QBManager

NUCLEAR PHYSICS

147401 If $m, m_{n}$ and $m_{p}$ are the masses of $_{z} X^{A}$ nucleus, neutron and proton respectively :

1

m = (A - Z) m_{n} + Z m_{p}

2

m < (A - Z) m_{n} + Z m_{p}

3

m > (A - Z) m_{n} + Z m_{p}

4

M = (A - Z) m_{p} + Z m_{n}

Explanation:

B The given element $-_{Z} X^{A}$
$Z =$ no. of proton
$A =$ mass number of electron
$A - Z =$ number of neutron
The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created.
$m < (A - Z) m_{n} + Z m_{P}$

Karnataka CET-2003

NUCLEAR PHYSICS

147404 A nucleus represented by the ${symbol}_{Z} X^{A}$ has

1

Z

neutrons and

(A - Z)

protons

2

Z

protons and

(A - Z)

neutrons

3

Z

protons and A neutrons

4 A protons and

(Z - A)

neutrons

Explanation:

B Mass number $(A) =$ protons + neutrons
$Z =$ Atomic number $=$ number of protons $Z =$ Protons
Number of neutrons $=$ mass number - atomic number
$= A - Z$
So, $_{Z} X^{A}$ is represent $Z$ proton and $A - Z$ neutrons

J and K CET- 2001

NUCLEAR PHYSICS

147409 Which pair is isotonic ?

1

_{7} N^{13},_{7} N^{14}

2

_{6} C^{14},_{6} C^{12}

3

_{6} C^{14},_{7} N^{14}

4

_{7} N^{13},_{6} C^{12}

Explanation:

D Isotonic means same number of neutrons. For $_{7} N^{13}$
Number of neutrons $= 13 - 7 = 6$
For $_{6} C^{12}$ number of neutrons $= 12 - 6 = 6$ So Isotonic pair $_{7} N^{13},_{6} C^{12}$

MP PMT-2013

NUCLEAR PHYSICS

147416 The radius of $_{72} {Te}^{125}$ nucleus is 6 fermi. The radius of $_{13} {Al}^{27}$ nucleus in meters is

1

3.6 \times 10^{- 12} m

2

3.6 \times 10^{- 15} m

3

7.2 \times 10^{- 8} m

4

7.2 \times 10^{- 15} m

Explanation:

B Given that,
$R_{Te} = 6 fermi A_{Al} = 27, A_{Te} = 125$
$\frac{R_{Al}}{R_{Te}} = {(\frac{A_{Al}}{A_{Te}})}^{\frac{1}{3}}$
$R_{Al} = {(\frac{27}{125})}^{\frac{1}{3}} \times 6 \times 10^{- 15} m$
$R_{Al} = 3.6 \times 10^{- 15} m$

AP EAMCET -2013

NUCLEAR PHYSICS

147417 If the radius of a nucleus with mass number 125 is 1.5 fermi, then radius of a nucleus with mass number 64 is

1 0.48 fermi

2 0.96 fermi

3 1.92 fermi

4 1.2 fermi

Explanation:

D Given, $A_{1} = 125, A_{2} = 64,$
$R_{1} = 1.5 fermi R_{2} = ?$
$\frac{R_{1}}{R_{2}} = {(\frac{A_{1}}{A_{2}})}^{\frac{1}{3}}$
$\frac{1.5}{R_{2}} = {(\frac{125}{64})}^{\frac{1}{3}} = \frac{5}{4}$
$R_{2} = \frac{1.5 \times 4}{5} = 1.2 fermi$

AP EAMCET -2014

NUCLEAR PHYSICS

147401 If $m, m_{n}$ and $m_{p}$ are the masses of $_{z} X^{A}$ nucleus, neutron and proton respectively :

1

m = (A - Z) m_{n} + Z m_{p}

2

m < (A - Z) m_{n} + Z m_{p}

3

m > (A - Z) m_{n} + Z m_{p}

4

M = (A - Z) m_{p} + Z m_{n}

Explanation:

B The given element $-_{Z} X^{A}$
$Z =$ no. of proton
$A =$ mass number of electron
$A - Z =$ number of neutron
The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created.
$m < (A - Z) m_{n} + Z m_{P}$

Karnataka CET-2003

NUCLEAR PHYSICS

147404 A nucleus represented by the ${symbol}_{Z} X^{A}$ has

1

Z

neutrons and

(A - Z)

protons

2

Z

protons and

(A - Z)

neutrons

3

Z

protons and A neutrons

4 A protons and

(Z - A)

neutrons

Explanation:

B Mass number $(A) =$ protons + neutrons
$Z =$ Atomic number $=$ number of protons $Z =$ Protons
Number of neutrons $=$ mass number - atomic number
$= A - Z$
So, $_{Z} X^{A}$ is represent $Z$ proton and $A - Z$ neutrons

J and K CET- 2001

NUCLEAR PHYSICS

147409 Which pair is isotonic ?

1

_{7} N^{13},_{7} N^{14}

2

_{6} C^{14},_{6} C^{12}

3

_{6} C^{14},_{7} N^{14}

4

_{7} N^{13},_{6} C^{12}

Explanation:

D Isotonic means same number of neutrons. For $_{7} N^{13}$
Number of neutrons $= 13 - 7 = 6$
For $_{6} C^{12}$ number of neutrons $= 12 - 6 = 6$ So Isotonic pair $_{7} N^{13},_{6} C^{12}$

MP PMT-2013

NUCLEAR PHYSICS

147416 The radius of $_{72} {Te}^{125}$ nucleus is 6 fermi. The radius of $_{13} {Al}^{27}$ nucleus in meters is

1

3.6 \times 10^{- 12} m

2

3.6 \times 10^{- 15} m

3

7.2 \times 10^{- 8} m

4

7.2 \times 10^{- 15} m

Explanation:

B Given that,
$R_{Te} = 6 fermi A_{Al} = 27, A_{Te} = 125$
$\frac{R_{Al}}{R_{Te}} = {(\frac{A_{Al}}{A_{Te}})}^{\frac{1}{3}}$
$R_{Al} = {(\frac{27}{125})}^{\frac{1}{3}} \times 6 \times 10^{- 15} m$
$R_{Al} = 3.6 \times 10^{- 15} m$

AP EAMCET -2013

NUCLEAR PHYSICS

147417 If the radius of a nucleus with mass number 125 is 1.5 fermi, then radius of a nucleus with mass number 64 is

1 0.48 fermi

2 0.96 fermi

3 1.92 fermi

4 1.2 fermi

Explanation:

D Given, $A_{1} = 125, A_{2} = 64,$
$R_{1} = 1.5 fermi R_{2} = ?$
$\frac{R_{1}}{R_{2}} = {(\frac{A_{1}}{A_{2}})}^{\frac{1}{3}}$
$\frac{1.5}{R_{2}} = {(\frac{125}{64})}^{\frac{1}{3}} = \frac{5}{4}$
$R_{2} = \frac{1.5 \times 4}{5} = 1.2 fermi$

AP EAMCET -2014

NUCLEAR PHYSICS

147401 If $m, m_{n}$ and $m_{p}$ are the masses of $_{z} X^{A}$ nucleus, neutron and proton respectively :

1

m = (A - Z) m_{n} + Z m_{p}

2

m < (A - Z) m_{n} + Z m_{p}

3

m > (A - Z) m_{n} + Z m_{p}

4

M = (A - Z) m_{p} + Z m_{n}

Explanation:

B The given element $-_{Z} X^{A}$
$Z =$ no. of proton
$A =$ mass number of electron
$A - Z =$ number of neutron
The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created.
$m < (A - Z) m_{n} + Z m_{P}$

Karnataka CET-2003

NUCLEAR PHYSICS

147404 A nucleus represented by the ${symbol}_{Z} X^{A}$ has

1

Z

neutrons and

(A - Z)

protons

2

Z

protons and

(A - Z)

neutrons

3

Z

protons and A neutrons

4 A protons and

(Z - A)

neutrons

Explanation:

B Mass number $(A) =$ protons + neutrons
$Z =$ Atomic number $=$ number of protons $Z =$ Protons
Number of neutrons $=$ mass number - atomic number
$= A - Z$
So, $_{Z} X^{A}$ is represent $Z$ proton and $A - Z$ neutrons

J and K CET- 2001

NUCLEAR PHYSICS

147409 Which pair is isotonic ?

1

_{7} N^{13},_{7} N^{14}

2

_{6} C^{14},_{6} C^{12}

3

_{6} C^{14},_{7} N^{14}

4

_{7} N^{13},_{6} C^{12}

Explanation:

D Isotonic means same number of neutrons. For $_{7} N^{13}$
Number of neutrons $= 13 - 7 = 6$
For $_{6} C^{12}$ number of neutrons $= 12 - 6 = 6$ So Isotonic pair $_{7} N^{13},_{6} C^{12}$

MP PMT-2013

NUCLEAR PHYSICS

147416 The radius of $_{72} {Te}^{125}$ nucleus is 6 fermi. The radius of $_{13} {Al}^{27}$ nucleus in meters is

1

3.6 \times 10^{- 12} m

2

3.6 \times 10^{- 15} m

3

7.2 \times 10^{- 8} m

4

7.2 \times 10^{- 15} m

Explanation:

B Given that,
$R_{Te} = 6 fermi A_{Al} = 27, A_{Te} = 125$
$\frac{R_{Al}}{R_{Te}} = {(\frac{A_{Al}}{A_{Te}})}^{\frac{1}{3}}$
$R_{Al} = {(\frac{27}{125})}^{\frac{1}{3}} \times 6 \times 10^{- 15} m$
$R_{Al} = 3.6 \times 10^{- 15} m$

AP EAMCET -2013

NUCLEAR PHYSICS

147417 If the radius of a nucleus with mass number 125 is 1.5 fermi, then radius of a nucleus with mass number 64 is

1 0.48 fermi

2 0.96 fermi

3 1.92 fermi

4 1.2 fermi

Explanation:

D Given, $A_{1} = 125, A_{2} = 64,$
$R_{1} = 1.5 fermi R_{2} = ?$
$\frac{R_{1}}{R_{2}} = {(\frac{A_{1}}{A_{2}})}^{\frac{1}{3}}$
$\frac{1.5}{R_{2}} = {(\frac{125}{64})}^{\frac{1}{3}} = \frac{5}{4}$
$R_{2} = \frac{1.5 \times 4}{5} = 1.2 fermi$

AP EAMCET -2014

NUCLEAR PHYSICS

147401 If $m, m_{n}$ and $m_{p}$ are the masses of $_{z} X^{A}$ nucleus, neutron and proton respectively :

1

m = (A - Z) m_{n} + Z m_{p}

2

m < (A - Z) m_{n} + Z m_{p}

3

m > (A - Z) m_{n} + Z m_{p}

4

M = (A - Z) m_{p} + Z m_{n}

Explanation:

B The given element $-_{Z} X^{A}$
$Z =$ no. of proton
$A =$ mass number of electron
$A - Z =$ number of neutron
The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created.
$m < (A - Z) m_{n} + Z m_{P}$

Karnataka CET-2003

NUCLEAR PHYSICS

147404 A nucleus represented by the ${symbol}_{Z} X^{A}$ has

1

Z

neutrons and

(A - Z)

protons

2

Z

protons and

(A - Z)

neutrons

3

Z

protons and A neutrons

4 A protons and

(Z - A)

neutrons

Explanation:

B Mass number $(A) =$ protons + neutrons
$Z =$ Atomic number $=$ number of protons $Z =$ Protons
Number of neutrons $=$ mass number - atomic number
$= A - Z$
So, $_{Z} X^{A}$ is represent $Z$ proton and $A - Z$ neutrons

J and K CET- 2001

NUCLEAR PHYSICS

147409 Which pair is isotonic ?

1

_{7} N^{13},_{7} N^{14}

2

_{6} C^{14},_{6} C^{12}

3

_{6} C^{14},_{7} N^{14}

4

_{7} N^{13},_{6} C^{12}

Explanation:

D Isotonic means same number of neutrons. For $_{7} N^{13}$
Number of neutrons $= 13 - 7 = 6$
For $_{6} C^{12}$ number of neutrons $= 12 - 6 = 6$ So Isotonic pair $_{7} N^{13},_{6} C^{12}$

MP PMT-2013

NUCLEAR PHYSICS

147416 The radius of $_{72} {Te}^{125}$ nucleus is 6 fermi. The radius of $_{13} {Al}^{27}$ nucleus in meters is

1

3.6 \times 10^{- 12} m

2

3.6 \times 10^{- 15} m

3

7.2 \times 10^{- 8} m

4

7.2 \times 10^{- 15} m

Explanation:

B Given that,
$R_{Te} = 6 fermi A_{Al} = 27, A_{Te} = 125$
$\frac{R_{Al}}{R_{Te}} = {(\frac{A_{Al}}{A_{Te}})}^{\frac{1}{3}}$
$R_{Al} = {(\frac{27}{125})}^{\frac{1}{3}} \times 6 \times 10^{- 15} m$
$R_{Al} = 3.6 \times 10^{- 15} m$

AP EAMCET -2013

NUCLEAR PHYSICS

147417 If the radius of a nucleus with mass number 125 is 1.5 fermi, then radius of a nucleus with mass number 64 is

1 0.48 fermi

2 0.96 fermi

3 1.92 fermi

4 1.2 fermi

Explanation:

D Given, $A_{1} = 125, A_{2} = 64,$
$R_{1} = 1.5 fermi R_{2} = ?$
$\frac{R_{1}}{R_{2}} = {(\frac{A_{1}}{A_{2}})}^{\frac{1}{3}}$
$\frac{1.5}{R_{2}} = {(\frac{125}{64})}^{\frac{1}{3}} = \frac{5}{4}$
$R_{2} = \frac{1.5 \times 4}{5} = 1.2 fermi$

AP EAMCET -2014

NUCLEAR PHYSICS

147401 If $m, m_{n}$ and $m_{p}$ are the masses of $_{z} X^{A}$ nucleus, neutron and proton respectively :

1

m = (A - Z) m_{n} + Z m_{p}

2

m < (A - Z) m_{n} + Z m_{p}

3

m > (A - Z) m_{n} + Z m_{p}

4

M = (A - Z) m_{p} + Z m_{n}

Explanation:

B The given element $-_{Z} X^{A}$
$Z =$ no. of proton
$A =$ mass number of electron
$A - Z =$ number of neutron
The actual mass of the nucleus is less than the sum of individual masses of the constituent neutrons and protons because energy is ejected when the nucleus is created.
$m < (A - Z) m_{n} + Z m_{P}$

Karnataka CET-2003

NUCLEAR PHYSICS

147404 A nucleus represented by the ${symbol}_{Z} X^{A}$ has

1

Z

neutrons and

(A - Z)

protons

2

Z

protons and

(A - Z)

neutrons

3

Z

protons and A neutrons

4 A protons and

(Z - A)

neutrons

Explanation:

B Mass number $(A) =$ protons + neutrons
$Z =$ Atomic number $=$ number of protons $Z =$ Protons
Number of neutrons $=$ mass number - atomic number
$= A - Z$
So, $_{Z} X^{A}$ is represent $Z$ proton and $A - Z$ neutrons

J and K CET- 2001

NUCLEAR PHYSICS

147409 Which pair is isotonic ?

1

_{7} N^{13},_{7} N^{14}

2

_{6} C^{14},_{6} C^{12}

3

_{6} C^{14},_{7} N^{14}

4

_{7} N^{13},_{6} C^{12}

Explanation:

D Isotonic means same number of neutrons. For $_{7} N^{13}$
Number of neutrons $= 13 - 7 = 6$
For $_{6} C^{12}$ number of neutrons $= 12 - 6 = 6$ So Isotonic pair $_{7} N^{13},_{6} C^{12}$

MP PMT-2013

NUCLEAR PHYSICS

147416 The radius of $_{72} {Te}^{125}$ nucleus is 6 fermi. The radius of $_{13} {Al}^{27}$ nucleus in meters is

1

3.6 \times 10^{- 12} m

2

3.6 \times 10^{- 15} m

3

7.2 \times 10^{- 8} m

4

7.2 \times 10^{- 15} m

Explanation:

B Given that,
$R_{Te} = 6 fermi A_{Al} = 27, A_{Te} = 125$
$\frac{R_{Al}}{R_{Te}} = {(\frac{A_{Al}}{A_{Te}})}^{\frac{1}{3}}$
$R_{Al} = {(\frac{27}{125})}^{\frac{1}{3}} \times 6 \times 10^{- 15} m$
$R_{Al} = 3.6 \times 10^{- 15} m$

AP EAMCET -2013

NUCLEAR PHYSICS

147417 If the radius of a nucleus with mass number 125 is 1.5 fermi, then radius of a nucleus with mass number 64 is

1 0.48 fermi

2 0.96 fermi

3 1.92 fermi

4 1.2 fermi

Explanation:

D Given, $A_{1} = 125, A_{2} = 64,$
$R_{1} = 1.5 fermi R_{2} = ?$
$\frac{R_{1}}{R_{2}} = {(\frac{A_{1}}{A_{2}})}^{\frac{1}{3}}$
$\frac{1.5}{R_{2}} = {(\frac{125}{64})}^{\frac{1}{3}} = \frac{5}{4}$
$R_{2} = \frac{1.5 \times 4}{5} = 1.2 fermi$

AP EAMCET -2014

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