathrm{Z})$ neutrons
3 $\mathrm{Z}$ protons and A neutrons
4 A protons and $(\mathrm{Z}-\mathrm{A})$ neutrons
Explanation:
B Mass number $(\mathrm{A})=$ protons + neutrons $\mathrm{Z}=$ Atomic number $=$ number of protons $\mathrm{Z}=$ Protons Number of neutrons $=$ mass number - atomic number $=\mathrm{A}-\mathrm{Z}$ So, ${ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ is represent $\mathrm{Z}$ proton and $\mathrm{A}-\mathrm{Z}$ neutrons
D Isotonic means same number of neutrons. For ${ }_{7} \mathrm{~N}^{13}$ Number of neutrons $=13-7=6$ For ${ }_{6} \mathrm{C}^{12}$ number of neutrons $=12-6=6$ So Isotonic pair ${ }_{7} \mathrm{~N}^{13},{ }_{6} \mathrm{C}^{12}$
MP PMT-2013
NUCLEAR PHYSICS
147416
The radius of ${ }_{72} \mathrm{Te}^{125}$ nucleus is 6 fermi. The radius of ${ }_{13} \mathrm{Al}^{27}$ nucleus in meters is
B The given element $-{ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ $Z=$ no. of proton $A=$ mass number of electron $\mathrm{A}-\mathrm{Z}=$ number of neutron The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created. $\mathrm{m} \lt (\mathrm{A}-\mathrm{Z}) \mathrm{m}_{\mathrm{n}}+\mathrm{Z} \mathrm{m}_{\mathrm{P}}$
Karnataka CET-2003
NUCLEAR PHYSICS
147404
A nucleus represented by the $\operatorname{symbol}_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ has
1 $\mathrm{Z}$ neutrons and $(\mathrm{A}-\mathrm{Z})$ protons
2 $\mathrm{Z}$ protons and $(\mathrm{A}-\mathrm{Z})$ neutrons
3 $\mathrm{Z}$ protons and A neutrons
4 A protons and $(\mathrm{Z}-\mathrm{A})$ neutrons
Explanation:
B Mass number $(\mathrm{A})=$ protons + neutrons $\mathrm{Z}=$ Atomic number $=$ number of protons $\mathrm{Z}=$ Protons Number of neutrons $=$ mass number - atomic number $=\mathrm{A}-\mathrm{Z}$ So, ${ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ is represent $\mathrm{Z}$ proton and $\mathrm{A}-\mathrm{Z}$ neutrons
D Isotonic means same number of neutrons. For ${ }_{7} \mathrm{~N}^{13}$ Number of neutrons $=13-7=6$ For ${ }_{6} \mathrm{C}^{12}$ number of neutrons $=12-6=6$ So Isotonic pair ${ }_{7} \mathrm{~N}^{13},{ }_{6} \mathrm{C}^{12}$
MP PMT-2013
NUCLEAR PHYSICS
147416
The radius of ${ }_{72} \mathrm{Te}^{125}$ nucleus is 6 fermi. The radius of ${ }_{13} \mathrm{Al}^{27}$ nucleus in meters is
B The given element $-{ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ $Z=$ no. of proton $A=$ mass number of electron $\mathrm{A}-\mathrm{Z}=$ number of neutron The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created. $\mathrm{m} \lt (\mathrm{A}-\mathrm{Z}) \mathrm{m}_{\mathrm{n}}+\mathrm{Z} \mathrm{m}_{\mathrm{P}}$
Karnataka CET-2003
NUCLEAR PHYSICS
147404
A nucleus represented by the $\operatorname{symbol}_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ has
1 $\mathrm{Z}$ neutrons and $(\mathrm{A}-\mathrm{Z})$ protons
2 $\mathrm{Z}$ protons and $(\mathrm{A}-\mathrm{Z})$ neutrons
3 $\mathrm{Z}$ protons and A neutrons
4 A protons and $(\mathrm{Z}-\mathrm{A})$ neutrons
Explanation:
B Mass number $(\mathrm{A})=$ protons + neutrons $\mathrm{Z}=$ Atomic number $=$ number of protons $\mathrm{Z}=$ Protons Number of neutrons $=$ mass number - atomic number $=\mathrm{A}-\mathrm{Z}$ So, ${ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ is represent $\mathrm{Z}$ proton and $\mathrm{A}-\mathrm{Z}$ neutrons
D Isotonic means same number of neutrons. For ${ }_{7} \mathrm{~N}^{13}$ Number of neutrons $=13-7=6$ For ${ }_{6} \mathrm{C}^{12}$ number of neutrons $=12-6=6$ So Isotonic pair ${ }_{7} \mathrm{~N}^{13},{ }_{6} \mathrm{C}^{12}$
MP PMT-2013
NUCLEAR PHYSICS
147416
The radius of ${ }_{72} \mathrm{Te}^{125}$ nucleus is 6 fermi. The radius of ${ }_{13} \mathrm{Al}^{27}$ nucleus in meters is
B The given element $-{ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ $Z=$ no. of proton $A=$ mass number of electron $\mathrm{A}-\mathrm{Z}=$ number of neutron The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created. $\mathrm{m} \lt (\mathrm{A}-\mathrm{Z}) \mathrm{m}_{\mathrm{n}}+\mathrm{Z} \mathrm{m}_{\mathrm{P}}$
Karnataka CET-2003
NUCLEAR PHYSICS
147404
A nucleus represented by the $\operatorname{symbol}_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ has
1 $\mathrm{Z}$ neutrons and $(\mathrm{A}-\mathrm{Z})$ protons
2 $\mathrm{Z}$ protons and $(\mathrm{A}-\mathrm{Z})$ neutrons
3 $\mathrm{Z}$ protons and A neutrons
4 A protons and $(\mathrm{Z}-\mathrm{A})$ neutrons
Explanation:
B Mass number $(\mathrm{A})=$ protons + neutrons $\mathrm{Z}=$ Atomic number $=$ number of protons $\mathrm{Z}=$ Protons Number of neutrons $=$ mass number - atomic number $=\mathrm{A}-\mathrm{Z}$ So, ${ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ is represent $\mathrm{Z}$ proton and $\mathrm{A}-\mathrm{Z}$ neutrons
D Isotonic means same number of neutrons. For ${ }_{7} \mathrm{~N}^{13}$ Number of neutrons $=13-7=6$ For ${ }_{6} \mathrm{C}^{12}$ number of neutrons $=12-6=6$ So Isotonic pair ${ }_{7} \mathrm{~N}^{13},{ }_{6} \mathrm{C}^{12}$
MP PMT-2013
NUCLEAR PHYSICS
147416
The radius of ${ }_{72} \mathrm{Te}^{125}$ nucleus is 6 fermi. The radius of ${ }_{13} \mathrm{Al}^{27}$ nucleus in meters is
B The given element $-{ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ $Z=$ no. of proton $A=$ mass number of electron $\mathrm{A}-\mathrm{Z}=$ number of neutron The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created. $\mathrm{m} \lt (\mathrm{A}-\mathrm{Z}) \mathrm{m}_{\mathrm{n}}+\mathrm{Z} \mathrm{m}_{\mathrm{P}}$
Karnataka CET-2003
NUCLEAR PHYSICS
147404
A nucleus represented by the $\operatorname{symbol}_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ has
1 $\mathrm{Z}$ neutrons and $(\mathrm{A}-\mathrm{Z})$ protons
2 $\mathrm{Z}$ protons and $(\mathrm{A}-\mathrm{Z})$ neutrons
3 $\mathrm{Z}$ protons and A neutrons
4 A protons and $(\mathrm{Z}-\mathrm{A})$ neutrons
Explanation:
B Mass number $(\mathrm{A})=$ protons + neutrons $\mathrm{Z}=$ Atomic number $=$ number of protons $\mathrm{Z}=$ Protons Number of neutrons $=$ mass number - atomic number $=\mathrm{A}-\mathrm{Z}$ So, ${ }_{\mathrm{Z}} \mathrm{X}^{\mathrm{A}}$ is represent $\mathrm{Z}$ proton and $\mathrm{A}-\mathrm{Z}$ neutrons
D Isotonic means same number of neutrons. For ${ }_{7} \mathrm{~N}^{13}$ Number of neutrons $=13-7=6$ For ${ }_{6} \mathrm{C}^{12}$ number of neutrons $=12-6=6$ So Isotonic pair ${ }_{7} \mathrm{~N}^{13},{ }_{6} \mathrm{C}^{12}$
MP PMT-2013
NUCLEAR PHYSICS
147416
The radius of ${ }_{72} \mathrm{Te}^{125}$ nucleus is 6 fermi. The radius of ${ }_{13} \mathrm{Al}^{27}$ nucleus in meters is