147400
Nucleus $A$ is converted into $C$ through the following reactions : $\mathbf{A} \rightarrow \mathbf{B}+\alpha\alpha \text {-particle }$ $\mathbf{B} \rightarrow \mathbf{C}+2 \beta\beta \text {-electron }$ Then
1 A and B are isotopes
2 $\mathrm{A}$ and $\mathrm{C}$ are isobars
3 A and B are isobars
4 A and $\mathrm{C}$ are isotopes
Explanation:
D ${ }_{\mathrm{Z}} \mathrm{A}^{\mathrm{x}} \stackrel{-\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{~B}^{\mathrm{x}-4} \stackrel{-2 \beta}{\longrightarrow}{ }_{\mathrm{Z}} \mathrm{C}^{\mathrm{x}-4}$ From this $\mathrm{A}$ and $\mathrm{C}$ are isotopes.
Karnataka CET-2003
NUCLEAR PHYSICS
147405
The nuclear radius varies with the mass number $A$ as
1 $\mathrm{A}$
2 $\mathrm{A}^{1 / 3}$
3 $\mathrm{A}^{3}$
4 $\mathrm{A}^{2}$
Explanation:
B We know that, $\mathrm{R}=\mathrm{R}_{0}(\mathrm{~A})^{1 / 3}$ Thus, $\quad \mathrm{R} \propto \mathrm{A}^{1 / 3}$
UPSEE - 2004
NUCLEAR PHYSICS
147406
Domain formation is the necessary feature of
1 diamagnetic substances
2 paramagnetic substances
3 ferromagnetic substances
4 all of these
Explanation:
C Iron, Cobalt, nickel and its alloys are ferromagnetic substance which possess domain structure but this domain randomly oriented normal situation.
J and K CET- 2003
NUCLEAR PHYSICS
147410
As compared to ${ }^{12} \mathrm{C}$ atom has:
1 Two extra protons and two extra electrons
2 Two extra protons but no extra electron
3 Two extra neutrons but no extra electron
4 Two extra neutrons and two extra electrons
Explanation:
C ${ }^{12} \mathrm{C}$ and ${ }^{14} \mathrm{C}$ are two Isotopes of carbon atom that have same atomic number but different mass numbers. This means that they have same number of protons and electrons but different number of neutrons therefore ${ }^{12} \mathrm{C}$ has 6 protons 6 electrons and 6 neutrons where as ${ }^{14} \mathrm{C}$ has 6 electrons, 6 protons, and 8 neutrons.
147400
Nucleus $A$ is converted into $C$ through the following reactions : $\mathbf{A} \rightarrow \mathbf{B}+\alpha\alpha \text {-particle }$ $\mathbf{B} \rightarrow \mathbf{C}+2 \beta\beta \text {-electron }$ Then
1 A and B are isotopes
2 $\mathrm{A}$ and $\mathrm{C}$ are isobars
3 A and B are isobars
4 A and $\mathrm{C}$ are isotopes
Explanation:
D ${ }_{\mathrm{Z}} \mathrm{A}^{\mathrm{x}} \stackrel{-\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{~B}^{\mathrm{x}-4} \stackrel{-2 \beta}{\longrightarrow}{ }_{\mathrm{Z}} \mathrm{C}^{\mathrm{x}-4}$ From this $\mathrm{A}$ and $\mathrm{C}$ are isotopes.
Karnataka CET-2003
NUCLEAR PHYSICS
147405
The nuclear radius varies with the mass number $A$ as
1 $\mathrm{A}$
2 $\mathrm{A}^{1 / 3}$
3 $\mathrm{A}^{3}$
4 $\mathrm{A}^{2}$
Explanation:
B We know that, $\mathrm{R}=\mathrm{R}_{0}(\mathrm{~A})^{1 / 3}$ Thus, $\quad \mathrm{R} \propto \mathrm{A}^{1 / 3}$
UPSEE - 2004
NUCLEAR PHYSICS
147406
Domain formation is the necessary feature of
1 diamagnetic substances
2 paramagnetic substances
3 ferromagnetic substances
4 all of these
Explanation:
C Iron, Cobalt, nickel and its alloys are ferromagnetic substance which possess domain structure but this domain randomly oriented normal situation.
J and K CET- 2003
NUCLEAR PHYSICS
147410
As compared to ${ }^{12} \mathrm{C}$ atom has:
1 Two extra protons and two extra electrons
2 Two extra protons but no extra electron
3 Two extra neutrons but no extra electron
4 Two extra neutrons and two extra electrons
Explanation:
C ${ }^{12} \mathrm{C}$ and ${ }^{14} \mathrm{C}$ are two Isotopes of carbon atom that have same atomic number but different mass numbers. This means that they have same number of protons and electrons but different number of neutrons therefore ${ }^{12} \mathrm{C}$ has 6 protons 6 electrons and 6 neutrons where as ${ }^{14} \mathrm{C}$ has 6 electrons, 6 protons, and 8 neutrons.
147400
Nucleus $A$ is converted into $C$ through the following reactions : $\mathbf{A} \rightarrow \mathbf{B}+\alpha\alpha \text {-particle }$ $\mathbf{B} \rightarrow \mathbf{C}+2 \beta\beta \text {-electron }$ Then
1 A and B are isotopes
2 $\mathrm{A}$ and $\mathrm{C}$ are isobars
3 A and B are isobars
4 A and $\mathrm{C}$ are isotopes
Explanation:
D ${ }_{\mathrm{Z}} \mathrm{A}^{\mathrm{x}} \stackrel{-\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{~B}^{\mathrm{x}-4} \stackrel{-2 \beta}{\longrightarrow}{ }_{\mathrm{Z}} \mathrm{C}^{\mathrm{x}-4}$ From this $\mathrm{A}$ and $\mathrm{C}$ are isotopes.
Karnataka CET-2003
NUCLEAR PHYSICS
147405
The nuclear radius varies with the mass number $A$ as
1 $\mathrm{A}$
2 $\mathrm{A}^{1 / 3}$
3 $\mathrm{A}^{3}$
4 $\mathrm{A}^{2}$
Explanation:
B We know that, $\mathrm{R}=\mathrm{R}_{0}(\mathrm{~A})^{1 / 3}$ Thus, $\quad \mathrm{R} \propto \mathrm{A}^{1 / 3}$
UPSEE - 2004
NUCLEAR PHYSICS
147406
Domain formation is the necessary feature of
1 diamagnetic substances
2 paramagnetic substances
3 ferromagnetic substances
4 all of these
Explanation:
C Iron, Cobalt, nickel and its alloys are ferromagnetic substance which possess domain structure but this domain randomly oriented normal situation.
J and K CET- 2003
NUCLEAR PHYSICS
147410
As compared to ${ }^{12} \mathrm{C}$ atom has:
1 Two extra protons and two extra electrons
2 Two extra protons but no extra electron
3 Two extra neutrons but no extra electron
4 Two extra neutrons and two extra electrons
Explanation:
C ${ }^{12} \mathrm{C}$ and ${ }^{14} \mathrm{C}$ are two Isotopes of carbon atom that have same atomic number but different mass numbers. This means that they have same number of protons and electrons but different number of neutrons therefore ${ }^{12} \mathrm{C}$ has 6 protons 6 electrons and 6 neutrons where as ${ }^{14} \mathrm{C}$ has 6 electrons, 6 protons, and 8 neutrons.
147400
Nucleus $A$ is converted into $C$ through the following reactions : $\mathbf{A} \rightarrow \mathbf{B}+\alpha\alpha \text {-particle }$ $\mathbf{B} \rightarrow \mathbf{C}+2 \beta\beta \text {-electron }$ Then
1 A and B are isotopes
2 $\mathrm{A}$ and $\mathrm{C}$ are isobars
3 A and B are isobars
4 A and $\mathrm{C}$ are isotopes
Explanation:
D ${ }_{\mathrm{Z}} \mathrm{A}^{\mathrm{x}} \stackrel{-\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{~B}^{\mathrm{x}-4} \stackrel{-2 \beta}{\longrightarrow}{ }_{\mathrm{Z}} \mathrm{C}^{\mathrm{x}-4}$ From this $\mathrm{A}$ and $\mathrm{C}$ are isotopes.
Karnataka CET-2003
NUCLEAR PHYSICS
147405
The nuclear radius varies with the mass number $A$ as
1 $\mathrm{A}$
2 $\mathrm{A}^{1 / 3}$
3 $\mathrm{A}^{3}$
4 $\mathrm{A}^{2}$
Explanation:
B We know that, $\mathrm{R}=\mathrm{R}_{0}(\mathrm{~A})^{1 / 3}$ Thus, $\quad \mathrm{R} \propto \mathrm{A}^{1 / 3}$
UPSEE - 2004
NUCLEAR PHYSICS
147406
Domain formation is the necessary feature of
1 diamagnetic substances
2 paramagnetic substances
3 ferromagnetic substances
4 all of these
Explanation:
C Iron, Cobalt, nickel and its alloys are ferromagnetic substance which possess domain structure but this domain randomly oriented normal situation.
J and K CET- 2003
NUCLEAR PHYSICS
147410
As compared to ${ }^{12} \mathrm{C}$ atom has:
1 Two extra protons and two extra electrons
2 Two extra protons but no extra electron
3 Two extra neutrons but no extra electron
4 Two extra neutrons and two extra electrons
Explanation:
C ${ }^{12} \mathrm{C}$ and ${ }^{14} \mathrm{C}$ are two Isotopes of carbon atom that have same atomic number but different mass numbers. This means that they have same number of protons and electrons but different number of neutrons therefore ${ }^{12} \mathrm{C}$ has 6 protons 6 electrons and 6 neutrons where as ${ }^{14} \mathrm{C}$ has 6 electrons, 6 protons, and 8 neutrons.
