142447 An electron on charge e and mass $m$ moving with an initial velocity $v_{0} \hat{i}$ is subjected to all electric field $E_{0} \hat{j}$. The de-Broglie wavelength of the electron at a time $t$ is (Initial de-Broglie wavelength of the electron = $\left.\lambda_{0}\right)$

142448 An electron of mass $m$ with a velocity $v=$ $v_{0} \hat{i}\left(v_{0}>0\right)$ enters an electric field $E=-E_{0} \hat{i}\left(E_{0}\right.$ constant $>0$ ) at $t=0$. If $\lambda_{0}$ its de-Broglie wavelength initially, then its de-Broglie wavelength at time is

142450 An electron accelerated through a potential of $10000 \mathrm{~V}$ from rest has a de-Broglie wave length ' $\lambda$ '. What should be the accelerating potential, so that the wavelength is doubled?

142451 If an electron and a proton have the same deBroglie wavelength, then the kinetic energy of the electron is :

142447 An electron on charge e and mass $m$ moving with an initial velocity $v_{0} \hat{i}$ is subjected to all electric field $E_{0} \hat{j}$. The de-Broglie wavelength of the electron at a time $t$ is (Initial de-Broglie wavelength of the electron = $\left.\lambda_{0}\right)$

142448 An electron of mass $m$ with a velocity $v=$ $v_{0} \hat{i}\left(v_{0}>0\right)$ enters an electric field $E=-E_{0} \hat{i}\left(E_{0}\right.$ constant $>0$ ) at $t=0$. If $\lambda_{0}$ its de-Broglie wavelength initially, then its de-Broglie wavelength at time is

142450 An electron accelerated through a potential of $10000 \mathrm{~V}$ from rest has a de-Broglie wave length ' $\lambda$ '. What should be the accelerating potential, so that the wavelength is doubled?

142451 If an electron and a proton have the same deBroglie wavelength, then the kinetic energy of the electron is :

142447 An electron on charge e and mass $m$ moving with an initial velocity $v_{0} \hat{i}$ is subjected to all electric field $E_{0} \hat{j}$. The de-Broglie wavelength of the electron at a time $t$ is (Initial de-Broglie wavelength of the electron = $\left.\lambda_{0}\right)$

142448 An electron of mass $m$ with a velocity $v=$ $v_{0} \hat{i}\left(v_{0}>0\right)$ enters an electric field $E=-E_{0} \hat{i}\left(E_{0}\right.$ constant $>0$ ) at $t=0$. If $\lambda_{0}$ its de-Broglie wavelength initially, then its de-Broglie wavelength at time is

142450 An electron accelerated through a potential of $10000 \mathrm{~V}$ from rest has a de-Broglie wave length ' $\lambda$ '. What should be the accelerating potential, so that the wavelength is doubled?

142451 If an electron and a proton have the same deBroglie wavelength, then the kinetic energy of the electron is :

142447 An electron on charge e and mass $m$ moving with an initial velocity $v_{0} \hat{i}$ is subjected to all electric field $E_{0} \hat{j}$. The de-Broglie wavelength of the electron at a time $t$ is (Initial de-Broglie wavelength of the electron = $\left.\lambda_{0}\right)$

142448 An electron of mass $m$ with a velocity $v=$ $v_{0} \hat{i}\left(v_{0}>0\right)$ enters an electric field $E=-E_{0} \hat{i}\left(E_{0}\right.$ constant $>0$ ) at $t=0$. If $\lambda_{0}$ its de-Broglie wavelength initially, then its de-Broglie wavelength at time is

142450 An electron accelerated through a potential of $10000 \mathrm{~V}$ from rest has a de-Broglie wave length ' $\lambda$ '. What should be the accelerating potential, so that the wavelength is doubled?

142451 If an electron and a proton have the same deBroglie wavelength, then the kinetic energy of the electron is :